MSSQL按日期排序,具有不同的
下面有一个查询段,我正试图从表中的日期字段构建一个“月-年”字符串。非常重要的是,从本月开始到未来12个月,它以正确的顺序出现MSSQL按日期排序,具有不同的,sql,sql-server,tsql,sql-order-by,Sql,Sql Server,Tsql,Sql Order By,下面有一个查询段,我正试图从表中的日期字段构建一个“月-年”字符串。非常重要的是,从本月开始到未来12个月,它以正确的顺序出现 DECLARE @cols AS NVARCHAR(MAX) SELECT @cols = STUFF( (SELECT N',' + QUOTENAME(y) AS [text()] FROM (SELECT DISTINCT CONVERT(char(3), StartDate, 0) + '-' + RIGHT(CONVERT(varchar, Y
DECLARE @cols AS NVARCHAR(MAX)
SELECT @cols = STUFF(
(SELECT N',' + QUOTENAME(y) AS [text()]
FROM (SELECT DISTINCT CONVERT(char(3), StartDate, 0) + '-' +
RIGHT(CONVERT(varchar, YEAR(StartDate)), 2) AS y
FROM Products2
) AS Y
--ORDER BY y desc
FOR XML PATH('')),
1, 1, N'')
这个查询没有按正确的顺序提取日期,我想看看你们是否知道按正确的顺序提取日期的巧妙方法。我可以引入startDate列并按该列进行排序,但它会引入重复项,因为同一个月可能有多个条目。我在这里创建了一个示例表您可以使用
DECLARE @cols AS NVARCHAR(MAX);
SELECT @cols = STUFF((SELECT N',' + QUOTENAME(y) AS [text()]
FROM (SELECT CONVERT(CHAR(3), StartDate, 0) + '-'
+ RIGHT(CONVERT(VARCHAR, YEAR(StartDate)), 2) AS y,
MIN(StartDate) AS z
FROM Products2
GROUP BY CONVERT(CHAR(3), StartDate, 0) + '-'
+ RIGHT(CONVERT(VARCHAR, YEAR(StartDate)), 2)) AS Y
ORDER BY z
FOR XML PATH('')), 1, 1, N'');
SELECT @cols;
您可以使用
DECLARE @cols AS NVARCHAR(MAX);
SELECT @cols = STUFF((SELECT N',' + QUOTENAME(y) AS [text()]
FROM (SELECT CONVERT(CHAR(3), StartDate, 0) + '-'
+ RIGHT(CONVERT(VARCHAR, YEAR(StartDate)), 2) AS y,
MIN(StartDate) AS z
FROM Products2
GROUP BY CONVERT(CHAR(3), StartDate, 0) + '-'
+ RIGHT(CONVERT(VARCHAR, YEAR(StartDate)), 2)) AS Y
ORDER BY z
FOR XML PATH('')), 1, 1, N'');
SELECT @cols;
如果您使用的是
SQL Server 2012+
,则可以使用以下功能:
DECLARE @cols AS NVARCHAR(MAX);
;WITH cte AS -- get only one date per month/year
(
SELECT MIN(StartDate) AS StartDate
FROM #Products2
GROUP BY YEAR(StartDate),MONTH(StartDate)
)
SELECT @cols = STUFF((SELECT ',' + QUOTENAME(FORMAT(StartDate, 'MMM-yy'))
FROM cte
ORDER BY StartDate
FOR XML PATH('')),
1, 1, N'');
SELECT @cols;
输出:
╔══════════════════════════════════════════════════════════════════════════════════════════════════════════════════════╗
║ result ║
╠══════════════════════════════════════════════════════════════════════════════════════════════════════════════════════╣
║ [Dec-15],[Jan-16],[Feb-16],[Mar-16],[Apr-16],[May-16],[Jun-16],[Jul-16],[Aug-16],[Sep-16],[Oct-16],[Nov-16],[Dec-16] ║
╚══════════════════════════════════════════════════════════════════════════════════════════════════════════════════════╝
如果您使用的是
SQL Server 2012+
,则可以使用以下函数:
DECLARE @cols AS NVARCHAR(MAX);
;WITH cte AS -- get only one date per month/year
(
SELECT MIN(StartDate) AS StartDate
FROM #Products2
GROUP BY YEAR(StartDate),MONTH(StartDate)
)
SELECT @cols = STUFF((SELECT ',' + QUOTENAME(FORMAT(StartDate, 'MMM-yy'))
FROM cte
ORDER BY StartDate
FOR XML PATH('')),
