Sql 当行中的时间戳小于或等于某个值时，使用分析函数对一组记录进行分组
我在Oracle数据库中有一个表，其中有一个日期列，该列加载了每行的插入时间戳。我需要使用该表中的现有数据来分析某些事件之间的相关性，以便使用如下数据：Sql 当行中的时间戳小于或等于某个值时，使用分析函数对一组记录进行分组,sql,oracle,window-functions,Sql,Oracle,Window Functions,我在Oracle数据库中有一个表，其中有一个日期列，该列加载了每行的插入时间戳。我需要使用该表中的现有数据来分析某些事件之间的相关性，以便使用如下数据： COL_1 COL_2 TS A 1 Mon 15, February 2010 10:03:22 B 2 Mon 15, February 2010 10:05:37 C 3
COL_1 COL_2 TS
A 1 Mon 15, February 2010 10:03:22
B 2 Mon 15, February 2010 10:05:37
C 3 Mon 15, February 2010 10:20:21
D 4 Mon 15, February 2010 10:20:21
E 5 Mon 15, February 2010 10:20:24
F 6 Mon 15, February 2010 10:23:35
G 7 Mon 15, February 2010 10:45:22
FIRST_TS COUNT
Mon 15, February 2010 10:03:22 2
Mon 15, February 2010 10:20:21 4
Mon 15, February 2010 10:45:22 1
是否可以使用分析函数来实现这一点？如何进行？这将把距离上一行不到5分钟的行组合在一起：
--ALTER SESSION SET nls_date_format= 'dy dd, month yyyy hh24:mi:ss';
--ALTER SESSION SET nls_date_language='ENGLISH';
SQL> WITH DATA AS (
2 SELECT to_date('Mon 15, February 2010 10:03:22') ts FROM dual
3 UNION ALL SELECT to_date('Mon 15, February 2010 10:05:37') FROM dual
4 UNION ALL SELECT to_date('Mon 15, February 2010 10:20:21') FROM dual
5 UNION ALL SELECT to_date('Mon 15, February 2010 10:20:21') FROM dual
6 UNION ALL SELECT to_date('Mon 15, February 2010 10:20:24') FROM dual
7 UNION ALL SELECT to_date('Mon 15, February 2010 10:23:35') FROM dual
8 UNION ALL SELECT to_date('Mon 15, February 2010 10:45:22') FROM dual
9 )
10 SELECT MIN(ts) first_ts, COUNT(*) COUNT
11 FROM (SELECT ts, SUM(gap) over(ORDER BY ts) ts_group
12 FROM (SELECT ts,
13 CASE
14 WHEN ts - lag(ts) over(ORDER BY ts)
15 <= 5 / (60 * 24) THEN
16 0
17 ELSE
18 1
19 END gap
20 FROM DATA))
21 GROUP BY ts_group;
FIRST_TS COUNT
-------------------------------- ----------
mon 15, february 2010 10:03:22 2
mon 15, february 2010 10:20:21 4
mon 15, february 2010 10:45:22 1
这将把距离上一行不到5分钟的行组合在一起：
--ALTER SESSION SET nls_date_format= 'dy dd, month yyyy hh24:mi:ss';
--ALTER SESSION SET nls_date_language='ENGLISH';
SQL> WITH DATA AS (
2 SELECT to_date('Mon 15, February 2010 10:03:22') ts FROM dual
3 UNION ALL SELECT to_date('Mon 15, February 2010 10:05:37') FROM dual
4 UNION ALL SELECT to_date('Mon 15, February 2010 10:20:21') FROM dual
5 UNION ALL SELECT to_date('Mon 15, February 2010 10:20:21') FROM dual
6 UNION ALL SELECT to_date('Mon 15, February 2010 10:20:24') FROM dual
7 UNION ALL SELECT to_date('Mon 15, February 2010 10:23:35') FROM dual
8 UNION ALL SELECT to_date('Mon 15, February 2010 10:45:22') FROM dual
9 )
10 SELECT MIN(ts) first_ts, COUNT(*) COUNT
11 FROM (SELECT ts, SUM(gap) over(ORDER BY ts) ts_group
