Sql 如何改进GROUPBY子句

Sql 如何改进GROUPBY子句,sql,sql-server,Sql,Sql Server,我正在尝试使用以下SQL生成报告: DECLARE @TOTALTRANS int SET @TOTALTRANS = (SELECT count(*) FROM log_table where answear is not null) SELECT answear = ISNULL(answear,'Totalization') , COUNT(*) as Qtd, CASE @TOTALTRANS WHEN 0 THEN '0%' ELSE CONCAT(CAST((

我正在尝试使用以下SQL生成报告:

DECLARE @TOTALTRANS int
SET @TOTALTRANS = (SELECT count(*) FROM log_table where answear is not null) 

SELECT  
answear = ISNULL(answear,'Totalization') ,
COUNT(*) as Qtd,
CASE @TOTALTRANS
    WHEN 0 THEN '0%'
    ELSE CONCAT(CAST(((count(*) * 100.0 / @TOTALTRANS)) as decimal(5,2)), ' % ')
END as Porcent
FROM log_table 
WHERE answear is not null
GROUP BY answear WITH ROLLUP 
我得到了以下结果:

APPROVED 111111 1   0.58 % 
APPROVED 444444 164 95.91 % 
APPROVED 222222 1   0.58 % 
APPROVED 333333 1   0.58 % 
CANCELLED       4   2.34 % 
Totalization  171   100.00 % 
但我想得到这个结果:

APPROVED        167 97.66 % 
CANCELLED         4  2.34 % 
Totalization    171 100.00 % 
怎么做?
甚至改进也是受欢迎的……我也在想,也许可以使用union来实现这一点……

理想情况下,您应该将数据标准化,以划分为“已批准”和“111111”。如果做不到这一点,像这样的事情应该会让你接近:

DECLARE @TOTALTRANS int
SET @TOTALTRANS = (SELECT count(*) FROM log_table where answear is not null) 

;WITH CleanedUp AS (
  SELECT
    CASE 
      WHEN Answear LIKE 'APPROVED %' THEN 'APPROVED'
      ELSE Answear
    END as Answear
  FROM Log_Table
) 
SELECT
   answear = ISNULL(answear,'Totalization') ,
   COUNT(*) as Qtd,
   CASE @TOTALTRANS
      WHEN 0 THEN '0%'
      ELSE CONCAT(CAST(((count(*) * 100.0 / @TOTALTRANS)) as decimal(5,2)), ' % ')
END as Porcent
FROM CleanedUp
WHERE answear is not null
GROUP BY answear WITH ROLLUP 

看起来您只需要
分组依据的第一个空格内的任何内容

SELECT (CASE WHEN answear IS NULL THEN 'Totalization'
             ELSE LEFT(answear, CHARINDEX(' ', answear) - 1)
        END) as Answear,
       COUNT(*) as Qtd,
       (CASE @TOTALTRANS
          WHEN 0 THEN '0%'
          ELSE CONCAT(CAST(((count(*) * 100.0 / @TOTALTRANS)) as decimal(5,2)), ' % ')
        END) as Porcent
FROM log_table 
WHERE answear is not null
GROUP BY LEFT(answear, CHARINDEX(' ', answear) - 1) WITH ROLLUP ;

此版本假定answear“APPROVED 111111”中有一个空格-此值是否来自一列?是,APPROVED+授权编号。