SQL查询以查找具有相似ID的行，其中；不是",/&引用；是不是；在第二列中有模式

我试图为共享重复ID的行编写一个查询，这些行彼此相关，但在第二列中保留特定的模式

想象一下，这是一个网络商店，每个订单都有几个阶段。每个

orderid

在表中都有多个条目

我想排除一些具有特定模式的

Orderid

例如：

Orderid     Stage     OtherInfo
----------------------------------
1           step 1    random info    
1           step 3    random info
1           step 4    random info
3           step 1    random info
3           step 2    random info
5           step 3    random info
4           step 1    random info
4           step 2    random info
4           step 3    random info

现在我想查询相应的

OrderID

满足条件的行，例如：

• 已完成“步骤1”和“步骤3”//但未完成“步骤2”

预期结果是：

Orderid      Stage     OtherInfo
-----------------------------------
1            step 1    random info
1            step 3    random info
1            step 4    random info

---

您可以使用聚合和

having

获取订单ID：

select orderid
from t
group by orderid
having sum(case when stage = 'step 1' then 1 else 0 end) > 0 and
       sum(case when stage = 'step 3' then 1 else 0 end) > 0 and
       sum(case when stage = 'step 2' then 1 else 0 end) = 0;

要获取原始行，请执行以下操作：

select t.*
from t
where t.orderid in (select orderid
                    from t
                    group by orderid
                    having sum(case when stage = 'step 1' then 1 else 0 end) > 0 and
                           sum(case when stage = 'step 3' then 1 else 0 end) > 0 and
                           sum(case when stage = 'step 2' then 1 else 0 end) = 0
                   );

---

您可以使用聚合和

having

获取订单ID：

select orderid
from t
group by orderid
having sum(case when stage = 'step 1' then 1 else 0 end) > 0 and
       sum(case when stage = 'step 3' then 1 else 0 end) > 0 and
       sum(case when stage = 'step 2' then 1 else 0 end) = 0;

要获取原始行，请执行以下操作：

select t.*
from t
where t.orderid in (select orderid
                    from t
                    group by orderid
                    having sum(case when stage = 'step 1' then 1 else 0 end) > 0 and
                           sum(case when stage = 'step 3' then 1 else 0 end) > 0 and
                           sum(case when stage = 'step 2' then 1 else 0 end) = 0
                   );

---

使用EXISTS检查以下条件：

SELECT * 
FROM tablename t
WHERE
  EXISTS (SELECT 1 FROM tablename WHERE tablename.Orderid = t.Orderid AND tablename.stage = 'step 1')
  AND
  EXISTS (SELECT 1 FROM tablename WHERE tablename.Orderid = t.Orderid AND tablename.stage = 'step 3')
  AND
  NOT EXISTS (SELECT 1 FROM tablename WHERE tablename.Orderid = t.Orderid AND tablename.stage = 'step 2');

---

使用EXISTS检查以下条件：

SELECT * 
FROM tablename t
WHERE
  EXISTS (SELECT 1 FROM tablename WHERE tablename.Orderid = t.Orderid AND tablename.stage = 'step 1')
  AND
  EXISTS (SELECT 1 FROM tablename WHERE tablename.Orderid = t.Orderid AND tablename.stage = 'step 3')
  AND
  NOT EXISTS (SELECT 1 FROM tablename WHERE tablename.Orderid = t.Orderid AND tablename.stage = 'step 2');

你也可以使用

SELECT *
FROM T TT
WHERE CASE WHEN EXISTS(SELECT 1 FROM T WHERE OrderID = TT.OrderID AND Stage = 'step 1')
           THEN 
      CASE WHEN EXISTS(SELECT 1 FROM T WHERE OrderID = TT.OrderID AND Stage = 'step 3')
           THEN 
      CASE WHEN NOT EXISTS (SELECT 1 FROM T WHERE OrderID = TT.OrderID AND Stage = 'step 2')
           THEN 1
      END
      END
      END = 1;

或

你也可以使用

SELECT *
FROM T TT
WHERE CASE WHEN EXISTS(SELECT 1 FROM T WHERE OrderID = TT.OrderID AND Stage = 'step 1')
           THEN 
      CASE WHEN EXISTS(SELECT 1 FROM T WHERE OrderID = TT.OrderID AND Stage = 'step 3')
           THEN 
      CASE WHEN NOT EXISTS (SELECT 1 FROM T WHERE OrderID = TT.OrderID AND Stage = 'step 2')
           THEN 1
      END
      END
      END = 1;

或