MySQL计数（*）结果中的最后一项？

快速提问。。。我有一个检查重复项的查询，如下所示：

 SELECT COUNT( * ) AS repetitions, Name, Phone, ID, categoryid, State
 FROM users 
 GROUP BY Name, Phone, State
 HAVING repetitions > 1 
 ORDER BY ID DESC

这是可行的，但MySQL会返回一组副本中的第一个ID。例如，假设我有两行。第一行的ID为1，第二行的ID为2，并且姓名、电话和状态具有相同的数据。。。如何让上面的查询返回ID为2而不是1的计数

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谢谢

使用最大聚合函数：

SELECT COUNT(*) AS repetitions, max(ID) FROM users GROUP BY Name, Phone, State HAVING repetitions > 1 ORDER BY ID DESC

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使用最大聚合函数：

SELECT COUNT(*) AS repetitions, max(ID) FROM users GROUP BY Name, Phone, State HAVING repetitions > 1 ORDER BY ID DESC

不完美但有效

SELECT COUNT( * ) AS repetitions, Name, Phone, MAX(ID), categoryid, State 
FROM users 
GROUP BY Name, Phone, State 
HAVING repetitions > 1

不完美但有效

SELECT COUNT( * ) AS repetitions, Name, Phone, MAX(ID), categoryid, State 
FROM users 
GROUP BY Name, Phone, State 
HAVING repetitions > 1

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几分钟前得到了同样的答案。。。非常好，谢谢！几分钟前得到了同样的答案。。。非常好，谢谢！