Sql 正在另一个字符串中查找子字符串

我有两个MS SQL表：

我必须用循环来说明，如果表1的字符串的所有字符都包含在表2的字符串中

例如

希望你能帮忙

谢谢

--编辑

下划线是分隔符

下面是结果的样子：

您可以尝试以下方法：

DECLARE @xml1 xml, @xml2 xml

SELECT @xml1= (
SELECT (CAST('<b id="'+cast(id as nvarchar(2)) + '"><a>' + REPLACE(string,'_','</a><a>') + '</a></b>' as xml))
from table1
FOR XML PATH('')
)

SELECT @xml2= (
SELECT (CAST('<b id="'+cast(id as nvarchar(2)) + '"><a>' + REPLACE(string,'_','</a><a>') + '</a></b>' as xml))
from table2
FOR XML PATH('')
)

;WITH res1 AS (
SELECT  t.v.value('../@id','int') as id,
        t.v.value('.','char(1)') as chars
FROM @xml1.nodes('/b/a') as t(v)
WHERE t.v.value('.','char(1)') !=''
), res2 AS (
SELECT  t.v.value('../@id','int') as id,
        t.v.value('.','char(1)') as chars
FROM @xml2.nodes('/b/a') as t(v)
WHERE t.v.value('.','char(1)') !=''
), cte1 AS (
SELECT distinct id, (SELECT '_' + r.chars FROM res1 r WHERE r.id = r1.id ORDER BY r.id, r.chars FOR XML PATH('')) + '_' as string
FROM res1 r1
), cte2 AS (
SELECT distinct id, (SELECT '_' + r.chars FROM res2 r WHERE r.id = r2.id ORDER BY r.id, r.chars FOR XML PATH('')) + '_' as string
FROM res2 r2
)

SELECT t1.id as table1id, t2.id as table2id
FROM cte1 t1
INNER  JOIN cte2 t2 ON  t2.string LIKE '%'+t1.string+'%' --t1.string LIKE '%'+t2.string+'%' 
ORDER BY t1.id

如我所见，

\u a\u b\u

中包含了

\u a\u c\u b\u d\u

您可以尝试以下方法：

DECLARE @xml1 xml, @xml2 xml

SELECT @xml1= (
SELECT (CAST('<b id="'+cast(id as nvarchar(2)) + '"><a>' + REPLACE(string,'_','</a><a>') + '</a></b>' as xml))
from table1
FOR XML PATH('')
)

SELECT @xml2= (
SELECT (CAST('<b id="'+cast(id as nvarchar(2)) + '"><a>' + REPLACE(string,'_','</a><a>') + '</a></b>' as xml))
from table2
FOR XML PATH('')
)

;WITH res1 AS (
SELECT  t.v.value('../@id','int') as id,
        t.v.value('.','char(1)') as chars
FROM @xml1.nodes('/b/a') as t(v)
WHERE t.v.value('.','char(1)') !=''
), res2 AS (
SELECT  t.v.value('../@id','int') as id,
        t.v.value('.','char(1)') as chars
FROM @xml2.nodes('/b/a') as t(v)
WHERE t.v.value('.','char(1)') !=''
), cte1 AS (
SELECT distinct id, (SELECT '_' + r.chars FROM res1 r WHERE r.id = r1.id ORDER BY r.id, r.chars FOR XML PATH('')) + '_' as string
FROM res1 r1
), cte2 AS (
SELECT distinct id, (SELECT '_' + r.chars FROM res2 r WHERE r.id = r2.id ORDER BY r.id, r.chars FOR XML PATH('')) + '_' as string
FROM res2 r2
)

SELECT t1.id as table1id, t2.id as table2id
FROM cte1 t1
INNER  JOIN cte2 t2 ON  t2.string LIKE '%'+t1.string+'%' --t1.string LIKE '%'+t2.string+'%' 
ORDER BY t1.id

---

正如我所见，

\u a_b_

中包含了

\u a_c_b_d_

两个表中包含行的示例数据将有助于解释您尝试执行的操作。不清楚您想要什么结果。下划线是分隔符还是输入的一部分？请使用校验和将表1和表2对齐！！校验和不起作用选择校验和（“'u a_b_c'），校验和（'u b_c_a'）产生不同的输出，但OP希望这是真的您似乎有错误的数据格式。如果以字符串形式存储列表，则应修复基础数据以使用连接表。两个表中的行示例数据将有助于解释您试图执行的操作。不清楚您想要什么结果。下划线是分隔符还是输入的一部分？请使用校验和将表1和表2对齐！！校验和不起作用选择校验和（“'u a_b_c'），校验和（'u b_c_a'）产生不同的输出，但OP希望这是真的您似乎有错误的数据格式。如果以字符串形式存储列表，则应修复基础数据以使用连接表。

table1id    table2id
----------- -----------
1           1
2           1
2           4
4           1
4           3

(5 row(s) affected)