Sql 具有重复电子邮件ID的不同行的计数

如何在SQL中获得具有重复电子邮件ID的不同行数

ID   NAME   EMAIL 
1    John   asd@asd.com 
2    Sam    asd@asd.com 
4    Bob    bob@asd.com 
5    Tom    asd@asd.com 
6    Rob    bob@asd.com
7    Tic    tic@asd.com
8    Dad    dad@asd.com

查询应返回2。 作为asd@asd.com及bob@asd.com都是重复的

SELECT 
 COUNT(*)  
FROM Users
GROUP BY EMail 
HAVING ( COUNT(EMAIL) > 1 )    

此查询正在返回一些wierd结果。 谢谢

行数：

select sum(cnt)
from (select count(*) as cnt
    from Users
    group by email
    having count(*) > 1) T

电子邮件计数：

select count(*)
from (select count(*) as cnt
    from Users
    group by email
    having count(*) > 1) T

两者同时：

select count(*) as COUNT_EMAIL sum(cnt) as COUNT_ROWS
from (select count(*) as cnt
    from Users
    group by email
    having count(*) > 1) T

以上内容应适用于SQL Server和Oracle