SQL-仅从包含字符串的列中选择数字
我有一个这样的表,第一列包含id,第二列是varchar,其中包含字符串和一些公式-SQL-仅从包含字符串的列中选择数字,sql,sql-server,sql-server-2008,patindex,charindex,Sql,Sql Server,Sql Server 2008,Patindex,Charindex,我有一个这样的表,第一列包含id,第二列是varchar,其中包含字符串和一些公式- column_id column_formula 4686 4686 = 4684 - 4685 4687 4687 = ( 4681 / 1.205 / 4684 * 1000 ) 4717 4717 = ( 4711 + 4712 + 4713 + 4714 + 4715 + 4716 )/6 4719 4719 = abs(
column_id column_formula
4686 4686 = 4684 - 4685
4687 4687 = ( 4681 / 1.205 / 4684 * 1000 )
4717 4717 = ( 4711 + 4712 + 4713 + 4714 + 4715 + 4716 )/6
4719 4719 = abs( 4716 - 4715 )
4787 4787 = max(max(max(max(max( 4780 , 4781 ), 4782 ), 4783 ), 4784 ), 4785 ) - min(min(min(min(min( 4780 , 4781 ), 4782 ), 4783 ), 4784 ), 4785 )
现在需要一些查询,它将给出如下输出-
col1 col2
4686 4684
4686 4685
4687 4681
4687 4684
4717 4711
4717 4712
等等。。仅限数字,但小于4位的数字除外,如1.205左右。。和1000
在这一点上使用patindex非常困难
您需要一个函数,用于将逗号分隔的字符串拆分为单独的行。以下是Jeff Moden的函数:
CREATE FUNCTION [dbo].[DelimitedSplit8K](
@pString NVARCHAR(4000), @pDelimiter NCHAR(1)
)
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
)
,E2(N) AS (SELECT 1 FROM E1 a, E1 b)
,E4(N) AS (SELECT 1 FROM E2 a, E2 b)
,cteTally(N) AS(
SELECT TOP (ISNULL(DATALENGTH(@pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
)
,cteStart(N1) AS(
SELECT 1 UNION ALL
SELECT t.N+1 FROM cteTally t WHERE SUBSTRING(@pString,t.N,1) = @pDelimiter
),
cteLen(N1,L1) AS(
SELECT
s.N1,
ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000)
FROM cteStart s
)
SELECT
ItemNumber = ROW_NUMBER() OVER(ORDER BY l.N1),
Item = SUBSTRING(@pString, l.N1, l.L1)
FROM cteLen l
其思想是首先用逗号替换所有数学字符:+、-、*、/、=,。这是必需的,以便我们以后可以拆分操作数。接下来调用splitter函数以使用逗号作为分隔符拆分行。拆分完成后,使用不相似的“[^0-9]%”和项筛选所有数值。您希望将此操作的结果插入临时表。然后,使用适当的WHERE子句从临时表中选择:
这是一个没有用户定义函数的解决方案。它应该快得多:
DECLARE @t TABLE ( ID INT, F NVARCHAR(MAX) )
INSERT INTO @t
VALUES ( 4686, '4686 = 4684 - 4685' ),
( 4687, '4687 = ( 4681 / 1.205 / 4684 * 1000 )' ),
( 4717, '4717 = ( 4711 + 4712 + 4713 + 4714 + 4715 + 4716 )/6' ),
( 4719, '4719 = abs( 4716 - 4715 ) ' ),
( 4787,
'4787 = max(max(max(max(max( 4780 , 4781 ), 4782 ), 4783 ), 4784 ), 4785 ) - min(min(min(min(min( 4780 , 4781 ), 4782 ), 4783 ), 4784 ), 4785 )' )
DECLARE @chars TABLE ( ID INT, c NVARCHAR(MAX) )
INSERT INTO @chars
VALUES ( 1, ' ' ),
( 2, '(' ),
( 3, ')' ),
( 4, '/' ),
( 5, '*' ),
( 6, '+' ),
( 7, '-' ),
( 8, 'max' ),
( 9, 'min' ),
( 10, 'abs' ),
( 11, '=' )
DECLARE @count INT
SELECT @count = COUNT(*) FROM @chars;
WITH recursion
AS ( SELECT t.ID ,
REPLACE(F, ' ', ',') + ',' AS F ,
1 AS CharID
FROM @t t
UNION ALL
SELECT t.ID ,
REPLACE(t.F, c.c, ',') AS F ,
t.CharID + 1 AS CharID
FROM recursion t
JOIN @chars c ON c.ID = t.CharID + 1
WHERE t.CharID < @count
),
commastrings
AS ( SELECT ID ,
