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Sql ORA-00905在case语句中缺少关键字..尽管语法正确_Sql_Case - Fatal编程技术网

Sql ORA-00905在case语句中缺少关键字..尽管语法正确

Sql ORA-00905在case语句中缺少关键字..尽管语法正确,sql,case,Sql,Case,我得到查询中缺少的关键字错误ORA-00905 SELECT '01_AMT' AS FIELD, COUNT((NVL(AMT,0)) AS CNT FROM TBL1 UNION ALL SELECT CASE WHEN AMT IS NULL THEN 'NULL' WHEN AMT<10000 THEN '<10000' WHEN AMT>= 10000 and AMT<=59999 THEN '10,000-59,999’ ELSE '60,

我得到查询中缺少的关键字错误ORA-00905

SELECT '01_AMT' AS FIELD, COUNT((NVL(AMT,0)) AS CNT FROM  TBL1

UNION ALL

SELECT 

CASE 
WHEN  AMT IS NULL THEN 'NULL'

WHEN AMT<10000 THEN '<10000'

WHEN AMT>= 10000 and AMT<=59999 THEN '10,000-59,999’

ELSE '60,000up' END,


COUNT (1) CNT FROM TBL1

GROUP BY CASE

WHEN  AMT IS NULL THEN 'NULL'

WHEN AMT<10000 THEN '<10000'

WHEN AMT>= 10000 and AMT<=59999 THEN '10,000-59,999’

ELSE '60,000up' END
输出:

场碳纳米管

01_金额100000

10000-59999 50000

600000升50000


第一个字段“01 Amt”应包含第二行的总计数和其他计数的细分。Amt是数字数据类型。

您使用的不是标准收盘勾号,而是卷曲的勾号。甲骨文不理解它,它忽略了句子的其余部分。更正:

SELECT '01_AMT' AS FIELD, COUNT((NVL(AMT,0)) AS CNT FROM  TBL1

UNION ALL

SELECT 

CASE 
WHEN  AMT IS NULL THEN 'NULL'

WHEN AMT<10000 THEN '<10000'

WHEN AMT>= 10000 and AMT<=59999 THEN '10,000-59,999' <= CHANGED THIS TICK!

ELSE '60,000up' END,


COUNT (1) CNT FROM TBL1

GROUP BY CASE

WHEN  AMT IS NULL THEN 'NULL'

WHEN AMT<10000 THEN '<10000'

WHEN AMT>= 10000 and AMT<=59999 THEN '10,000-59,999' <= CHANGED THIS TICK!

ELSE '60,000up' END

这应该会有帮助:这个999“应该是999”我的问题已通过更改的勾号解决。请告诉我它在键盘上的位置。我使用了“回车”按钮旁边的一个。但在键盘上找不到类似的。Microsoft Word会自动将正常的勾号更改为卷曲的勾号。如果您在word、outlook中键入了部分内容,或者从其他人处收到的内容超出了应更改的内容。大多数普通键盘上都不存在卷曲的刻度。