Sql 如何从表中获取最新的“n”更新行

可能重复：

我有一个表abc，其中有以下列

行为id、客户id、上次更新日期、客户活动。其中act_id是主键

LastUpdateDate存储为该客户完成的最后一项活动

我试图根据LastUpdateDate获取给定custid的最新10行

我怎样才能做到这一点

-vivek

Oracle支持和窗口功能。试试下面的方法

SELECT act_id, cust_id, lastUpdatedDate, custActivity
FROM
(
    SELECT  act_id, cust_id, lastUpdatedDate, custActivity,
            ROW_NUMBER() OVER (PARTITION BY cust_id ORDER BY lastUpdatedDate DESC) rn
    FROM tableNAME
) x
WHERE rn <= 10

Oracle支持Windows和Windows功能。试试下面的方法

SELECT act_id, cust_id, lastUpdatedDate, custActivity
FROM
(
    SELECT  act_id, cust_id, lastUpdatedDate, custActivity,
            ROW_NUMBER() OVER (PARTITION BY cust_id ORDER BY lastUpdatedDate DESC) rn
    FROM tableNAME
) x
WHERE rn <= 10

您可以在Oracle中使用ROWNUM。。单击此处查看文档

select *
from  
   ( select * 
     from your_table 
     where cust_id=<given cust_id>
     order by lastUpdatedDate desc ) 
where ROWNUM <= 10;

您可以在Oracle中使用ROWNUM。。单击此处查看文档

select *
from  
   ( select * 
     from your_table 
     where cust_id=<given cust_id>
     order by lastUpdatedDate desc ) 
where ROWNUM <= 10;

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希望这对你有所帮助-

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希望这对你有所帮助-