如何比较SQL Server中的两行
我习惯于mysql,当你可以毫无问题地做到这一点时。我想在SQLServer中运行以下语句,但是它没有看到列C_计数如何比较SQL Server中的两行,sql,sql-server,Sql,Sql Server,我习惯于mysql,当你可以毫无问题地做到这一点时。我想在SQLServer中运行以下语句,但是它没有看到列C_计数 SQL Server不允许在WHERE子句中使用别名。你必须有这样的东西: SELECT *, Customers - C_COUNT "Difference" FROM ( SELECT A.customers AS CUSTOMERS, (SELECT COUNT(ID) FROM Partners_customers B WHERE
SQL Server不允许在WHERE子句中使用别名。你必须有这样的东西:
SELECT *, Customers - C_COUNT "Difference"
FROM (
SELECT
A.customers AS CUSTOMERS,
(SELECT COUNT(ID)
FROM Partners_customers B WHERE A.ID = B.PIID)
AS C_COUNT FROM Partners A
) t
WHERE CUSTOMERS <> [C_COUNT]
或者,更好的方法是消除内联计数:
select A.customers, count(b.id)
FROM Partners A
LEFT JOIN Partners_customers B ON A.ID = B.PIID
Group By A.ID
having a.customers <> count(b.id)
SQL Server不允许在WHERE子句中使用别名。你必须有这样的东西:
SELECT *, Customers - C_COUNT "Difference"
FROM (
SELECT
A.customers AS CUSTOMERS,
(SELECT COUNT(ID)
FROM Partners_customers B WHERE A.ID = B.PIID)
AS C_COUNT FROM Partners A
) t
WHERE CUSTOMERS <> [C_COUNT]
或者,更好的方法是消除内联计数:
select A.customers, count(b.id)
FROM Partners A
LEFT JOIN Partners_customers B ON A.ID = B.PIID
Group By A.ID
having a.customers <> count(b.id)
完全未经测试
(select * from TabA
minus
select * from TabB) -- Rows in TabA not in TabB
union all
(
select * from TabB
minus
select * from TabA
) -- rows in TabB not in TabA
完全未经测试
(select * from TabA
minus
select * from TabB) -- Rows in TabA not in TabB
union all
(
select * from TabB
minus
select * from TabA
) -- rows in TabB not in TabA
或者:复制/粘贴相关子查询。或者:复制/粘贴相关子查询。