Sql 如何更正从子查询聚合时的错误

我有一个如下的查询：

SELECT store_id,
(CASE WHEN txns_A>0 AND txns_B=0 THEN 'A Only' WHEN txns_A=0 AND txns_B>0 THEN 'B Only' END) A_B_indicator,
sum(1) cnt_customers,
sum(spend_A+spend_B)/sum(txns_A+txns_B) avg_receipt
FROM(
    SELECT store_id, cust_id
    SUM(CASE WHEN A_B_indicator='A' THEN spend else 0 end) spend_A,
    SUM(CASE WHEN A_B_indicator='B' THEN spend else 0 end) spend_B,
    SUM(CASE WHEN A_B_indicator='A' THEN spend else 0 end) txns_A,
    SUM(CASE WHEN A_B_indicator='B' THEN spend else 0 end) txns_B
    FROM table1
    GROUP BY store_id, cust_id
    ) table2;

但是，这会生成一个错误，因为store_id不在

GROUP BY

子句中。当我重写查询以包含

groupbystore\u id

子句时，它会抱怨聚合列不在

groupby

中。但是，如果我通过将

Group by

重写为

Group by 1,2,3,4

来添加它们，这也会生成一个错误（

尚未支持UDAF Sum的位置

）

如何将此查询重写为无错误？

您可以这样写：

SELECT store_id,
        (CASE WHEN SUM(txns_A) > 0 AND SUM(txns_B) = 0 THEN 'A Only'
              WHEN SUM(txns_A) = 0 AND SUM(txns_B) > 0 THEN 'B Only'
         END) as A_B_indicator,
       COUNT(*) as cnt_customers,
       SUM(spend_A+spend_B)/sum(txns_A+txns_B) as avg_receipt
FROM (SELECT store_id, cust_id
             SUM(CASE WHEN A_B_indicator='A' THEN spend else 0 end) as spend_A,
             SUM(CASE WHEN A_B_indicator='B' THEN spend else 0 end) as spend_B,
             SUM(CASE WHEN A_B_indicator='A' THEN spend else 0 end) as txns_A,
             SUM(CASE WHEN A_B_indicator='B' THEN spend else 0 end) as txns_B
      FROM table1
      GROUP BY store_id, cust_id
    ) table2
GROUP BY store_id;

---

非常感谢。正如我所理解的，您的方法是在case语句中使用聚合函数，以避免在Group By中包含这些行？这是因为SQL不需要将SUM、COUNT等聚合函数包含在groupby？@Caerus。其目的是实现您想要的逻辑，这可能是“A Only”意味着每个

存储id

的所有行上的“A Only”。