12 FROM (SELECT ts,
13 CASE
14 WHEN ts - lag(ts) over(ORDER BY ts)
15 <= 5 / (60 * 24) THEN
16 0
17 ELSE
18 1
19 END gap
20 FROM DATA))
21 GROUP BY ts_group;
FIRST_TS COUNT
-------------------------------- ----------
mon 15, february 2010 10:03:22 2
mon 15, february 2010 10:20:21 4
mon 15, february 2010 10:45:22 1
我不认为你需要分析，你只需要产生一些五分钟的间隔。下面的代码使用一个公共表表达式AKA sub-query factoring从给定的开始日期生成五分钟的间隔。主查询使用SUM和CASE生成属于间隔的记录计数 以下是测试数据：
SQL> select * from t23
2 /
C COL2 COL3
- ---------- -----------------
A 1 15-feb-2010 10:03
B 2 15-feb-2010 10:05
C 3 15-feb-2010 10:20
D 4 15-feb-2010 10:20
E 5 15-feb-2010 10:20
F 6 15-feb-2010 10:23
G 7 15-feb-2010 10:45
7 rows selected.
SQL>
SQL> with t_range as (
2 select to_date('15 February 2010 10:00','DD Month YYYY hh24:mi')
3 + ((level-1)/288) as this_5mins
4 , to_date('15 February 2010 10:00','DD Month YYYY hh24:mi')
5 + (level/288) as next_5mins
6 from dual
7 connect by level <= 12
8 )
9 select t_range.this_5mins
10 , sum(case when t23.col3 >= t_range.this_5mins
11 and t23.col3 < t_range.next_5mins
12 then 1
13 else 0 end ) as cnt
14 from t23 cross join t_range
15 group by t_range.this_5mins
16 /
THIS_5MINS CNT
----------------- ----------
15-feb-2010 10:10 0
15-feb-2010 10:20 4
15-feb-2010 10:30 0
15-feb-2010 10:05 1
15-feb-2010 10:55 0
15-feb-2010 10:15 0
15-feb-2010 10:40 0
15-feb-2010 10:45 1
15-feb-2010 10:00 1
15-feb-2010 10:35 0
15-feb-2010 10:25 0
15-feb-2010 10:50 0
12 rows selected.
SQL>
我不认为你需要分析，你只需要产生一些五分钟的间隔。下面的代码使用一个公共表表达式AKA sub-query factoring从给定的开始日期生成五分钟的间隔。主查询使用SUM和CASE生成属于间隔的记录计数 以下是测试数据：
SQL> select * from t23
2 /
C COL2 COL3
- ---------- -----------------
A 1 15-feb-2010 10:03
B 2 15-feb-2010 10:05
C 3 15-feb-2010 10:20
D 4 15-feb-2010 10:20
E 5 15-feb-2010 10:20
F 6 15-feb-2010 10:23
G 7 15-feb-2010 10:45
7 rows selected.
SQL>
SQL> with t_range as (
2 select to_date('15 February 2010 10:00','DD Month YYYY hh24:mi')
3 + ((level-1)/288) as this_5mins
4 , to_date('15 February 2010 10:00','DD Month YYYY hh24:mi')
5 + (level/288) as next_5mins
6 from dual
7 connect by level <= 12
8 )
9 select t_range.this_5mins
10 , sum(case when t23.col3 >= t_range.this_5mins
11 and t23.col3 < t_range.next_5mins
12 then 1
13 else 0 end ) as cnt
14 from t23 cross join t_range
15 group by t_range.this_5mins
16 /
THIS_5MINS CNT
----------------- ----------
15-feb-2010 10:10 0
15-feb-2010 10:20 4
15-feb-2010 10:30 0
15-feb-2010 10:05 1
15-feb-2010 10:55 0
15-feb-2010 10:15 0
15-feb-2010 10:40 0
15-feb-2010 10:45 1
15-feb-2010 10:00 1
15-feb-2010 10:35 0
15-feb-2010 10:25 0
15-feb-2010 10:50 0
12 rows selected.
