Postgresql-省略派生类型上的组

我有下面的查询，如果它与求和条件匹配，则不会正确返回一行。。。然而问题是我需要改变它

我需要它现在不返回组，如果所有等级总数都已满足

例如，我返回了如下数据。当前，如果A101有足够的引用，它将不会选择该行。但是，如果我想要所有A1，除非所有A1##值都满足SQL条件，该怎么办

我唯一的想法是运行另一个查询以获得下面的结果，然后根据该结果尝试选择？但必须有一个更简单、更快的方法

A101本年级

A102本年级

A103本年级

A201本等级

    RETURN QUERY            
        SELECT comp.id, comp.shortname, comp.description,
   (sum(CASE WHEN crs.grade = 'Pass' THEN 1 WHEN crs.grade = 'Fail' THEN -1        WHEN crs.grade = 'Exceeds' THEN 2 ELSE 0 END) >= comp_l.competency_break_level) AS reached_limit
FROM competencies comp
JOIN competency_levels comp_l USING (competency_group)
LEFT JOIN (
SELECT competency_id, review_status_id
 FROM call_competency
 JOIN users ON users.id = user_id
 WHERE email = _studentemail
) call_c ON call_c.competency_id = comp.id
LEFT JOIN competency_review_status crs ON crs.id = call_c.review_status_id
GROUP BY comp.id, comp.shortname, comp.description,       comp_l.competency_break_level
ORDER BY comp.id; 

A203本年级

    RETURN QUERY            
        SELECT comp.id, comp.shortname, comp.description,
   (sum(CASE WHEN crs.grade = 'Pass' THEN 1 WHEN crs.grade = 'Fail' THEN -1        WHEN crs.grade = 'Exceeds' THEN 2 ELSE 0 END) >= comp_l.competency_break_level) AS reached_limit
FROM competencies comp
JOIN competency_levels comp_l USING (competency_group)
LEFT JOIN (
SELECT competency_id, review_status_id
 FROM call_competency
 JOIN users ON users.id = user_id
 WHERE email = _studentemail
) call_c ON call_c.competency_id = comp.id
LEFT JOIN competency_review_status crs ON crs.id = call_c.review_status_id
GROUP BY comp.id, comp.shortname, comp.description,       comp_l.competency_break_level
ORDER BY comp.id; 

A204本等级

    RETURN QUERY            
        SELECT comp.id, comp.shortname, comp.description,
   (sum(CASE WHEN crs.grade = 'Pass' THEN 1 WHEN crs.grade = 'Fail' THEN -1        WHEN crs.grade = 'Exceeds' THEN 2 ELSE 0 END) >= comp_l.competency_break_level) AS reached_limit
FROM competencies comp
JOIN competency_levels comp_l USING (competency_group)
LEFT JOIN (
SELECT competency_id, review_status_id
 FROM call_competency
 JOIN users ON users.id = user_id
 WHERE email = _studentemail
) call_c ON call_c.competency_id = comp.id
LEFT JOIN competency_review_status crs ON crs.id = call_c.review_status_id
GROUP BY comp.id, comp.shortname, comp.description,       comp_l.competency_break_level
ORDER BY comp.id; 

B101本等级

    RETURN QUERY            
        SELECT comp.id, comp.shortname, comp.description,
   (sum(CASE WHEN crs.grade = 'Pass' THEN 1 WHEN crs.grade = 'Fail' THEN -1        WHEN crs.grade = 'Exceeds' THEN 2 ELSE 0 END) >= comp_l.competency_break_level) AS reached_limit
FROM competencies comp
JOIN competency_levels comp_l USING (competency_group)
LEFT JOIN (
SELECT competency_id, review_status_id
 FROM call_competency
 JOIN users ON users.id = user_id
 WHERE email = _studentemail
) call_c ON call_c.competency_id = comp.id
LEFT JOIN competency_review_status crs ON crs.id = call_c.review_status_id
GROUP BY comp.id, comp.shortname, comp.description,       comp_l.competency_break_level
ORDER BY comp.id; 

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请提供示例数据和预期结果，以及可以针对该示例数据运行的查询。感谢Craig的回复。这是我的dropbox上的DB输出。我希望这是罚款链接在这里，为您得到。我在这里输出了我们的测试数据。同样对于预期的结果，它是5列，每个A101项和最后一列是它遇到多少次的计数，就像这个链接显示我的图片上面的查询正在运行。