如何使用SQL SELECT根据另一个表中的特定行查询表

有一个包含多个团队数据的表，如下所示：

original_dates:

   date    |   team_id   |  value
---------------------------------
2019-01-01 |      1      |    13
2019-01-01 |      2      |    88
2019-01-02 |      1      |    17
2019-01-02 |      2      |    99  
2019-01-03 |      1      |    26  
2019-01-03 |      2      |    105
2019-01-04 |      1      |    49
2019-01-04 |      2      |    134
2019-01-04 |      1      |    56
2019-01-04 |      2      |    167

但是，在某个日期，我们希望将该日期的值重置为0，将该ID的所有先前日期设置为0，然后从所有后续日期中减去该值，最小值为0。以下是需要重置的日期表：

inflection_dates:

   date    |   team_id   |  value
-----------------------------------
2019-01-02 |      2      |    99
2019-01-03 |      1      |    26

这是我希望得到的结果表：

result:

   date    |   team_id   |  value
---------------------------------
2019-01-01 |      1      |    0    
2019-01-01 |      2      |    0     
2019-01-02 |      1      |    0     
2019-01-02 |      2      |    0    <- row in inflection_dates (value was 99)
2019-01-03 |      1      |    0    <- row in inflection_dates (value was 26)
2019-01-03 |      2      |    6     (-99)
2019-01-04 |      1      |    23    (-26)
2019-01-04 |      2      |    35    (-99)
2019-01-04 |      1      |    30    (-26)
2019-01-04 |      2      |    68    (-99)

唯一的限制是所有表都是只读的，所以我只能查询它们，不能修改它们

有人知道这是否可能吗

试试这个：

 drop table #tmp
---------------------------------
select '2019-01-01' as date, 1 as team_id, 13 as value into #tmp
union select '2019-01-01', 2, 88
union select '2019-01-02', 1, 17
union select '2019-01-02', 2, 99  
union select '2019-01-03', 1, 26  
union select '2019-01-03', 2, 105
union select '2019-01-04', 1, 49
union select '2019-01-04', 2, 134
union select '2019-01-04', 1, 56
union select '2019-01-04', 2, 167

 drop table #tmpinflection
---------------------------------
select '2019-01-02' as date, 2 as team_id, 99 as value  into #tmpinflection
union select '2019-01-03', 1, 26 


select a.date, a.team_id, 
case when a.date <= b.date then 0 
else a.value - b.value end as value
 from #tmp a left join #tmpinflection b on a.team_id = b.team_id where b.date is not null

试试这个：

 drop table #tmp
---------------------------------
select '2019-01-01' as date, 1 as team_id, 13 as value into #tmp
union select '2019-01-01', 2, 88
union select '2019-01-02', 1, 17
union select '2019-01-02', 2, 99  
union select '2019-01-03', 1, 26  
union select '2019-01-03', 2, 105
union select '2019-01-04', 1, 49
union select '2019-01-04', 2, 134
union select '2019-01-04', 1, 56
union select '2019-01-04', 2, 167

 drop table #tmpinflection
---------------------------------
select '2019-01-02' as date, 2 as team_id, 99 as value  into #tmpinflection
union select '2019-01-03', 1, 26 


select a.date, a.team_id, 
case when a.date <= b.date then 0 
else a.value - b.value end as value
 from #tmp a left join #tmpinflection b on a.team_id = b.team_id where b.date is not null

---

使用表的联接和CASE表达式计算新值：

select o.date, o.team_id,
  case 
    when o.date <= i.date then 0
    else o.value - i.value
  end value
from original_dates o inner join inflection_dates i
on i.team_id = o.team_id

---

使用表的联接和CASE表达式计算新值：

select o.date, o.team_id,
  case 
    when o.date <= i.date then 0
    else o.value - i.value
  end value
from original_dates o inner join inflection_dates i
on i.team_id = o.team_id

---

非常感谢。这帮了大忙谢谢你！这帮了大忙