Sql 如何根据同一查询中的条件计算所有记录和部分记录？

我尝试在sql中使用以下命令

SELECT year(datecreated) as tahun, jenis_kelamin, COUNT(jenis_kelamin) as jumlah
from santri
GROUP by jenis_kelamin, tahun

但它是这样表现的

+------+-------------+-----------+
| Tahun|jenis_kelamin| JUmlah    |
+------+-------------+-----------+
| 2009 |    Laki_laki| 5         |
+------+-------------+-----------+
|2010  |  Perempuan  | 7         |
+------+-------------+-----------+
|2010  |  laki-laki  | 6         |
+------+-------------+-----------+

+------+-----------+-----------+-----+
| Tahun| laki-laki | perempuan |Jumlah
+------+-----------+-----------+-----+
| 2009 |    5      | 0         | 5   |
+------+-----------+-----------+-----+
| 2    |    6      | 7         | 13  |
+-----+------------+-----------+-----+

我想要像这样的sql视图

+------+-------------+-----------+
| Tahun|jenis_kelamin| JUmlah    |
+------+-------------+-----------+
| 2009 |    Laki_laki| 5         |
+------+-------------+-----------+
|2010  |  Perempuan  | 7         |
+------+-------------+-----------+
|2010  |  laki-laki  | 6         |
+------+-------------+-----------+

+------+-----------+-----------+-----+
| Tahun| laki-laki | perempuan |Jumlah
+------+-----------+-----------+-----+
| 2009 |    5      | 0         | 5   |
+------+-----------+-----------+-----+
| 2    |    6      | 7         | 13  |
+-----+------------+-----------+-----+

---

我试图修改我的命令，但仍然与此不同

您似乎想要条件聚合：

+------+-------------+-----------+
| Tahun|jenis_kelamin| JUmlah    |
+------+-------------+-----------+
| 2009 |    Laki_laki| 5         |
+------+-------------+-----------+
|2010  |  Perempuan  | 7         |
+------+-------------+-----------+
|2010  |  laki-laki  | 6         |
+------+-------------+-----------+

+------+-----------+-----------+-----+
| Tahun| laki-laki | perempuan |Jumlah
+------+-----------+-----------+-----+
| 2009 |    5      | 0         | 5   |
+------+-----------+-----------+-----+
| 2    |    6      | 7         | 13  |
+-----+------------+-----------+-----+

SELECT YEAR(datecreated) as tahun,
       SUM(CASE WHEN jenis_kelamin = 'laki-laki' THEN 1 ELSE 0 END) as lakilaki,
       SUM(CASE WHEN jenis_kelamin = 'Perempuan' THEN 1 ELSE 0 END) as Perempuan,
       COUNT(*) as jumlah
from santri
GROUP by tahun;

---

我将第二行中的

tahun

值解释为输入错误。

（1）我删除了不兼容的数据库标记。只标记您真正使用的数据库。（2）

Tahun=

2`从何而来？您想处理多少不同的jenis_kelamin值？我使用Xampthank u@GordonLinoff的sql