Sql 如何基于另一列的一部分更新列
我需要使用循环或任何其他过程，使用同一表中另一列的引用更新同一表中所有记录的一列记录Sql 如何基于另一列的一部分更新列,sql,oracle,plsql,oracle-sqldeveloper,Sql,Oracle,Plsql,Oracle Sqldeveloper,我需要使用循环或任何其他过程，使用同一表中另一列的引用更新同一表中所有记录的一列记录 Column1 Column2 kalyan kalyan122@gmail.com arun arun414 mahesh ma223ds@gmail.com blog 4anyinfo Co
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
提前感谢。您只需参考集合中的列即可
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
UPDATE myTable
SET
Column1 = (case when INSTR(Column2,'@') > 0 then SUBSTR(Column2,1,INSTR(Column2,'@')-1) else Column2 end);
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
您可以添加where子句来指定要更新的行。您只需引用集合中的列即可
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
UPDATE myTable
SET
Column1 = (case when INSTR(Column2,'@') > 0 then SUBSTR(Column2,1,INSTR(Column2,'@')-1) else Column2 end);
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
您可以添加where子句来指定要更新的行。如果是oracle，则可以执行以下操作：
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
UPDATE YourTable
SET Column1 = CASE WHEN INSTR(column2, '@')
THEN substring(column2,0,INSTR(column2, '@')-1)
ELSE column2
END
如果是oracle，您可以执行以下操作：
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
UPDATE YourTable
SET Column1 = CASE WHEN INSTR(column2, '@')
THEN substring(column2,0,INSTR(column2, '@')-1)
ELSE column2
END
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
这显示了如何提取所需的数据：
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
SQL> with tbl(col1, col2) as (
select 'kalyan','kalyan122@gmail.com' from dual union
select 'arun', 'arun414' from dual union
select 'mahesh','ma223ds@gmail.com' from dual union
select 'blog', '4anyinfo' from dual
)
select regexp_replace(col2, '^(.*)@.*$', '\1') col1_data
from tbl;
COL1_DATA
---------------------------------------------------------------
arun414
4anyinfo
kalyan122
ma223ds
SQL>
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
create table tbl_bkup as select * from tbl;
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
Update tbl
set column1 = regexp_replace(column2, '^(.*)@.*$', '\1');
这显示了如何提取所需的数据：
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
SQL> with tbl(col1, col2) as (
select 'kalyan','kalyan122@gmail.com' from dual union
select 'arun', 'arun414' from dual union
select 'mahesh','ma223ds@gmail.com' from dual union
select 'blog', '4anyinfo' from dual
)
select regexp_replace(col2, '^(.*)@.*$', '\1') col1_data
from tbl;
COL1_DATA
---------------------------------------------------------------
arun414
4anyinfo
kalyan122
ma223ds
SQL>
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
create table tbl_bkup as select * from tbl;
Column1 Column2
kalyan kalyan122@gmail.com
arun arun414
mahesh ma223ds@gmail.com
blog 4anyinfo
Column1 Column2
kalyan122 kalyan122@gmail.com
arun414 arun414
ma223ds ma223ds@gmail.com
4anyinfo 4anyinfo
Update tbl
set column1 = regexp_replace(column2, '^(.*)@.*$', '\1');
SQL-SERVER或ORACLE？基于pl/SQL和ORACLE sqldeveloper标记，我删除了SQL SERVER标记。SQL-SERVER或ORACLE？基于pl/SQL和ORACLE sqldeveloper标记，我删除了SQL SERVER标记。