STUFF(F, LEN(F), 1, '') AS F
FROM ( SELECT ID ,
REPLACE(REPLACE(REPLACE(F, ',', '{}'), '}{', ''), '{}', ',') AS F
FROM recursion
WHERE CharID = @count
) a
),
final ( ID, Number, rght, idx )
AS ( SELECT t.ID ,
LEFT(t.F, CHARINDEX(',', t.F) - 1) ,
SUBSTRING(t.F, CHARINDEX(',', t.F) + 1, LEN(t.F)) ,
0
FROM commastrings t
UNION ALL
SELECT c.id ,
CASE WHEN CHARINDEX(',', c.rght) = 0 THEN c.rght
ELSE LEFT(c.rght, CHARINDEX(',', c.rght) - 1)
END ,
CASE WHEN CHARINDEX(',', c.rght) > 0
THEN SUBSTRING(c.rght, CHARINDEX(',', c.rght) + 1, DATALENGTH(c.rght))
ELSE ''
END ,
idx + 1
FROM final c
WHERE LENGTH(c.rght) > 0
)
SELECT DISTINCT
ID ,
Number
FROM final
WHERE idx <> 0
AND CAST(Number AS DECIMAL(20, 10)) > 1000
你知道如何使用.Net编写正则表达式吗?我认为CLR用户定义函数是实现这一点的方法。我只需要使用SQL server。。project requirement.CLR函数是SQL Server的一部分。这是一些疯狂的需求
Col1 Col2
----------- ---------
4686 4684
4686 4685
4687 4681
4687 4684
4717 4711
4717 4712
4717 4713
4717 4714
4717 4715
4717 4716
4719 4715
4719 4716
4787 4780
4787 4781
4787 4782
4787 4783
4787 4784
4787 4785
DECLARE @t TABLE ( ID INT, F NVARCHAR(MAX) )
INSERT INTO @t
VALUES ( 4686, '4686 = 4684 - 4685' ),
( 4687, '4687 = ( 4681 / 1.205 / 4684 * 1000 )' ),
( 4717, '4717 = ( 4711 + 4712 + 4713 + 4714 + 4715 + 4716 )/6' ),
( 4719, '4719 = abs( 4716 - 4715 ) ' ),
( 4787,
'4787 = max(max(max(max(max( 4780 , 4781 ), 4782 ), 4783 ), 4784 ), 4785 ) - min(min(min(min(min( 4780 , 4781 ), 4782 ), 4783 ), 4784 ), 4785 )' )
DECLARE @chars TABLE ( ID INT, c NVARCHAR(MAX) )
INSERT INTO @chars
VALUES ( 1, ' ' ),
( 2, '(' ),
( 3, ')' ),
( 4, '/' ),
( 5, '*' ),
( 6, '+' ),
( 7, '-' ),
( 8, 'max' ),
( 9, 'min' ),
( 10, 'abs' ),
( 11, '=' )
DECLARE @count INT
SELECT @count = COUNT(*) FROM @chars;
WITH recursion
AS ( SELECT t.ID ,
REPLACE(F, ' ', ',') + ',' AS F ,
1 AS CharID
FROM @t t
UNION ALL
SELECT t.ID ,
REPLACE(t.F, c.c, ',') AS F ,
t.CharID + 1 AS CharID
FROM recursion t
JOIN @chars c ON c.ID = t.CharID + 1
WHERE t.CharID < @count
),
commastrings
AS ( SELECT ID ,
STUFF(F, LEN(F), 1, '') AS F
FROM ( SELECT ID ,
REPLACE(REPLACE(REPLACE(F, ',', '{}'), '}{', ''), '{}', ',') AS F
FROM recursion
WHERE CharID = @count
) a
),
final ( ID, Number, rght, idx )
AS ( SELECT t.ID ,
LEFT(t.F, CHARINDEX(',', t.F) - 1) ,
SUBSTRING(t.F, CHARINDEX(',', t.F) + 1, LEN(t.F)) ,
0
FROM commastrings t
UNION ALL
SELECT c.id ,
CASE WHEN CHARINDEX(',', c.rght) = 0 THEN c.rght
ELSE LEFT(c.rght, CHARINDEX(',', c.rght) - 1)
END ,
CASE WHEN CHARINDEX(',', c.rght) > 0
THEN SUBSTRING(c.rght, CHARINDEX(',', c.rght) + 1, DATALENGTH(c.rght))
ELSE ''
END ,
idx + 1
FROM final c
WHERE LENGTH(c.rght) > 0
)
SELECT DISTINCT
ID ,
Number
FROM final
WHERE idx <> 0
AND CAST(Number AS DECIMAL(20, 10)) > 1000