1, 1, N'');
SELECT @cols;
输出:
╔══════════════════════════════════════════════════════════════════════════════════════════════════════════════════════╗
║ result ║
╠══════════════════════════════════════════════════════════════════════════════════════════════════════════════════════╣
║ [Dec-15],[Jan-16],[Feb-16],[Mar-16],[Apr-16],[May-16],[Jun-16],[Jul-16],[Aug-16],[Sep-16],[Oct-16],[Nov-16],[Dec-16] ║
╚══════════════════════════════════════════════════════════════════════════════════════════════════════════════════════╝
看起来您刚刚得到月/年,因此我们可以截断到月的第一天,并将其包含在查询中
DATEADD(month, DATEDIFF(month, 0, StartDate), 0) monthStart
现在我们可以通过它订购:
DECLARE @cols AS NVARCHAR(MAX);
SELECT @cols = STUFF(
(SELECT N',' + QUOTENAME(y) AS [text()]
FROM (
SELECT DISTINCT CONVERT(char(3), StartDate, 0) + '-' +
RIGHT(CONVERT(varchar, YEAR(StartDate)), 2) AS y,
DATEADD(month, DATEDIFF(month, 0, StartDate), 0) monthStart
FROM Products2
) AS Y
ORDER BY monthStart
FOR XML PATH('')),
1, 1, N'');
select @cols;
这是输出:
[Dec-15]、[Jan-16]、[Feb-16]、[Mar-16]、[Apr-16]、[May-16]、[Jun-16]、[Jul-16]、[Jul-16]、[Aug-16]、[Sep-16]、[Oct-16]、[Nov-16]、[Dec-16]
这就是你要找的吗?这是一把小提琴:
更好的是,只需选择不同的月份开始日期,然后仅对其进行字符串转换
DECLARE @cols AS NVARCHAR(MAX);
SELECT @cols = STUFF(
(SELECT N',' + QUOTENAME(CONVERT(char(3), monthStart, 0) + '-' +
RIGHT(CONVERT(varchar, YEAR(monthStart)), 2)) AS [text()]
FROM (
SELECT DISTINCT
DATEADD(month, DATEDIFF(month, 0, StartDate), 0) monthStart
FROM Products2
) AS Y
ORDER BY monthStart
FOR XML PATH('')),
1, 1, N'');
select @cols;
这是小提琴:
看起来您刚刚得到了月份/年份,因此我们可以截断到月份的第一天,并将其包含在查询中
DATEADD(month, DATEDIFF(month, 0, StartDate), 0) monthStart
现在我们可以通过它订购:
DECLARE @cols AS NVARCHAR(MAX);
SELECT @cols = STUFF(
(SELECT N',' + QUOTENAME(y) AS [text()]
FROM (
SELECT DISTINCT CONVERT(char(3), StartDate, 0) + '-' +
RIGHT(CONVERT(varchar, YEAR(StartDate)), 2) AS y,
DATEADD(month, DATEDIFF(month, 0, StartDate), 0) monthStart
FROM Products2
) AS Y
ORDER BY monthStart
FOR XML PATH('')),
1, 1, N'');
select @cols;
这是输出:
[Dec-15]、[Jan-16]、[Feb-16]、[Mar-16]、[Apr-16]、[May-16]、[Jun-16]、[Jul-16]、[Jul-16]、[Aug-16]、[Sep-16]、[Oct-16]、[Nov-16]、[Dec-16]
这就是你要找的吗?这是一把小提琴:
更好的是,只需选择不同的月份开始日期,然后仅对其进行字符串转换
DECLARE @cols AS NVARCHAR(MAX);
SELECT @cols = STUFF(
(SELECT N',' + QUOTENAME(CONVERT(char(3), monthStart, 0) + '-' +
RIGHT(CONVERT(varchar, YEAR(monthStart)), 2)) AS [text()]
FROM (
SELECT DISTINCT
DATEADD(month, DATEDIFF(month, 0, StartDate), 0) monthStart
FROM Products2
) AS Y
ORDER BY monthStart
FOR XML PATH('')),
1, 1, N'');
select @cols;
这是小提琴:
非常感谢您的帮助。非常感谢。非常感谢你的帮助。非常感谢。非常感谢你的帮助。非常感谢。非常感谢你的帮助。非常感谢。我认为上面的第二个解决方案是最好的解决方案,因为字符串转换更少。在转换之前,您将获得不同的行。在group by和select语句中使用字符串转换比上面的选择更好。非常感谢您的帮助。我认为上面的第二个解决方案是最好的解决方案,因为字符串转换更少。在转换之前,您将获得不同的行。在group by和select语句中进行字符串转换比上面的选择更好。非常感谢您的帮助。