Oracle SQL Pivot多列

我有一个数据集，其中1个许可证ID被拆分为多行。我想合并这些行，这样我就有了每人1行的ID和许可证ID的组合

以下是我的数据的格式：

SELECT '123456789' AS PERSON_ID, '1' AS LICENSE_ID, 'NUMBER' AS FIELD, '123' AS EXPECTED, '124' AS ACTUAL, 'UPDATE' AS ACTION FROM DUAL UNION ALL
SELECT '123456789' AS PERSON_ID, '1' AS LICENSE_ID, 'ISSUE_DT' AS FIELD, '43498' AS EXPECTED, '43498' AS ACTUAL, 'NA' AS ACTION FROM DUAL UNION ALL
SELECT '123456789' AS PERSON_ID, '2' AS LICENSE_ID, 'NUMBER' AS FIELD, '888' AS EXPECTED, '888' AS ACTUAL, 'NA' AS ACTION FROM DUAL UNION ALL
SELECT '123456789' AS PERSON_ID, '2' AS LICENSE_ID, 'ISSUE_DT' AS FIELD, '43498' AS EXPECTED, '' AS ACTUAL, 'UPDATE' AS ACTION FROM DUAL

该表如下所示：

我需要的输出如下：

---

您可以使用条件聚合：

select person_id, licence_id,
       max(case when field = 'NUMBER' then expected end) as expected_number,
       max(case when field = 'NUMBER' then actual end) as actual_number,
       max(case when field = 'NUMBER' then actual end) as actual_number,
       max(case when field = 'ISSUE_DT' then expected end) as expected_issue_dt,
       max(case when field = 'ISSUE_DT' then actual end) as actual_issue_dt,
       max(case when field = 'ISSUE_DT' then action end) as actual_issue_dt_action,
from t
group by person_id, licence_id