Sql 如何使用内部联接和子查询编写delete语句

下面的查询有什么问题，它的抛出错误SQL错误：ORA-00933:SQL命令没有正确结束 93300000-“SQL命令未正确结束”。 要从两个与ERROR\u LOG err\u payment\u id匹配的表中删除所有payment\u id吗 请帮我纠正这个问题

TBLPAYMENT(PAYMENT_ID, OTHER COLUMNS)
TBLPAYMENT_ALT_ID (PAYMENT_ID, OTHER COLUMNS)
ERROR_LOG(ERR_PAYMENT_ID, OTHER COLUMNS)

    DELETE TBLPAYMENT, TBLPAYMENT_ALT_ID FROM TBLPAYMENT PYMT INNER JOIN 
    TBLPAYMENT_ALT_ID PAI ON PYMT.PAYMENT_ID = PAI.PAYMENT_ID 
    WHERE PYMT.PAYMENT_ID IN (SELECT ERR_PAYMENT_ID FROM ERROR_LOG);

---

您需要在Oracle中使用2条

delete

语句

DELETE TBLPAYMENT PYMT WHERE PYMT.PAYMENT_ID IN (SELECT ERR_PAYMENT_ID FROM ERROR_LOG);

DELETE TBLPAYMENT_ALT_ID PAI WHERE PAI.PAYMENT_ID IN (SELECT ERR_PAYMENT_ID FROM ERROR_LOG);

---

您需要在Oracle中使用2条

delete

语句

DELETE TBLPAYMENT PYMT WHERE PYMT.PAYMENT_ID IN (SELECT ERR_PAYMENT_ID FROM ERROR_LOG);

DELETE TBLPAYMENT_ALT_ID PAI WHERE PAI.PAYMENT_ID IN (SELECT ERR_PAYMENT_ID FROM ERROR_LOG);

---

无法在SQL Server中使用“加入”删除。此外，您不能使用普通的delete一次从多个表中删除。相反，将其设置为2删除语句，如下所示：

DELETE FROM TBLPAYMENT
       WHERE EXISTS
       (      
          SELECT 1 FROM ERROR_LOG WHERE ERR_PAYMENT_ID = TBLPAYMENT.PAYMENT_ID
       )
DELETE FROM TBLPAYMENT_ALT_ID
       WHERE EXISTS
       (      
          SELECT 1 FROM ERROR_LOG WHERE ERR_PAYMENT_ID = TBLPAYMENT_ALT_ID.PAYMENT_ID
       )

---

无法在SQL Server中使用“加入”删除。此外，您不能使用普通的delete一次从多个表中删除。相反，将其设置为2删除语句，如下所示：

DELETE FROM TBLPAYMENT
       WHERE EXISTS
       (      
          SELECT 1 FROM ERROR_LOG WHERE ERR_PAYMENT_ID = TBLPAYMENT.PAYMENT_ID
       )
DELETE FROM TBLPAYMENT_ALT_ID
       WHERE EXISTS
       (      
          SELECT 1 FROM ERROR_LOG WHERE ERR_PAYMENT_ID = TBLPAYMENT_ALT_ID.PAYMENT_ID
       )

试试这个-

DELETE from TBLPAYMENT where PAYMENT_ID in (select PYMT.PAYMENT_ID FROM TBLPAYMENT PYMT INNER JOIN 
TBLPAYMENT_ALT_ID PAI ON PYMT.PAYMENT_ID = PAI.PAYMENT_ID 
WHERE PYMT.PAYMENT_ID IN (SELECT ERR_PAYMENT_ID FROM ERROR_LOG))

DELETE from TBLPAYMENT_ALT_ID where PAYMENT_ID in (select PAI.PAYMENT_ID FROM TBLPAYMENT PYMT INNER JOIN 
TBLPAYMENT_ALT_ID PAI ON PYMT.PAYMENT_ID = PAI.PAYMENT_ID 
WHERE PYMT.PAYMENT_ID IN (SELECT ERR_PAYMENT_ID FROM ERROR_LOG))

试试这个-

DELETE from TBLPAYMENT where PAYMENT_ID in (select PYMT.PAYMENT_ID FROM TBLPAYMENT PYMT INNER JOIN 
TBLPAYMENT_ALT_ID PAI ON PYMT.PAYMENT_ID = PAI.PAYMENT_ID 
WHERE PYMT.PAYMENT_ID IN (SELECT ERR_PAYMENT_ID FROM ERROR_LOG))

DELETE from TBLPAYMENT_ALT_ID where PAYMENT_ID in (select PAI.PAYMENT_ID FROM TBLPAYMENT PYMT INNER JOIN 
TBLPAYMENT_ALT_ID PAI ON PYMT.PAYMENT_ID = PAI.PAYMENT_ID 
WHERE PYMT.PAYMENT_ID IN (SELECT ERR_PAYMENT_ID FROM ERROR_LOG))

---

您想只删除一列吗？请不要标记不相关的RDBMS。在中，您在

delete

语句的哪里找到了支持

internal JOIN

的语法？您想只删除一列吗？请不要标记不相关的RDBMS。在中，您在哪里找到了支持

internal JOIN

的语法

DELETE

语句？您可以使用SQL Server中的联接进行删除，但不能使用Oracle。您可以使用SQL Server中的联接进行删除，但不能使用Oracle。