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Sql 在Oracle中获取给定日期的最新条目_Sql_Oracle_Greatest N Per Group_Sysdate - Fatal编程技术网

Sql 在Oracle中获取给定日期的最新条目

Sql 在Oracle中获取给定日期的最新条目,sql,oracle,greatest-n-per-group,sysdate,Sql,Oracle,Greatest N Per Group,Sysdate,我想选择 data12 [last entry for 12-21-2014], data11 [last entry for 12-20-2014], data8 [last entry for 12-19-2014] 从下表中选择 snapshot_datestamp data ------------------------------- 12-21-2014 08:24:21 data12 12-20-2014 19:58:49 data11

我想选择

 data12 [last entry for 12-21-2014],
 data11 [last entry for 12-20-2014],
 data8  [last entry for 12-19-2014] 
从下表中选择

   snapshot_datestamp   data
-------------------------------   
 12-21-2014 08:24:21    data12
 12-20-2014 19:58:49    data11
 12-20-2014 19:55:36    data10
 12-20-2014 19:53:59    data9
 12-19-2014 21:56:23    data8
 12-19-2014 21:13:16    data7
 12-19-2014 11:05:45    data6
 12-19-2014 11:05:07    data5
 12-19-2014 10:56:13    data4
 12-19-2014 10:52:21    data3
 12-19-2014 10:50:43    data2
 12-19-2014 10:49:30    data1

不太清楚如何实现这一点。任何指针都会有很大帮助。

简单的方法是使用
orderby
ROWNUM

SELECT *
FROM   (SELECT data
        FROM   tablename
        WHERE  trunc(snapshot_datestamp)  = TO_DATE('12-21-2014','MM-DD-YYYY')
        ORDER  BY snapshot_datestamp DESC)
WHERE  ROWNUM = 1; 

简单的方法是使用
orderby
ROWNUM

SELECT *
FROM   (SELECT data
        FROM   tablename
        WHERE  trunc(snapshot_datestamp)  = TO_DATE('12-21-2014','MM-DD-YYYY')
        ORDER  BY snapshot_datestamp DESC)
WHERE  ROWNUM = 1; 

简单的方法是使用
orderby
ROWNUM

SELECT *
FROM   (SELECT data
        FROM   tablename
        WHERE  trunc(snapshot_datestamp)  = TO_DATE('12-21-2014','MM-DD-YYYY')
        ORDER  BY snapshot_datestamp DESC)
WHERE  ROWNUM = 1; 

简单的方法是使用
orderby
ROWNUM

SELECT *
FROM   (SELECT data
        FROM   tablename
        WHERE  trunc(snapshot_datestamp)  = TO_DATE('12-21-2014','MM-DD-YYYY')
        ORDER  BY snapshot_datestamp DESC)
WHERE  ROWNUM = 1; 

一种方法是获取每天的最新时间,然后选择相应的记录:

select
  trunc(snapshot_datestamp),
  data
from mytable
where snapshot_datestamp in
(
  select max(snapshot_datestamp)
  from mytable
  group by trunc(snapshot_datestamp)
)
order by trunc(snapshot_datestamp);
另一种是使用分析函数:

select 
  trunc(snapshot_datestamp),
  max(data) keep (dense_rank last order by snapshot_datestamp)
from mytable
group by trunc(snapshot_datestamp)
order by trunc(snapshot_datestamp);

一种方法是获取每天的最新时间,然后选择相应的记录:

select
  trunc(snapshot_datestamp),
  data
from mytable
where snapshot_datestamp in
(
  select max(snapshot_datestamp)
  from mytable
  group by trunc(snapshot_datestamp)
)
order by trunc(snapshot_datestamp);
另一种是使用分析函数:

select 
  trunc(snapshot_datestamp),
  max(data) keep (dense_rank last order by snapshot_datestamp)
from mytable
group by trunc(snapshot_datestamp)
order by trunc(snapshot_datestamp);

