Sql 在另一个字段列上选择带有distinct的ties的Top 1

我有这样一个示例表记录：

AutoID  ReceiptNo  Outlet_Code  
-------------------------------- 
    1       SUN12        Store X     
    3       SUN12        Store X     
    4       ART123       Store y

我想根据门店编号选择一个前1名的领带，在收货处有不同的号码，这样在这种情况下，我的结果将是：

门店X/门店Y

因为我应该将2个Store X记录读取为1，因为它们具有相同的receiptNo

这是我查询的一部分：

SELECT TOP 1 WITH TIES (Outlet_Code)                  
From [Trans] T                 
WHERE T.CardNo IN (Select [CardNo] From [Card]                
                         Where  [MemberID] = 
                         (Select [ID] From [Member]  Where [autoid] = @MemAutoID ))   
GROUP BY Outlet_Code     
ORDER BY Count(T.Outlet_Code) Desc 

---

我不知道我是否理解正确，但是使用

DISTINCT

怎么样

SELECT DISTINCT Outlet_Code FROM tableName

---

EWW。。。子查询。。。这对你有用吗

SELECT DISTINCT T.Outlet_Code  
FROM [Trans] T, [Card] C, [Member] M
WHERE T.CardNo = C.CardNo
AND C.MemberID = M.ID
AND M.autoid = @MemAutoID
ORDER BY Count(T.Outlet_Code) Desc 

或者是不那么懒惰的方式

SELECT DISTINCT T.Outlet_Code  
FROM [Trans] AS T
JOIN  [Card] AS C ON (T.CardNo = C.CardNo)
JOIN [Member] AS M ON (C.MemberID = M.ID)
WHERE M.autoid = @MemAutoID
ORDER BY Count(T.Outlet_Code) Desc 

---

您的GROUPBY子句是正确的，但在ORDERBY子句中必须使用不同的列值ReceiptNo

SELECT TOP 1 WITH TIES Outlet_Code                  
FROM [Trans] T                 
WHERE T.CardNo IN (
                   SELECT c.[CardNo]
                   FROM [Card] c JOIN [Member] m ON c.[MemberID] = m.ID                
                   WHERE m.[autoid] = @MemAutoID                   
                   )
GROUP BY T.Outlet_Code     
ORDER BY COUNT(DISTINCT T.ReceiptNo) DESC

---

演示

请参见：您已有的查询有什么问题？它是否给出了错误的结果？它是否给出错误消息？EWW。。。从1987年开始？强烈建议坚持正确的

内部联接

语法。