使用SQL查找可从给定范围整除的最小正数

例如：2520是最小的正数，它被1到10之间的每个数字所除

请帮助我使用SQL查找1到20之间的最小正数，它是13693680

假设结果小于15 000 000 000

with
number as (
SELECT TOP (6000) 
    CONVERT(BIGINT, ROW_NUMBER() OVER (ORDER BY s1.object_id)) * 2520 as n
FROM
    sys.all_objects AS s1 
    CROSS JOIN sys.all_objects AS s2
)
select
   min(n),
   max(n),
   min(
   case
   when n%20 + n%19 + n%18 + n%16 + n%15 + n%14 + n%13 + n%12 + n%11 = 0 then n
   end)
from
   number

暴力：

with
number as (
SELECT TOP (15000000) 
    CONVERT(BIGINT, ROW_NUMBER() OVER (ORDER BY s1.object_id)) as n
FROM
    sys.all_objects AS s1 
    CROSS JOIN sys.all_objects AS s2
    CROSS JOIN sys.all_objects AS s3
)
select
   min(n),
   max(n),
   min(
   case
   when n%20 + n%19 + n%18 + n%16 + n%15 + n%14 + n%13 + n%12 + n%11 + n%10 + n%9 + n%8 + n%7 + n%6 + n%5 + n%4 + n%3 + n%2 + n%1 = 0 then n
   end)
from
   number
;

==>很长

假设解决方案是10的倍数：

with
number as (
SELECT TOP (1500000) 
    CONVERT(BIGINT, ROW_NUMBER() OVER (ORDER BY s1.object_id)) * 10 as n
FROM
    sys.all_objects AS s1 
    CROSS JOIN sys.all_objects AS s2
    CROSS JOIN sys.all_objects AS s3
)
select
   min(n),
   max(n),
   min(
   case
   when n%20 + n%19 + n%18 + n%16 + n%15 + n%14 + n%13 + n%12 + n%11 + n%10 + n%9 + n%8 + n%7 + n%6 + n%5 + n%4 + n%3 + n%2 + n%1 = 0 then n
   end)
from
   number
;

只需快10倍

假设结果是2520的倍数（最小正值除以1到10的每个数字）和6000*2520>15000）

---

非常快（比第一个方案快约x2520）。

请添加一些代码，显示您已经尝试过的内容！尝试使用c逻辑。但它的错误方式已经被告知。