如何在SQL Server中减去两个数据项

在我的数据库中，有一个表包含（ID、名称、时间、类型）

我需要构造一个查询来输出时差（OUT-IN）

例如：

Osama, 5
Osama, 5

如果你认为你的时间是连续的，你可以做Max（TimeRecorded）。这假设您的ID是连续的。您可以使用检查约束控制其中任何一个

declare @test table (
    Id int, Name varchar(50), TimeRecorded time, TypeOfTimeRecording varchar(3)
)

insert into @test values (1, 'Osama', CONVERT(time, '12:15'), 'IN')
insert into @test values (2, 'Osama', CONVERT(time, '12:20'), 'OUT')
insert into @test values (3, 'Osama', CONVERT(time, '12:25'), 'IN')
insert into @test values (4, 'Osama', CONVERT(time, '12:30'), 'OUT')

 select testOut.Name
        ,testOut.TimeRecorded
        ,testIn.TimeRecorded
        ,DATEDIFF(minute, testIn.TimeRecorded, testOut.TimeRecorded) as [Out - In]
   from @test testOut
            inner join
        @test testIn    on testIn.Id = (select MAX(Id) from @test where Name = testOut.Name and Id < testOut.Id and TypeOfTimeRecording = 'IN')
  where testOut.TypeOfTimeRecording = 'OUT'

declare@testtable(
Id int，Name varchar（50），TimeRecorded time，TypeOfTimeRecording varchar（3）
)
插入@test values（1，'Osama'，CONVERT（time，'12:15'），'IN'）
插入@test values（2，'Osama'，CONVERT（time，'12:20'），'OUT'）
插入@test values（3，'Osama'，CONVERT（time，'12:25'），'IN'）
插入@test values（4，'Osama'，CONVERT（time，'12:30'），'OUT'）
选择testOut.Name
，testOut.TimeRecorded
时间记录
，DATEDIFF（分钟，testIn.TimeRecorded，testOut.TimeRecorded）为[Out-In]
来自@test testOut
内连接
@test testIn on testIn.Id=（从@test中选择MAX（Id），其中Name=testOut.Name和Id

此处的

TestData

CTE纯粹用于测试目的。另外，我注意到您的数据有一个错误。上次我检查的

14:15 AM

不是有效时间。它是

14:15

（通过24小时时钟）或

2:15 AM

（通过12小时时钟）。此外，此解决方案需要SQL Server 2005或更高版本

With TestData As
    (
    Select 1 As Id, 'Osama' As Name, '12:15' As Time, 'IN' As Type
    Union All Select 2, 'Osama', '12:20', 'OUT'
    Union All Select 3, 'Osama', '14:15', 'IN'
    Union All Select 4, 'Osama', '14:20', 'OUT'
    )
    , CheckInCheckOut As
    (
    Select Id, Name, Time, Type
        , Row_Number() Over ( Partition By Name, Type Order By Time ) As Num
    From TestData
    )
Select C1.Name
    , DateDiff( mi, CAST(C1.Time as datetime), Cast(C2.Time As datetime) ) As [OUT-IN]
From CheckInCheckOut As C1
    Join CheckInCheckOut As C2
        On C2.Name = C1.Name
            And C2.Type = 'OUT'
            And C2.Num = C1.Num 
Where C1.Type = 'IN'    

declare @test table (
    Id int, Name varchar(50), TimeRecorded time, TypeOfTimeRecording varchar(3)
)

insert into @test values (1, 'Osama', CONVERT(time, '12:15'), 'IN')
insert into @test values (2, 'Osama', CONVERT(time, '12:20'), 'OUT')
insert into @test values (3, 'Osama', CONVERT(time, '12:25'), 'IN')
insert into @test values (4, 'Osama', CONVERT(time, '12:30'), 'OUT')

 select testOut.Name
        ,testOut.TimeRecorded
        ,testIn.TimeRecorded
        ,DATEDIFF(minute, testIn.TimeRecorded, testOut.TimeRecorded) as [Out - In]
   from @test testOut
            inner join
        @test testIn    on testIn.Id = (select MAX(Id) from @test where Name = testOut.Name and Id < testOut.Id and TypeOfTimeRecording = 'IN')
  where testOut.TypeOfTimeRecording = 'OUT'

With TestData As
    (
    Select 1 As Id, 'Osama' As Name, '12:15' As Time, 'IN' As Type
    Union All Select 2, 'Osama', '12:20', 'OUT'
    Union All Select 3, 'Osama', '14:15', 'IN'
    Union All Select 4, 'Osama', '14:20', 'OUT'
    )
    , CheckInCheckOut As
    (
    Select Id, Name, Time, Type
        , Row_Number() Over ( Partition By Name, Type Order By Time ) As Num
    From TestData
    )
Select C1.Name
    , DateDiff( mi, CAST(C1.Time as datetime), Cast(C2.Time As datetime) ) As [OUT-IN]
From CheckInCheckOut As C1
    Join CheckInCheckOut As C2
        On C2.Name = C1.Name
            And C2.Type = 'OUT'
            And C2.Num = C1.Num 
Where C1.Type = 'IN'