Sql Fluent NHibernate：如何将此查询作为条件编写？

数据结构如下： 房子有许多房间。每个房间都有很多人

我想做的是让所有人都买房子。在纯SQL中，我将编写以下内容：

SELECT * FROM Person WHERE Room_id
IN
(SELECT Id FROM Room WHERE House_id = 1)

我怎样才能用流利的NHibernate'ish代码来写呢

对于本例，我们可以假设实体和映射如下所示：

SELECT this_.Id as Id4_0_, this_.Name as Name4_0_, this_.RoomId as RoomId4_0_
FROM [Person] this_
WHERE this_.RoomId in (SELECT this_0_.Id as y0_ FROM [Room] this_0_ WHERE this_0_.HouseId = @p0)',N'@p0 int',@p0=1

众议院实体

public virtual int Id { get; set; }
public virtual string Name { get; set; }
public virtual IEnumerable<Room> Rooms { get; set; }

房间实体

public virtual int Id { get; set; }
public virtual string Name { get; set; }
public virtual House House { get; set; }
public virtual IEnumerable<Person> Persons { get; set; }

个人实体

public virtual int Id { get; set; }
public virtual string Name { get; set; }
public virtual Room Room { get; set; }

人员映射

Id(x => x.Id);
Map(x => x.Name);
References(x => x.Room);

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要使SQL查询接近您的查询，可以使用以下标准：

var subCriteria = DetachedCriteria.For<Room>(); // subquery
subCriteria.Add(Expression.Eq("House", house)); // where clause in subquery
subCriteria.SetProjection(Projections.Id()); // DetachedCriteria needs to have a projection, id of Room is projected here

var criteria = session.CreateCriteria<Person>();
criteria.Add(Subqueries.PropertyIn("Room", subCriteria)); // in operator to search in detached criteria
var result = criteria.List<Person>();

我在FNH1.2和NH3.1中对其进行了测试，但它在NH2.1中也应该运行良好

编辑： UpTheCreek是对的。Linq比标准API更清晰。例如：

var query = session.Query<Person>().Where(x => x.Room.House == house);
var linqResult = query.ToList<Person>();

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这不是一个流畅的问题-fluent仅用于指定映射和配置。根据您使用的NHibernate版本，您可以选择HQL、Criteria API或（如果是NH3）Linq。请显示您的实体和映射？@Jakub:Done@UptheCraek：哪种解决方案看起来最漂亮？你能给我举个例子吗？@Awesome-你用的是哪个版本的NHibernate？Linq是目前为止最清晰的方法。@Awesome-那么当你有一个需要编写的标准查询时，我个人会选择Linq，而不关心SQL的具体外观。Jakub下面的ICriteria答案很好，我很高兴它能帮上忙。但UpTheCreek是对的。Linq比我个人讨厌的API更清晰：）。另一方面，由于历史原因，我对NH Linq持谨慎态度——NH2.1中的Linq实现不是很有用。但你自己来判断（编辑后）。

SELECT this_.Id as Id4_0_, this_.Name as Name4_0_, this_.RoomId as RoomId4_0_
FROM [Person] this_
WHERE this_.RoomId in (SELECT this_0_.Id as y0_ FROM [Room] this_0_ WHERE this_0_.HouseId = @p0)',N'@p0 int',@p0=1

var query = session.Query<Person>().Where(x => x.Room.House == house);
var linqResult = query.ToList<Person>();

select person0_.Id as Id4_, person0_.Name as Name4_, person0_.Room_id as Room3_4_
from [Person] person0_, [Room] room1_
where person0_.Room_id=room1_.Id and room1_.House_id=2