无法使用SQL滞后和

我的问题是这样的

SELECT
    [day], [time],AvaliableTimes,
    CASE
       WHEN AvaliableTimes > 0 
          THEN SUM(AvaliableTimes) OVER (ORDER BY [day], [time], AvaliableTimes)
          ELSE 0 
    END AS SumValue
FROM
    [AvailableTimes] 
WHERE
    [day] = 1 AND BranchAreaId = 1
ORDER BY
    [day], [time], AvaliableTimes

如果值为null或0，我希望从0开始求和

结果:

---

您可以使用递归CTE来执行此操作。在rcte中执行累积和，如果AvailableTimes=0，则重置它

; with
cte as
(
    select  *, rn = row_number() over (order by time)
    from    yourtable   
),
rcte as
(
    select  *, sumvalues = AvailableTimes
    from    cte
    where   rn = 1

    union all

    select  c.*, sumvalues = case when  c.AvailableTimes <> 0
                      then  r.sumvalues + c.AvailableTimes
                      else  c.AvailableTimes
                      end
    from    cte c
        inner join rcte r   on  c.rn    = r.rn + 1
)
select  day, time, AvailableTimes, sumvalues
from    rcte
order by time

---

有什么问题？向我们显示数据库模式、示例数据、当前和预期输出。请阅读，这里是学习如何提高问题质量和获得更好答案的好地方。将表格和数据作为文本发布