如何生成此sql查询？

0是VisitingCount--数值Datepart，例如：00:00-1、00:30-2、01:00-2、01:30-3

我的查询返回到下表

0   1

0   2

..(removed repeating)..

0   45

0   46

0   47

825 23

526 21

1064    24

885 22

这是我梦寐以求的桌子。我需要这个：

将订单按2描述添加到您的选择中

  select Sum(VisitingCount), [Time]
  from #Temp group by [Time]
Union All
  select count(page) as VisitingCount, 
  (datepart(hour,Date)*60+datepart(minute,Date))/30 as [Time]
  from scr_SecuristLog
  where Date between '2009-05-04 10:30' and '2009-05-04 12:30'
  GROUP BY (datepart(hour,Date)*60+datepart(minute,Date))/30--scr
order by 2 desc

请参见from

中的示例A，将订单按2个描述添加到您的选择中

  select Sum(VisitingCount), [Time]
  from #Temp group by [Time]
Union All
  select count(page) as VisitingCount, 
  (datepart(hour,Date)*60+datepart(minute,Date))/30 as [Time]
  from scr_SecuristLog
  where Date between '2009-05-04 10:30' and '2009-05-04 12:30'
  GROUP BY (datepart(hour,Date)*60+datepart(minute,Date))/30--scr
order by 2 desc

---

参见from中的示例A，而不是按dateparthour、Date*60+datepartminute、Date/30分组；如何按[时间]更改组然而，您的查询并不完全准确。哦-它应该是升序的吗？我总是忘记、猜测和编辑：不，我想在这个问题中添加评论部分，但是；我添加了一个新的外观，而不是按dateparthour、Date*60+datepartminute、Date/30分组；如何按[时间]更改组然而，您的查询并不完全准确。哦-它应该是升序的吗？我总是忘记、猜测和编辑：不，我想在这个问题中添加评论部分，但是；我加了一个新的看看好吗？

  select Sum(VisitingCount), [Time]
  from #Temp group by [Time]
Union All
  select count(page) as VisitingCount, 
  (datepart(hour,Date)*60+datepart(minute,Date))/30 as [Time]
  from scr_SecuristLog
  where Date between '2009-05-04 10:30' and '2009-05-04 12:30'
  GROUP BY (datepart(hour,Date)*60+datepart(minute,Date))/30--scr
order by 2 desc