选择SQL Server上每个帐户最多两行

我有这张桌子

ID     AGE     ACCNUM     NAME
--------------------------------
1      10      55409      Intro
2      6       55409      Chapter1
3      4       55409      Chapter2
4      3       69591      Intro
5      6       69591      Outro
6      0       40322      Intro

我需要一个查询，从每个ACCNUM返回两个最大年龄 在这种情况下，记录：

1, 2, 4, 5, 6

我尝试了太多的问题，但都不适合我

我试过这个问题

Select 
    T1.accnum, T1.age 
from 
    table1 as T1
inner join 
    (select 
         accnum, max(age) as max 
     from table1 
     group by accnum) as T2 on T1.accnum = T2.accnum 
                            and (T1.age = T2.max or T1.age = T2.max -1)

您可以使用：

您可以使用：

TSQL排名函数：行数

TSQL排名函数：行数

代码：

使用公共表表达式来实现所需的结果

代码：

使用公共表表达式来实现所需的结果

---

您正在使用哪个数据库？请在OVER子句中使用行号和ORDER BY DESC。Microsoft SQLServer@Yatiac，哪个版本？您使用的是哪个数据库？请在OVER子句中使用行号和ORDER BY DESC。Microsoft SQLServer@Yatiac，哪个版本？

select accnum
     , age
from ( select accnum
            , age
            , row_number() over(partition by accnum order by age desc) as r
       from table1 as T1) t where r < 3

  select id, age, accnum, name 
  from 
  (
     select id, age, accnum, name, ROW_NUMBER() Over (Partition By accnum order by age desc) as rn
     from yourtable
  ) a
  where a.rn <= 2

WITH CTE AS (SELECT ID, AGE, ACCNUM, NAME,
             ROW_NUMBER() OVER(PARTITION BY ACCNUM ORDER BY AGE DESC) AS ROW_NUM
             FROM T1)
SELECT ID, AGE, ACCNUM, NAME
FROM CTE
WHERE ROW_NUM <= 2