同一数据集上不同级别的SQL分组

我有以下数据集，我希望创建不同的组来统计名称下的值的出现次数

Have：（县在字符串中）

想要：

我相信通过SQL，过分区将允许按不同级别进行计数 比如：

count(name) over (partition by name) as freq_name,
count(name) over (partition by state) as freq_state,
count(name) as freq_county
from have
group by name,state, county;

---

由于某些原因，这段代码没有为freq_name提供正确的计数。我还想检查我的freq_state和freq_county代码是否准确。谢谢

对于

freq\u name

，使用

count（*）

而不是

count（name）

---

对于

freq\u name

，请使用

count（*）

而不是

count（name）

你似乎想要：

select name, state, county, count(*) as this_count,
       sum(count(*)) over (partition by name) as freq_name,
       sum(count(*)) over (partition by state) as freq_state,
       sum(count(*)) as freq_county
from have
group by name, state, county;

你似乎想要：

select name, state, county, count(*) as this_count,
       sum(count(*)) over (partition by name) as freq_name,
       sum(count(*)) over (partition by state) as freq_state,
       sum(count(*)) as freq_county
from have
group by name, state, county;

---

还有，我的freq_state代码看起来正确吗？我使用的是大数据集，很难在详细的层面上进行验证。我非常确定freq_county应该可以工作……还有，我的freq_state代码看起来正确吗？我使用的是大型数据集，很难在详细级别上进行验证。我非常确定freq_county应该可以工作…是否可以计数（*）允许我仅按州计算名称的外观？@lydias。。这是使用窗口函数。“是的”。您是否运行了查询？是否计数（*）允许我仅按状态计数名称的外观？@lydias。。这是使用窗口函数。“是的”。你运行查询了吗？

count(*) over (partition by name) as freq_name,
count(name) over (partition by state) as freq_state,
count(name) as freq_county
from have
group by name,state, county;

select name, state, county, count(*) as this_count,
       sum(count(*)) over (partition by name) as freq_name,
       sum(count(*)) over (partition by state) as freq_state,
       sum(count(*)) as freq_county
from have
group by name, state, county;