Sql 如何根据列'；发生顺序

我需要使用date列提取所有与其各自ID相关联的行，这些行在type列中的“In”出现在“Out”之前。在提供的数据中，只有Id 1和Id 2可以通过测试。 试验数据如下：

CREATE TABLE #Table (
id INT,
[type] varchar(25),
[Dates] Date)

INSERT INTO #Table
VALUES (1, 'In', '2018-10-01'),
 (1, 'In', '2018-11-01'),
 (1, 'Out', '2018-12-01'),
 (2, 'In', '2018-10-01'),
 (2, 'Out', '2018-11-01'),
 (2, 'In', '2018-12-01'),
 (3, 'Out', '2018-10-01'),
 (3, 'In', '2018-11-01')

输出应如下所示：

+----+------+------------+
| id | type |    date    |
+----+------+------------+
|  1 | In   | 2018-10-01 |
|  1 | In   | 2018-11-01 |
|  1 | Out  | 2018-12-01 |
|  2 | In   | 2018-10-01 |
|  2 | Out  | 2018-11-01 |
|  2 | In   | 2018-12-01 |
+----+------+------------+

我真的对这个问题感到困惑。 我从

SELECT #Table.*, MIN(CASE WHEN #Table.[type] = 'In' THEN #Table.Dates ELSE NULL END) As A
    ,MIN(CASE WHEN #Table.[type] = 'Out' THEN #Table.Dates ELSE NULL END) As B
FROM #Table
GROUP BY #Table.id, #Table.[type], #Table.Dates

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不知道接下来该怎么办…

如果我理解正确，聚合和

让

做这个把戏：

select t.id
from #Table t
group by t.id
having min(case when type = 'In' then dates end) < max(case when type = 'Out' then dates end);

---

这是Gordon使用窗口聚合应用于查询的逻辑：

---

这可能对您有用：

With CTE As
 (
   Select Id,[Type], [Dates], ROW_NUMBER() OVER(Partition By Id Order By Dates) As rn From #Tbl
 )
 Select * From cte
 Where cte.Id In (Select Distinct Id From CTE Where rn = 1 And [Type] = 'In')

---

您可以使用如下所示的内部联接尝试以下操作

CREATE TABLE #Table (
id INT,
[type] varchar(25),
[Dates] Date)

INSERT INTO #Table
VALUES (1, 'In', '2018-10-01'),
 (1, 'In', '2018-11-01'),
 (1, 'Out', '2018-12-01'),
 (2, 'In', '2018-10-01'),
 (2, 'Out', '2018-11-01'),
 (2, 'In', '2018-12-01'),
 (3, 'Out', '2018-10-01'),
 (3, 'In', '2018-11-01')

 SELECT DISTINCT #Table.* FROM(
SELECT  * FROM #Table
)a inner join (
SELECT * FROM #Table
)b on a.id = b.id and a.Dates < b.Dates and a.[type] = 'In' and b.[type] = 'Out'
inner join #Table on a.id = #Table.id

---

我还需要它所有对应的行，而不仅仅是Id@Gordon Linoffim，我只是不确定为什么我们在“Out”之前的type列中使用MAX而不是MINIt's your logic'In'：-）您想要在MIN（In date）处的行

select *
from #Table
where id in 
 ( Gordon's Select )

With CTE As
 (
   Select Id,[Type], [Dates], ROW_NUMBER() OVER(Partition By Id Order By Dates) As rn From #Tbl
 )
 Select * From cte
 Where cte.Id In (Select Distinct Id From CTE Where rn = 1 And [Type] = 'In')

CREATE TABLE #Table (
id INT,
[type] varchar(25),
[Dates] Date)

INSERT INTO #Table
VALUES (1, 'In', '2018-10-01'),
 (1, 'In', '2018-11-01'),
 (1, 'Out', '2018-12-01'),
 (2, 'In', '2018-10-01'),
 (2, 'Out', '2018-11-01'),
 (2, 'In', '2018-12-01'),
 (3, 'Out', '2018-10-01'),
 (3, 'In', '2018-11-01')

 SELECT DISTINCT #Table.* FROM(
SELECT  * FROM #Table
)a inner join (
SELECT * FROM #Table
)b on a.id = b.id and a.Dates < b.Dates and a.[type] = 'In' and b.[type] = 'Out'
inner join #Table on a.id = #Table.id

id  type    Dates
 --------------------
 1  In  2018-10-01
 1  In  2018-11-01
 1  Out 2018-12-01
 2  In  2018-10-01
 2  In  2018-12-01
 2  Out 2018-11-01