Sql 如何从平面表中提取层次结构?

Sql 如何从平面表中提取层次结构?,sql,oracle,hierarchy,hierarchical-data,Sql,Oracle,Hierarchy,Hierarchical Data,我想从oracle数据库中的表中提取层次结构。 表如下所示: +----+--------+----------------+---------------------+ | id | lvl1 | lvl2 | lvl3 | +----+--------+----------------+---------------------+ | 1 | Oracle | Marketing unit | Internet

我想从oracle数据库中的表中提取层次结构。 表如下所示:

+----+--------+----------------+---------------------+
| id | lvl1   | lvl2           | lvl3                | 
+----+--------+----------------+---------------------+
| 1  | Oracle | Marketing unit | Internet            | 
+----+--------+----------------+---------------------+
| 2  | Oracle | Lawyers unit   | Intellectual        | 
+----+--------+----------------+---------------------+
| 3  | Oracle | Finance unit   | null                |
+----+--------+----------------+---------------------+
| 4  | Oracle | Lawyers unit   | Judicial department | 
+----+--------+----------------+---------------------+
| 5  | Oracle | IT unit        | Database            |
+----+--------+----------------+---------------------+
| 6  | Oracle | Marketing unit | Television          | 
+----+--------+----------------+---------------------+
| 7  | Oracle | IT unit        | ERP                 | 
+----+--------+----------------+---------------------+
这就是我想要的:

- Oracle
. - Marketing unit
.   - Internet
.   - Television 
. - Lawyers unit
.   - Intellectual
.   - Judicial department
. - Finance unit
. - IT unit
.   - Database
.   - ERP
我读过关于Oracle分层查询的文章,但我不知道如何利用我的表结构实现它。。。 最后,我必须让JSON显示在网页上。 为了方便,我在桌上准备了一张桌子

我将非常感谢您的帮助, 有什么想法吗?

一种方法是(使用
UNPIVOT
):


看起来很棒,这就是我想要的,谢谢!有没有办法使用oracle将其作为JSON?
WITH unpiv AS (SELECT lvl, par, cur, MIN(id) id FROM HIERARCHY_SAMPLE
               unpivot ((par, cur) for lvl in ((lvl1 /*Something here - it doesn't really matter */,lvl1) as 1
                                              ,(lvl1,lvl2) as 2
                                              ,(lvl2,lvl3) as 3))
                WHERE cur IS NOT NULL
               GROUP BY lvl,par,cur)
SELECT LPAD('- ', LEVEL*2)||cur 
  FROM unpiv
START WITH lvl = 1
CONNECT BY lvl = PRIOR lvl + 1
       AND par = PRIOR cur
ORDER siblings BY id