在SQL中添加XML模式引用

如果可以在XML的根目录中添加对模式的直接引用，我一生都找不到

这是我的密码：

Declare @Employee table (EmployeeID int,First_Name varchar(50),Last_Name varchar(50))
    Insert into @Employee values
    (1,'John','Smith'),
    (2,'Jane','Doe'  )


    Select (Select CreatedBy='My Organization',CreateDate=GetDate() For XML Path('RecordHeader'),Type ) 
          ,(Select * From @Employee For XML Path('Employee'),Type ) 
    For XML Path ('Employees'),Type

这将产生以下结果：

<Employees>
  <RecordHeader>
    <CreatedBy>My Organization</CreatedBy>
    <CreateDate>2016-10-18T16:09:48.110</CreateDate>
  </RecordHeader>
  <Employee>
    <EmployeeID>1</EmployeeID>
    <First_Name>John</First_Name>
    <Last_Name>Smith</Last_Name>
  </Employee>
  <Employee>
    <EmployeeID>2</EmployeeID>
    <First_Name>Jane</First_Name>
    <Last_Name>Doe</Last_Name>
  </Employee>
</Employees>

我的组织
2016-10-18T16:09:48.110
1.
约翰
史密斯
2.
简
雌鹿

是否有一种方法可以在my SQL中添加part，使根标记包含以下内容：

<Employees xmlns="https://www.blahblah.org/blahblah/BlahSchema.xsd">

谢谢你的帮助

您可以使用关键字，但这会将名称空间添加到所有节点：

Declare @Employee table (EmployeeID int,First_Name varchar(50),Last_Name varchar(50))
Insert into @Employee values
(1,'John','Smith'),
(2,'Jane','Doe'  );


WITH XMLNAMESPACES (DEFAULT 'https://www.blahblah.org/blahblah/BlahSchema.xsd')
Select (Select CreatedBy='My Organization',CreateDate=GetDate() For XML Path('RecordHeader'),Type ) 
      ,(Select * From @Employee For XML Path('Employee'),Type ) 
For XML Path ('Employees'),Type

结果:

<Employees xmlns="https://www.blahblah.org/blahblah/BlahSchema.xsd">
  <RecordHeader xmlns="https://www.blahblah.org/blahblah/BlahSchema.xsd">
    <CreatedBy>My Organization</CreatedBy>
    <CreateDate>2017-01-10T16:36:23.450</CreateDate>
  </RecordHeader>
  <Employee xmlns="https://www.blahblah.org/blahblah/BlahSchema.xsd">
    <EmployeeID>1</EmployeeID>
    <First_Name>John</First_Name>
    <Last_Name>Smith</Last_Name>
  </Employee>
  <Employee xmlns="https://www.blahblah.org/blahblah/BlahSchema.xsd">
    <EmployeeID>2</EmployeeID>
    <First_Name>Jane</First_Name>
    <Last_Name>Doe</Last_Name>
  </Employee>
</Employees>

我的组织
2017-01-10T16:36:23.450
1.
约翰
史密斯
2.
简
雌鹿

在使用xmlns时总是遇到问题，所以我使用了一些技巧

Declare @Employee table (EmployeeID int,First_Name varchar(50),Last_Name varchar(50))
Insert into @Employee values
(1,'John','Smith'),
(2,'Jane','Doe'  )

Declare @XML xml = (
Select (Select CreatedBy='My Organization',CreateDate=GetDate() For XML Path('RecordHeader'),Type ) 
      ,(Select * From @Employee For XML Path('Employee'),Type ) 
For XML Path ('Employees'),Type
)

set @XML.modify('insert ( attribute MyNameSpace {"https://www.blahblah.org/blahblah/BlahSchema.xsd"}) into (/Employees)[1]')
set @XML = replace(cast(@XML as nvarchar(max)),'[MyNameSpace]','xmlns')

Select @XML

返回

<Employees xmlns="https://www.blahblah.org/blahblah/BlahSchema.xsd">
  <RecordHeader>
    <CreatedBy>My Organization</CreatedBy>
    <CreateDate>2017-01-10T15:19:42.873</CreateDate>
  </RecordHeader>
  <Employee>
    <EmployeeID>1</EmployeeID>
    <First_Name>John</First_Name>
    <Last_Name>Smith</Last_Name>
  </Employee>
  <Employee>
    <EmployeeID>2</EmployeeID>
    <First_Name>Jane</First_Name>
    <Last_Name>Doe</Last_Name>
  </Employee>
</Employees>

---

这看起来很有希望，但它似乎将其添加到每个父标记而不是根标记中。Tks！谢谢你，约翰！你照常过来@我也不知道直接的方法+从我这边。一个小提示：最好转换为

NVARCHAR（MAX）

，因为XML是16位内部编码的，除了性能之外，VARCHAR可能会弄乱一些特殊字符。。。还有一个想法：使用

东西

在字符串基础上用

替换开头的

可能更容易…@johncapelletti，我不知道，这看起来很傻。。。我的假设是，在内部，XML的处理方式与从OPENXML调用

（或从超重量级函数调用
的结果非常相似。更改默认名称空间可能会产生很高且不可预测的影响…@ssokol91请参阅更新/编辑。默认情况下，空值将被忽略，因此可以通过NullIf（）为空值设置空值
Declare @Employee table (EmployeeID int,First_Name varchar(50),Last_Name varchar(50))
Insert into @Employee values
(1,'John','Smith'),
(2,'Jane','Doe'  ),
(3,'Betty',null  ),  -- No element for Last_Name
(4,'Susan',''  )     -- No element for Last_Name

Declare @XML xml = (
Select (Select CreatedBy='My Organization',CreateDate=GetDate() For XML Path('RecordHeader'),Type ) 
      ,(Select EmployeeID = NullIf(EmployeeID,'') 
              ,First_Name = NullIf(First_Name,'')
              ,Last_Name  = NullIf(Last_Name,'')
         From  @Employee For XML Path('Employee'),Type ) 
For XML Path ('Employees'),Type
)

set @XML.modify('insert ( attribute MyNameSpace {"https://www.blahblah.org/blahblah/BlahSchema.xsd"}) into (/Employees)[1]')
set @XML = replace(cast(@XML as nvarchar(max)),'[MyNameSpace]','xmlns')

Select @XML