SQL用于JSON转换问题

我试图运行以下查询，从示例数据库中的客户记录构建JSON字符串

SELECT
    CustomerID, 
    CustomerName,
    PersonID AS [CustomerContact.PersonID],
    SUBSTRING(FullName, 0, CHARINDEX(' ', FullName)) AS [CustomerContact.FirstName],
    SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName)) AS [CustomerContact.LastName],
    EmailAddress AS [CustomerContact.Email],
    DeliveryAddressLine1 AS [CustomerContact.Address1],
    DeliveryAddressLine2 AS [CustomerContact.Address2],
    CityName AS [CustomerContact.City],
    StateProvinceName AS [CustomerContact.State],
    DeliveryPostalCode AS [CustomerContact.Zip],
    CustomerCategoryName AS CustomerType,
    WebsiteURL As Website
FROM
    Sales.Customers
    LEFT JOIN Sales.CustomerCategories 
    ON Customers.CustomerCategoryID = CustomerCategories.CustomerCategoryID
    LEFT JOIN Application.Cities
    ON Customers.DeliveryCityID = Cities.CityID
    LEFT JOIN Application.StateProvinces
    ON Cities.StateProvinceID = StateProvinces.StateProvinceCode
    LEFT JOIN Application.People
    ON Customers.CustomerID = People.PersonID
WHERE
    Customers.CustomerID = 200
FOR JSON PATH

当我尝试此操作时，它只会抛出以下错误：

Conversion failed when converting the ****** value '******' to data type ******.

有人知道这是什么意思吗

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编辑：***按字面意思显示为星号，而不是隐藏值。行错误是

Msg 245，级别16，状态1，行1

首先想到的是这行：

ON Cities.StateProvinceID = StateProvinces.StateProvinceCode 

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您是想用代码连接ID吗？

在本例中，这可能意味着您试图用不同的类型将两列等同起来。你能分享一下******是什么吗？如果它给你一个行号的话？首先想到的是这一行：ON Cities.StateProvinceID=StateProvinceID=StateProvinceCode-你是想把ID和代码连接起来吗？这实际上修复了它，它生成了JSON字符串，但它…很时髦。这不是我所期望的。@Simon对我有用，如果你想正式回答，我可以把你标记为解决问题的人。