如何在SQL Server中对字符串中的数值进行排序

输入字符串-

'0|33|6|2|30|12|4|1|8|29|9|34|7|13|11|5|3|31|10|36|37|37|37|38|39|40|44|65|66'

输出字符串-

'0|1|2|3|4|5|6|7|8|9|10|11|12|13|29|30|31|33|34|36|37|37|37|38|39|40|44|65|66'

在SQLServer2008中需要这个

---

我已将|上的值拆分，然后将这些值插入临时表，然后连接该值。有更好的方法吗？

没有解析/拆分功能

Declare @String varchar(max) = '0|33|6|2|30|12|4|1|8|29|9|34|7|13|11|5|3|31|10|36|37|37|37|38|39|40|44|65|66'

Select Sorted = Stuff((Select '|' +RetVal 
                       From (
                              Select RetSeq = Row_Number() over (Order By (Select null))
                                    ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
                                From  (Select x = Cast('<x>'+ replace((Select @String as [*] For XML Path('')),'|','</x><x>')+'</x>' as xml).query('.')) as A 
                                Cross Apply x.nodes('x') AS B(i)
                            ) A
                       Order By cast(RetVal as int) 
                       For XML Path ('')),1,1,'')

0|1|2|3|4|5|6|7|8|9|10|11|12|13|29|30|31|33|34|36|37|37|37|38|39|40|44|65|66

两者都返回

Declare @String varchar(max) = '0|33|6|2|30|12|4|1|8|29|9|34|7|13|11|5|3|31|10|36|37|37|37|38|39|40|44|65|66'

Select Sorted = Stuff((Select '|' +RetVal 
                       From (
                              Select RetSeq = Row_Number() over (Order By (Select null))
                                    ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
                                From  (Select x = Cast('<x>'+ replace((Select @String as [*] For XML Path('')),'|','</x><x>')+'</x>' as xml).query('.')) as A 
                                Cross Apply x.nodes('x') AS B(i)
                            ) A
                       Order By cast(RetVal as int) 
                       For XML Path ('')),1,1,'')

0|1|2|3|4|5|6|7|8|9|10|11|12|13|29|30|31|33|34|36|37|37|37|38|39|40|44|65|66

---

如果需要，UDF

CREATE FUNCTION [dbo].[udf-Str-Parse-8K] (@String varchar(max),@Delimiter varchar(25))
Returns Table 
As
Return (  
    with   cte1(N)   As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
           cte2(N)   As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 a,cte1 b,cte1 c,cte1 d) A ),
           cte3(N)   As (Select 1 Union All Select t.N+DataLength(@Delimiter) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter)) = @Delimiter),
           cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter,@String,s.N),0)-S.N,8000) From cte3 S)

    Select RetSeq = Row_Number() over (Order By A.N)
          ,RetVal = LTrim(RTrim(Substring(@String, A.N, A.L)))
    From   cte4 A
);
--Orginal Source http://www.sqlservercentral.com/articles/Tally+Table/72993/
--Much faster than str-Parse, but limited to 8K
--Select * from [dbo].[udf-Str-Parse-8K]('Dog,Cat,House,Car',',')
--Select * from [dbo].[udf-Str-Parse-8K]('John||Cappelletti||was||here','||')

---

没有解析/拆分功能

Declare @String varchar(max) = '0|33|6|2|30|12|4|1|8|29|9|34|7|13|11|5|3|31|10|36|37|37|37|38|39|40|44|65|66'

Select Sorted = Stuff((Select '|' +RetVal 
                       From (
                              Select RetSeq = Row_Number() over (Order By (Select null))
                                    ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
                                From  (Select x = Cast('<x>'+ replace((Select @String as [*] For XML Path('')),'|','</x><x>')+'</x>' as xml).query('.')) as A 
                                Cross Apply x.nodes('x') AS B(i)
                            ) A
                       Order By cast(RetVal as int) 
                       For XML Path ('')),1,1,'')

0|1|2|3|4|5|6|7|8|9|10|11|12|13|29|30|31|33|34|36|37|37|37|38|39|40|44|65|66

两者都返回

Declare @String varchar(max) = '0|33|6|2|30|12|4|1|8|29|9|34|7|13|11|5|3|31|10|36|37|37|37|38|39|40|44|65|66'

Select Sorted = Stuff((Select '|' +RetVal 
                       From (
                              Select RetSeq = Row_Number() over (Order By (Select null))
                                    ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)')))
                                From  (Select x = Cast('<x>'+ replace((Select @String as [*] For XML Path('')),'|','</x><x>')+'</x>' as xml).query('.')) as A 
                                Cross Apply x.nodes('x') AS B(i)
                            ) A
                       Order By cast(RetVal as int) 
                       For XML Path ('')),1,1,'')

0|1|2|3|4|5|6|7|8|9|10|11|12|13|29|30|31|33|34|36|37|37|37|38|39|40|44|65|66

---

如果需要，UDF

CREATE FUNCTION [dbo].[udf-Str-Parse-8K] (@String varchar(max),@Delimiter varchar(25))
Returns Table 
As
Return (  
    with   cte1(N)   As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
           cte2(N)   As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 a,cte1 b,cte1 c,cte1 d) A ),
           cte3(N)   As (Select 1 Union All Select t.N+DataLength(@Delimiter) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter)) = @Delimiter),
           cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter,@String,s.N),0)-S.N,8000) From cte3 S)

    Select RetSeq = Row_Number() over (Order By A.N)
          ,RetVal = LTrim(RTrim(Substring(@String, A.N, A.L)))
    From   cte4 A
);
--Orginal Source http://www.sqlservercentral.com/articles/Tally+Table/72993/
--Much faster than str-Parse, but limited to 8K
--Select * from [dbo].[udf-Str-Parse-8K]('Dog,Cat,House,Car',',')
--Select * from [dbo].[udf-Str-Parse-8K]('John||Cappelletti||was||here','||')

---

@BeanFrog更新了这个问题。似乎您已经解决了这个问题。CLR func将比关系数据库管理系统做得更好。您为什么要在数据库中这样做？此字符串不能用于其他查询，为什么不在客户端对其进行拆分和排序？@BeanFrog更新了此问题。似乎您已经解决了此问题。CLR func比关系数据库管理系统做得更好。为什么要在数据库中进行此操作？这个字符串不能用于其他查询，所以为什么不在客户端对其进行拆分和排序呢？