一种方法是获取每天的最新时间,然后选择相应的记录:

select
  trunc(snapshot_datestamp),
  data
from mytable
where snapshot_datestamp in
(
  select max(snapshot_datestamp)
  from mytable
  group by trunc(snapshot_datestamp)
)
order by trunc(snapshot_datestamp);
另一种是使用分析函数:

select 
  trunc(snapshot_datestamp),
  max(data) keep (dense_rank last order by snapshot_datestamp)
from mytable
group by trunc(snapshot_datestamp)
order by trunc(snapshot_datestamp);

一种方法是获取每天的最新时间,然后选择相应的记录:

select
  trunc(snapshot_datestamp),
  data
from mytable
where snapshot_datestamp in
(
  select max(snapshot_datestamp)
  from mytable
  group by trunc(snapshot_datestamp)
)
order by trunc(snapshot_datestamp);
另一种是使用分析函数:

select 
  trunc(snapshot_datestamp),
  max(data) keep (dense_rank last order by snapshot_datestamp)
from mytable
group by trunc(snapshot_datestamp)
order by trunc(snapshot_datestamp);

假设我们在这里使用的数据中没有任何键,那么使用可能是一种解决方案:

SELECT "snapshot_datestamp", "data" FROM
(

    SELECT "snapshot_datestamp", "data",
           ROW_NUMBER() 
            OVER (PARTITION BY TRUNC("snapshot_datestamp")
                  ORDER BY "snapshot_datestamp" DESC) rn
    FROM T
) V
WHERE rn = 1
ORDER BY 1 DESC
这里的想法是为给定日期的每一行编号(根据“时间戳”按降序排列)。一旦完成,每个分区的“最后一个”条目就是该分区中编号为1的行


请参见

假设我们在此处使用的数据中没有任何键,使用可能是一种解决方案:

SELECT "snapshot_datestamp", "data" FROM
(

    SELECT "snapshot_datestamp", "data",
           ROW_NUMBER() 
            OVER (PARTITION BY TRUNC("snapshot_datestamp")
                  ORDER BY "snapshot_datestamp" DESC) rn
    FROM T
) V
WHERE rn = 1
ORDER BY 1 DESC
这里的想法是为给定日期的每一行编号(根据“时间戳”按降序排列)。一旦完成,每个分区的“最后一个”条目就是该分区中编号为1的行


请参见

假设我们在此处使用的数据中没有任何键,使用可能是一种解决方案:

SELECT "snapshot_datestamp", "data" FROM
(

    SELECT "snapshot_datestamp", "data",
           ROW_NUMBER() 
            OVER (PARTITION BY TRUNC("snapshot_datestamp")
                  ORDER BY "snapshot_datestamp" DESC) rn
    FROM T
) V
WHERE rn = 1
ORDER BY 1 DESC
这里的想法是为给定日期的每一行编号(根据“时间戳”按降序排列)。一旦完成,每个分区的“最后一个”条目就是该分区中编号为1的行


请参见

假设我们在此处使用的数据中没有任何键,使用可能是一种解决方案:

SELECT "snapshot_datestamp", "data" FROM
(

    SELECT "snapshot_datestamp", "data",
           ROW_NUMBER() 
            OVER (PARTITION BY TRUNC("snapshot_datestamp")
                  ORDER BY "snapshot_datestamp" DESC) rn
    FROM T
) V
WHERE rn = 1
ORDER BY 1 DESC
这里的想法是为给定日期的每一行编号(根据“时间戳”按降序排列)。一旦完成,每个分区的“最后一个”条目就是该分区中编号为1的行


请参见

您使用的是哪个
DBMS
using@Soumya这里发布的所有答案都是绝对正确的,您的问题以多种方式得到解决您可以选择任何一种…您是
DBMS
using@Soumya这里所有的答案都是绝对正确的,你的问题以多种方式解决,你可以选择任何一种…您是哪个
DBMS
using@Soumya这里发布的所有答案都是绝对正确的,您的问题以多种方式得到解决您可以选择任何一种…您是
DBMS
using@Soumya这里所有的答案都是绝对正确的,你的问题以多种方式解决,你可以选择任何一种。。。