SQL>
这是一个具有分析函数的版本。只需将您的表替换为union子查询，在该子查询中，我使用您的数据创建了一个表：
select distinct
first_value(ts) over (partition by continuous_group order by ts) first_ts
, count(ts) over (partition by continuous_group) count
from (
select col_1, col_2, ts, sum(discontinuity) over (order by ts) continuous_group
from (
select col_1, col_2, ts, case when lag(ts) over (order by ts) + numtodsinterval(5,'MINUTE') <= ts then 1 else 0 end discontinuity
from (
select 'A' col_1, 1 col_2, to_date('2010-2-15 10:03:22', 'YYYY-MM-DD HH24:MI:SS') ts from dual
union (
select 'B' col_1, 2 col_2, to_date('2010-2-15 10:05:37', 'YYYY-MM-DD HH24:MI:SS') ts from dual)
union (
select 'C' col_1, 3 col_2, to_date('2010-2-15 10:20:21', 'YYYY-MM-DD HH24:MI:SS') ts from dual)
union (
select 'D' col_1, 4 col_2, to_date('2010-2-15 10:20:21', 'YYYY-MM-DD HH24:MI:SS') ts from dual)
union (
select 'E' col_1, 5 col_2, to_date('2010-2-15 10:20:24', 'YYYY-MM-DD HH24:MI:SS') ts from dual)
union (
select 'F' col_1, 6 col_2, to_date('2010-2-15 10:23:35', 'YYYY-MM-DD HH24:MI:SS') ts from dual)
union (
select 'G' col_1, 7 col_2, to_date('2010-2-15 10:45:22', 'YYYY-MM-DD HH24:MI:SS') ts from dual)
))
) order by first_value(ts) over (partition by continuous_group order by ts);
这是一个具有分析函数的版本。只需将您的表替换为union子查询，在该子查询中，我使用您的数据创建了一个表：
select distinct
first_value(ts) over (partition by continuous_group order by ts) first_ts
, count(ts) over (partition by continuous_group) count
from (
select col_1, col_2, ts, sum(discontinuity) over (order by ts) continuous_group
from (
select col_1, col_2, ts, case when lag(ts) over (order by ts) + numtodsinterval(5,'MINUTE') <= ts then 1 else 0 end discontinuity
from (
select 'A' col_1, 1 col_2, to_date('2010-2-15 10:03:22', 'YYYY-MM-DD HH24:MI:SS') ts from dual
union (
select 'B' col_1, 2 col_2, to_date('2010-2-15 10:05:37', 'YYYY-MM-DD HH24:MI:SS') ts from dual)
union (
select 'C' col_1, 3 col_2, to_date('2010-2-15 10:20:21', 'YYYY-MM-DD HH24:MI:SS') ts from dual)
union (
select 'D' col_1, 4 col_2, to_date('2010-2-15 10:20:21', 'YYYY-MM-DD HH24:MI:SS') ts from dual)
union (
select 'E' col_1, 5 col_2, to_date('2010-2-15 10:20:24', 'YYYY-MM-DD HH24:MI:SS') ts from dual)
union (
select 'F' col_1, 6 col_2, to_date('2010-2-15 10:23:35', 'YYYY-MM-DD HH24:MI:SS') ts from dual)
union (
select 'G' col_1, 7 col_2, to_date('2010-2-15 10:45:22', 'YYYY-MM-DD HH24:MI:SS') ts from dual)
))
) order by first_value(ts) over (partition by continuous_group order by ts);
什么版本的Oracle？必须是9i或更高版本才能使用分析。Oracle的哪个版本？必须是9i或更高版本才能使用分析。出色！非常感谢你！优秀的非常感谢你！