Sql 光标的移动？我想是的。仍然可以在两个游标之间进行联接吗？如果是这样的话，语法会是什么样子？从我在文档中看到的情况来看，使用游标的语法与查询表的语法似乎有很大的不同。这就是你要找的吗？因为根据你所说，光标不是适合你的解决方案。不客气。我刚刚添加了一个简短的查

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光标的移动？我想是的。仍然可以在两个游标之间进行联接吗？如果是这样的话，语法会是什么样子？从我在文档中看到的情况来看，使用游标的语法与查询表的语法似乎有很大的不同。这就是你要找的吗？因为根据你所说，光标不是适合你的解决方案。不客气。我刚刚添加了一个简短的查询作为奖励：-）

select distinct cust_num into t1 
from all_visits_x_cust 
where date > '06/02/2015'
and date <= '07/02/2015' 
and cust_num > 9999;

select distinct cust_num into t1_2 
from cc_calls_x_cust 
where date = '06/02/2015' 
and cust_num > 9999);

select count(*) as post_call_visitors 
into v1 
from t1_2 join t1 
on t1.cust_num = t1_2.cust_num);

select count(*) as post_call_visitors 
into temp v1
from (
        select distinct cust_num
        from all_visits_x_cust 
        where date > '06/02/2015'
        and date <= '07/02/2015' 
        and cust_num > 9999
    ) as t1
join (
        select distinct cust_num 
        from cc_calls_x_cust 
        where date = '06/02/2015' 
        and cust_num > 9999
     ) as t1_2
on t1.cust_num = t1_2.cust_num; 

select count(distinct cust_num) as post_call_visitors 
from cc_calls_x_cust 
where date = '06/02/2015' 
and cust_num > 9999
and cust_num in (
        select cust_num 
        from all_visits_x_cust 
        where date > '06/02/2015'
        and date <= '07/02/2015' 
    ); 

with t1 as (
    select distinct cust_num
    from all_visits_x_cust 
    where date > '06/02/2015'
    and date <= '07/02/2015' 
    and cust_num > 9999
    ),
t1_2 as (
    select distinct cust_num into t1_2 
    from cc_calls_x_cust 
    where date = '06/02/2015' 
    and cust_num > 9999
    )
select count(*) as post_call_visitors 
from t1_2 
join t1 
on t1.cust_num = t1_2.cust_num;