Sql server 从出生/死亡表计算人口表

我有一个表格，下面是一个例子，列出了人们及其出生和死亡年份（9999表示一个活着的人）

我想计算这些年的人口。对于上面显示的示例，输出如下所示。行末尾的生还者列表仅用于演示目的，我的输出中不需要它

year | population
2001 | 1                  (1)
2002 | 3                  (1,2,3)
2003 | 2                  (1,3)
2004 | 3                  (1,3,4)
2005 | 4                  (1,3,4,5)
2006 | 4                  (1,3,4,5)
2007 | 4                  (1,3,4,5)
2008 | 3                  (1,4,5)
2009 | 2                  (1,5)
2010 | 3                  (1,5,6)
2011 | 3                  (1,5,6)
2012 | 2                  (1,5)

我可以写一个C#程序，循环原始表中的每一行，增加出生和死亡年份之间的每一年的人口数。但是，我需要完全在TSQL脚本中完成。我是TSQL新手。我该怎么做呢？如果已经讨论过类似的问题，请告诉我。多谢各位

DECLARE @t TABLE(person INT, born INT, died INT);

INSERT @t VALUES
(1,2001,9999),
(2,2002,2003),
(3,2002,2008),
(4,2004,2009),
(5,2005,9999),
(6,2010,2012);

DECLARE @start INT, @end INT;

SELECT @start = 2001, @end = 2012;

;WITH n(y) AS 
(
  SELECT TOP (@end - @start + 1) 
    @start - 1 + ROW_NUMBER() OVER (ORDER BY [object_id])
  FROM sys.all_objects
)
SELECT 
  [year] = n.y, 
  population = SUM(CASE WHEN n.y >= t.born AND n.y < t.died THEN 1 ELSE 0 END) 
FROM n CROSS JOIN @t AS t GROUP BY n.y;

FWIW我刚刚开始了一系列关于这件事的博客：

---

什么版本的sql server？@Vijay嗯，我不知道。但我遇到过这种模式，知道有一个简单的解决方案。：-）

DECLARE @t TABLE(person INT, born INT, died INT);

INSERT @t VALUES
(1,2001,9999),
(2,2002,2003),
(3,2002,2008),
(4,2004,2009),
(5,2005,9999),
(6,2010,2012);

DECLARE @start INT, @end INT;

SELECT @start = 2001, @end = 2012;

;WITH n(y) AS 
(
  SELECT TOP (@end - @start + 1) 
    @start - 1 + ROW_NUMBER() OVER (ORDER BY [object_id])
  FROM sys.all_objects
)
SELECT 
  [year] = n.y, 
  population = SUM(CASE WHEN n.y >= t.born AND n.y < t.died THEN 1 ELSE 0 END) 
FROM n CROSS JOIN @t AS t GROUP BY n.y;

year    population
----    ----
2001    1
2002    3
2003    2
2004    3
2005    4
2006    4
2007    4
2008    3
2009    2
2010    3
2011    3
2012    2