SQL—按一列和某些字段类型进行分区

我的桌子要大得多，但是一个小的剪子会是这样的：

---------+---+----------+--------+------------+---
|distance|qtt|deliver_by| store  |deliver_time| ...
+--------+---+----------+--------+------------|---
|   11   |  1|  pa      | store_a|  1111      |
|   123  |  2|  pa      | store_a|  1112      |
|   33   |  3|  pb      | store_a|  1113      |
|   33   |  2|  pa      | store_b|  2221      |
|   44   |  2|  pb      | store_b|  2222      |
|   5    |  2|  pc      | store_b|  2223      |
|   5    |  2|  pc      | store_b|  2224      |
|   6    |  5|  pb      | store_c|  3331      |
|   7    |  5|  pb      | store_c|  3332      |
----------------------------------------------....

有多家商店，但只有3家可能的送货店（送货人：pa、pb和pc）在特定时间送货。考虑<代码>交付时间< /代码>时间戳。 我想选择整个表，并在商店中添加6个新列、min和max每个

deliver\u的时间。
一个商店可以由三种送货方式（pa、pb、pc）中的任何一种提供服务，但不是必需的

我可以完成几乎正确的结果，通过下面的查询，问题是在情况下

delivery\u bypX不存在，我不会得到空值，而是商店交货的最小/最大值

我真的很想使用分区，所以我写了这个来添加新的min/max列：

select
  min(deliver_time) over (partition by store, deliver_by='pa') as as min_time_sd_pa
, max(deliver_time) over (partition by store, deliver_by='pa') as as min_time_sd_pa

, min(deliver_time) over (partition by store, deliver_by='pb') as as min_time_sd_pb
, max(deliver_time) over (partition by store, deliver_by='pb') as as min_time_sd_pb

, min(deliver_time) over (partition by store, deliver_by='pc') as as min_time_sd_pc
, max(deliver_time) over (partition by store, deliver_by='pc') as as min_time_sd_pc

, distance, qtt, ....
from mytable

正确的输出应为：

min_time_sd_pa|max_time_sd_pa|min_time_sd_pb|max_time_sd_pb|min_time_sd_pc|max_time_sd_pc|distance|qtt|deliver_by| store  |deliver_time
--------------+--------------+--------------+--------------+--------------+--------------+--------+---+----------+--------+------------
    1111      |  1112        |  1113        |   1113       |   null       |   null       |   11   |  1| pa       | store_a| 1111
    1111      |  1112        |  1113        |   1113       |   null       |   null       |   123  |  2| pa       | store_a| 1112
    1111      |  1112        |  1113        |   1113       |   null       |   null       |   33   |  3| pb       | store_a| 1113
    2221      |  2221        |  2222        |   2222       |   2223       |   2224       |   33   |  2| pa       | store_b| 2221
    2221      |  2221        |  2222        |   2222       |   2223       |   2224       |   44   |  2| pb       | store_b| 2222
    2221      |  2221        |  2222        |   2222       |   2223       |   2224       |   5    |  2| pc       | store_b| 2223
    2221      |  2221        |  2222        |   2222       |   2223       |   2224       |   5    |  2| pc       | store_b| 2224
    null      |  null        |  null        |   null       |   3331       |   3332       |   6    |  5| pb       | store_c| 3331
    null      |  null        |  null        |   null       |   3331       |   3332       |   7    |  5| pb       | store_c| 3332
---------------------------------------------------------------------------------------------------------------------------------------

我的

select min（..）over..

语句中缺少了什么，或者我如何以最简单的方式实现这个结果？ 我使用的是HiveQL，但我想这在大多数SQL DBMS中是通用的

---

谢谢

您可以在

min

和

max

中使用

大小写

表达式来完成

select
 min(case when deliver_by='pa' then deliver_time end) over (partition by store) as min_time_sd_pa
,max(case when deliver_by='pa' then deliver_time end) over (partition by store) as max_time_sd_pa
,min(case when deliver_by='pb' then deliver_time end) over (partition by store) as min_time_sd_pb
,max(case when deliver_by='pb' then deliver_time end) over (partition by store) as max_time_sd_pb
,min(case when deliver_by='pc' then deliver_time end) over (partition by store) as min_time_sd_pc
,max(case when deliver_by='pc' then deliver_time end) over (partition by store) as max_time_sd_pc
,m.*
from mytable m

---

您可以使用

min

和

max

中的

case

表达式执行此操作

select
 min(case when deliver_by='pa' then deliver_time end) over (partition by store) as min_time_sd_pa
,max(case when deliver_by='pa' then deliver_time end) over (partition by store) as max_time_sd_pa
,min(case when deliver_by='pb' then deliver_time end) over (partition by store) as min_time_sd_pb
,max(case when deliver_by='pb' then deliver_time end) over (partition by store) as max_time_sd_pb
,min(case when deliver_by='pc' then deliver_time end) over (partition by store) as min_time_sd_pc
,max(case when deliver_by='pc' then deliver_time end) over (partition by store) as max_time_sd_pc
,m.*
from mytable m