将SQL查询（与子查询联接）转换为KnexJS

我试图将SQL查询转换为KnexJS格式，但当前的KnexJS查询给我以下错误

堆栈处或附近的语法错误：错误：堆栈处或附近的语法错误 这是原始查询，也是我为KnexJS开发的查询。 请更正我的KnexJS查询。 基本上，我想知道如何构建KnexJS查询-内部连接子查询 提前谢谢你

原始SQL查询：

select DATE_RANGE.START_DATE, DATE_RANGE.END_DATE, count (distinct DATE) as DATE_COUNT
from TASK_HISTORY
join
(select 
STORE_ID, 
to_number(to_char(to_date(to_char(DATE,'99999999'),'YYYYMMDD') - 1,'YYYYMMDD'),'99999999') as END_DATE
, count (distinct DATE) as REC_COUNT
, to_number(to_char(to_date(to_char(lag (DATE) over (order by DATE asc),'99999999'),'YYYYMMDD') + 1,'YYYYMMDD'),'99999999') as START_DATE
, count (case when FINISH_TIME is not null then 1 end) as COUNT_FINISHED
, count (case when FINISH_TIME is null then 1 end) as COUNT_UNFINISHED
  from TASK_HISTORY
  where STORE_ID = 43
  group by DATE, STORE_ID
  having count (case when FINISH_TIME is not null then 1 end) = 0
  order by DATE)
  as DATE_RANGE
on TASK_HISTORY.DATE >= DATE_RANGE.START_DATE 
    AND TASK_HISTORY.DATE <= DATE_RANGE.END_DATE
    AND TASK_HISTORY.STORE_ID = 43
group by DATE_RANGE.START_DATE, DATE_RANGE.END_DATE, DATE_RANGE.REC_COUNT
order by DATE_COUNT desc, START_DATE desc

更新：

以下是对我有效的解决方案：

    await db
      .table("task_history")
      .select('date_range.start_date', 'date_range.end_date')
      .select(db.raw(`count(distinct date) as date_count`))
      .join(
        db
        .select('task_history.store_id')
        .table('task_history')
        .select(db.raw(
          `to_number(to_char(to_date(to_char(date,'99999999'),'YYYYMMDD') - 1,'YYYYMMDD'),'99999999') as end_date`
        ))
        .select(db.raw(`count(distinct date) as rec_count`))
        .select(db.raw(
          `to_number(to_char(to_date(to_char(lag (date) over (order by date asc),'99999999'),'YYYYMMDD') + 1,'YYYYMMDD'),'99999999') as start_date`
        ))
        .select(db.raw(`count(case when FINISH_TIME is not null then 1 end) as COUNT_FINISHED`))
        .select(db.raw(`count(case when FINISH_TIME is null then 1 end) as COUNT_UNFINISHED`))
        .where('task_history.store_id', 43)
        .groupBy('task_history.date', 'task_history.store_id')
        .having(db.raw(`count(case when FINISH_TIME is not null then 1 end) = 0 order by date`))
        .as('date_range'),
        function () {
          this.on('task_history.date', '>=', 'date_range.start_date')
            .andOn('task_history.date', '<=', 'date_range.end_date')
            .andOn('task_history.store_id', 43)
        }
      )
      .groupBy('date_range.start_date', 'date_range.end_date', 'date_range.rec_count')
      .orderBy('date_count', 'desc')
      .orderBy('start_date', 'desc')

这可能会帮助你-

const sql = db.table("task_history")
   .select('DATE_RANGE.START_DATE', 'DATE_RANGE.END_DATE')
   .select(db.raw(`count(distinct DATE) as DATE_COUNT`))
   .innerJoin(
      db.select('store_id')
         .table('task_history')
         .select(db.raw(
            `to_number(to_char(to_date(to_char(DATE,'99999999'),'YYYYMMDD') - 1,'YYYYMMDD'),'99999999') as END_DATE`
         ))
         .select(db.raw(`count(distinct DATE) as REC_COUNT`))
         .select(db.raw(
            `to_number(to_char(to_date(to_char(lag (DATE) over (order by DATE asc),'99999999'),'YYYYMMDD') + 1,'YYYYMMDD'),'99999999') as START_DATE`
         ))
         .select(db.raw(`count(case when FINISH_TIME is not null then 1 end) as COUNT_FINISHED`))
         .select(db.raw(`count(case when FINISH_TIME is null then 1 end) as COUNT_UNFINISHED`))
         .where('store_id', 43)
         .groupBy('date', 'store_id')
         .having(db.raw(`count(case when FINISH_TIME is not null then 1 end) = 0 order by DATE`))
         .as('DATE_RANGE')
      , function () {
         this.on('DATE_RANGE.START_DATE', '>=', 'TASK_HISTORY.DATE')
            .andOn('TASK_HISTORY.DATE', '<=', 'DATE_RANGE.END_DATE')
            .andOn('TASK_HISTORY.STORE_ID', 43)
      })
   .where('task_history.date', '>=', 'DATE_RANGE.START_DATE')
   .where('task_history.date', '<=', 'DATE_RANGE.END_DATE')
   .groupBy('DATE_RANGE.START_DATE', 'DATE_RANGE.END_DATE', 'DATE_RANGE.REC_COUNT')
   .orderBy('DATE_COUNT', 'desc')
   .orderBy('START_DATE', 'desc')
   .toSQL();
console.log(sql);

---

首先尝试对查询中无法正确生成的部分进行最小的示例。您可以使用.toSQL打印出knex生产的产品。在当前的表单调试中，这可能需要30分钟，因为查询中有大量不相关的部分，并与原始查询进行交叉检查，确保原始查询具有有效的语法……感谢您的提示，@MikaelLepistö。你能告诉我我可以构建join子查询的语法吗？谢谢@Fazal Rasel。你的例子确实帮助我解决了我的问题。