Sql 如何合并两个不同的行(如何分配不同的值为零)
我正在尝试使用union合并两个输出,但这些行的值不同。我需要不同的行的值为零。如OutputHird表。我正在努力通过两天请帮助我Sql 如何合并两个不同的行(如何分配不同的值为零),sql,postgresql,join,group-by,union,Sql,Postgresql,Join,Group By,Union,我正在尝试使用union合并两个输出,但这些行的值不同。我需要不同的行的值为零。如OutputHird表。我正在努力通过两天请帮助我 Select t1.round, t1.SC, t1.ST, t1.OTHERS, t2.round_up, t2.SC_up, t2.ST_up, t2.OTHERS_up From (Select round as round, Sum (non_slsc_qty) as SC, Sum (non_slst_qt
Select t1.round,
t1.SC,
t1.ST,
t1.OTHERS,
t2.round_up,
t2.SC_up,
t2.ST_up,
t2.OTHERS_up
From
(Select round as round,
Sum (non_slsc_qty) as SC,
Sum (non_slst_qty) as ST,
Sum (non_slot_qty) as OTHERS
FROM vhn_issue
where (date between '2015-08-01' and '2015-08-31')AND
dvn_cd='15' AND phc_cd='012' AND hsc_cd='05' GROUP BY round) t1
,
(Select round as round_up,
Sum (non_slsc_qty) as SC_up,
Sum (non_slst_qty) as ST_up,
Sum (non_slot_qty) as OTHERS_up,
FROM vhn_issue
where (date between '2015-04-01' and '2015-08-31')AND
dvn_cd='15' AND phc_cd='012' AND hsc_cd='05' GROUP BY round) t2
这是第一个表格的结果
+-----------------------------------+------------+--------+--------
| round | SC | ST | OTHERS |
+-----------------------------------+------------+--------+--------
| 1 | 20 | 30 | 50 |
| | | | |
| | | | |
+-----------------------------------+------------+--------+--------+
这是第二个表格结果
+-----------------------------------+------------+--------+----------
| round_up | SC_up | ST_up | OTHERS_up |
+-----------------------------------+------------+--------+-----------
| 1 | 21 | 31 | 51 |
| 3 | 10 | 5 | 2 |
| | | | |
+-----------------------------------+------------+--------+--------+---
我需要这样的输出
+------------+--------+----------------------------------------------
| round_up | SC | ST |OTHERS | SC_up | ST_up |OTHERS_up |
+------------+--------+-----------------------------------------------
| 1 | 20 | 30 | 50 | 21 | 31 | 51 |
| | | | | | | |
| 3 | 0 | 0 | 0 | 10 | 5 | 2 |
+------------+--------+--------+---------------------------------------
您可以使用来包装这两个选择,并使用RIGHT JOIN来获得所需的输出,用于打印0而不是NULL
选择b.round_up,coalesca.sc,0,coalesca.st,0,coalesca.others,0,b.sc_up,b.st_up,b.others_up从t1 a右键连接t2 b到a.round=b.round_up试试这个…,COALESCE t2.sc,0,coalesct2.st,0。。。从…起t1左连接t2开…老板..它不是静态的…我可以使用。。。coalesca.sc,0作为SC1ok boss,但我可以像这样更改名称coalesca.sc,0作为SC1吗
WITH a
AS (
SELECT round AS round
,Sum(non_slsc_qty) AS SC
,Sum(non_slst_qty) AS ST
,Sum(non_slot_qty) AS OTHERS
FROM vhn_issue
WHERE (
DATE BETWEEN '2015-08-01'
AND '2015-08-31'
)
AND dvn_cd = '15'
AND phc_cd = '012'
AND hsc_cd = '05'
GROUP BY round
)
,b
AS (
SELECT round AS round_up
,Sum(non_slsc_qty) AS SC_up
,Sum(non_slst_qty) AS ST_up
,Sum(non_slot_qty) AS OTHERS_up
,
FROM vhn_issue
WHERE (
DATE BETWEEN '2015-04-01'
AND '2015-08-31'
)
AND dvn_cd = '15'
AND phc_cd = '012'
AND hsc_cd = '05'
GROUP BY round
)
SELECT coalesce(b.round_up, 0) round_up
,coalesce(a.sc, 0) sc
,coalesce(a.st, 0) st
,coalesce(a.others, 0) others
,coalesce(b.sc_up, 0) sc_up
,coalesce(b.st_up, 0) st_up
,coalesce(b.others_up, 0) others_up
FROM a
RIGHT JOIN b ON a.round = b.round_up
WITH Results_CTE AS
(
Select t1.round as round_up ,
t1.SC as SC,
t1.ST as ST,
t1.OTHERS as OTHERS,
0 as SC_up,
0 as ST_up,
0 as OTHERS_up
from round t1
union all
t2.round_up as round_up ,
0 as SC,
0 as ST,
0 as OTHERS,
t2.SC_up,
t2.ST_up,
t2.OTHERS_up from round t2
)
select round_up , sum(SC) as SC,sum (ST) as ST, sum(OTHERS) as OTHERS, sum(SC_up) as SC_up, sum(ST_up) as ST_up, sum(OTHERS_up) as OTHERS_ up
from Results_CTE group by round_up