SQL：如何从GROUPBY语句中获取更多信息

考虑以下SQL语句：

SELECT 
invoice.customer_name, 
invoice.customer_id, 
invoice.shop_location,
sum(invoice.cost)
FROM invoice
GROUP BY
invoice.customer_name, invoice.customer_id, invoice.shop_location

---

如果不是发票.shop\u location的

值，可以对语句执行哪些操作来标识哪些行与其他行相同？
尝试此操作-删除发票.ShopLocation

SELECT  
invoice.customer_name,  
invoice.customer_id,  
sum(invoice.cost) 
FROM invoice 
GROUP BY 
invoice.customer_name, invoice.customer_id

这将提供与其余字段匹配的所有行
尝试此操作-删除Invoice.ShopLocation

SELECT  
invoice.customer_name,  
invoice.customer_id,  
sum(invoice.cost) 
FROM invoice 
GROUP BY 
invoice.customer_name, invoice.customer_id

Select customer_name, Customer_id, count(Shop_location) from
(
    SELECT  
        invoice.customer_name,  
        invoice.customer_id,  
        invoice.shop_location, 
        sum(invoice.cost) 
    FROM invoice 
    GROUP BY 
        invoice.customer_name, 
        invoice.customer_id,
        invoice.shop_location 
 )
 Group by customer_name, Customer_id
 Having    count(Shop_location) > 1

这将提供与其余字段匹配的所有行

Select customer_name, Customer_id, count(Shop_location) from
(
    SELECT  
        invoice.customer_name,  
        invoice.customer_id,  
        invoice.shop_location, 
        sum(invoice.cost) 
    FROM invoice 
    GROUP BY 
        invoice.customer_name, 
        invoice.customer_id,
        invoice.shop_location 
 )
 Group by customer_name, Customer_id
 Having    count(Shop_location) > 1

上述查询将为您提供具有多个店铺位置的Customername和id的组合

注意：我不确定这是否是优化的

上述查询将为您提供具有多个店铺位置的Customername和id的组合

注意：我不确定这是否是优化的
也许我的问题不清楚。我想知道结果中存在哪些行只是因为不同的发票。shop_location将计数（不同的发票。shop_location）>1添加到Sachin的查询中正好可以。也许我的问题不清楚。我想知道结果中存在哪些行仅仅是因为不同的发票。shop_location向Sachin的查询添加计数（不同的发票。shop_location）>1

就可以做到这一点。我希望原始查询结果的行中有一个值来识别这一点。在我的头顶上，我想你可以把这个查询和你的查询连接起来，得到你的结果。。。我会研究并发布一些更为冗长的内容…我希望原始查询结果的行中有一个值来标识这一点。在我的脑海中，我认为您可以将此查询与您的查询结合起来以获得结果。。。我会研究和张贴，如果有什么更优雅的。。。