SQL查询创建跨列

我有这张桌子

customer |  product | quantity
-------------------------------
CLI01    | A        | 10
CLI01    | B        | 20
CLI02    | A        | 31
CLI03    | A        | 10
CLI03    | C        | 12

我想在SQL Server中创建以下输出：

customer | crossProduct | quantity
-----------------------------------
CLI01    | A+B          | 30
CLI02    | Only A       | 31
CLI03    | B+C          | 22

提前谢谢

---

Niko

如果您只关心两种产品，那么这就是简单的聚合：

select customer,
       (case when count(distinct product) > 2 then 'Lots of Products'
             when min(product) = max(product) then 'Only ' + min(product)
             else min(product) + '+' + max(product)
        end) as crossproduct,
       sum(quantity)
from t
group by customer;

如果您关心两个以上的产品，则需要进行聚合字符串连接。这在SQLServer中有点痛苦。首先通过谷歌搜索“sql server聚合字符串连接”。

这是s的示例：

----- Test Data ----------
DECLARE @TestData TABLE (customer VARCHAR(10),product VARCHAR(10),quantity INT)
INSERT INTO @TestData
SELECT 'CLI01','A',10 UNION ALL
SELECT 'CLI01','B',20 UNION ALL
SELECT 'CLI02','A',31 UNION ALL
SELECT 'CLI03','A',10 UNION ALL
SELECT 'CLI03 ','C',12
-----  Query -------------
SELECT customer,CASE WHEN COUNT( DISTINCT t.product)=1 THEN 'Only ' ELSE '' END + LEFT(c.product,LEN(c.product)-1) AS Product,SUM(quantity) AS quantity 
FROM @TestData AS t
CROSS APPLY(SELECT a.product+'+' FROM @TestData AS a WHERE a.customer=t.customer FOR XML PATH('')) c(product)
GROUP BY customer,c.product
ORDER BY t.customer

客户产品数量 CLI01 A+B 30 CLI02只有一个31 CLI03 A+C 22

---

你试过使用这些东西吗？这会给你你所需要的。从sql 2008开始，可以根据需要使用任意多的产品

CREATE TABLE x (customer VARCHAR (20), product CHAR(1), quantity INT )
INSERT INTO x
  VALUES( 'CLI01', 'A', 10),
        ( 'CLI01', 'B', 20),
        ( 'CLI02', 'A', 31),
        ( 'CLI03', 'A', 10),
        ( 'CLI03', 'C', 12)

SELECT  x1.customer, x3.Products, SUM(x1.quantity)
FROM    x x1
        CROSS APPLY ( SELECT  Products = STUFF( (select '+' + product AS [text()]
                      FROM    x  x2
                      WHERE   x2.customer = x1.customer
                      FOR XML PATH ('') ), 1, 1,'') ) x3
GROUP BY x1.customer, x3.Products

---

是否每两个以上的产品？应该是“谢谢你们”的动态复制品。史蒂夫，你怀疑它是完美的。我已经在交叉应用中添加了2个不同的。对不起，Steve，但是如果我想设置“+”？

CREATE TABLE x (customer VARCHAR (20), product CHAR(1), quantity INT )
INSERT INTO x
  VALUES( 'CLI01', 'A', 10),
        ( 'CLI01', 'B', 20),
        ( 'CLI02', 'A', 31),
        ( 'CLI03', 'A', 10),
        ( 'CLI03', 'C', 12)

SELECT  x1.customer, x3.Products, SUM(x1.quantity)
FROM    x x1
        CROSS APPLY ( SELECT  Products = STUFF( (select '+' + product AS [text()]
                      FROM    x  x2
                      WHERE   x2.customer = x1.customer
                      FOR XML PATH ('') ), 1, 1,'') ) x3
GROUP BY x1.customer, x3.Products