Sql 基于多个子项配对的父项计数

在下面的例子中，我试图根据每个酒吧的食材供应情况来计算我可以制作的饮料数量

进一步澄清，如以下示例所示：基于下图中突出显示的数字；我知道，如果我将供应品运送到该地点，我只能在2018年6月30日在DC或FL生产一瓶玛格丽塔

数据表样本

请使用以下代码输入上述相关数据：

    CREATE TABLE #drinks 
    (
        a_date      DATE,
        loc         NVARCHAR(2),
        parent      NVARCHAR(20),
        line_num    INT,
        child       NVARCHAR(20),
        avail_amt   INT
    );

INSERT INTO #drinks VALUES ('6/26/2018','CA','Long Island','1','Vodka','7');
INSERT INTO #drinks VALUES ('6/27/2018','CA','Long Island','2','Gin','5');
INSERT INTO #drinks VALUES ('6/28/2018','CA','Long Island','3','Rum','26');
INSERT INTO #drinks VALUES ('6/26/2018','DC','Long Island','1','Vodka','15');
INSERT INTO #drinks VALUES ('6/27/2018','DC','Long Island','2','Gin','18');
INSERT INTO #drinks VALUES ('6/28/2018','DC','Long Island','3','Rum','5');
INSERT INTO #drinks VALUES ('6/26/2018','FL','Long Island','1','Vodka','34');
INSERT INTO #drinks VALUES ('6/27/2018','FL','Long Island','2','Gin','14');
INSERT INTO #drinks VALUES ('6/28/2018','FL','Long Island','3','Rum','4');
INSERT INTO #drinks VALUES ('6/30/2018','DC','Margarita','1','Tequila','6');
INSERT INTO #drinks VALUES ('7/1/2018','DC','Margarita','2','Triple Sec','3');
INSERT INTO #drinks VALUES ('6/29/2018','FL','Margarita','1','Tequila','1');
INSERT INTO #drinks VALUES ('6/30/2018','FL','Margarita','2','Triple Sec','0');
INSERT INTO #drinks VALUES ('7/2/2018','CA','Cuba Libre','1','Rum','1');
INSERT INTO #drinks VALUES ('7/8/2018','CA','Cuba Libre','2','Coke','5');
INSERT INTO #drinks VALUES ('7/13/2018','CA','Cuba Libre','3','Lime','14');
INSERT INTO #drinks VALUES ('7/5/2018','DC','Cuba Libre','1','Rum','0');
INSERT INTO #drinks VALUES ('7/19/2018','DC','Cuba Libre','2','Coke','12');
INSERT INTO #drinks VALUES ('7/31/2018','DC','Cuba Libre','3','Lime','9');
INSERT INTO #drinks VALUES ('7/2/2018','FL','Cuba Libre','1','Rum','1');
INSERT INTO #drinks VALUES ('7/19/2018','FL','Cuba Libre','2','Coke','3');
INSERT INTO #drinks VALUES ('7/17/2018','FL','Cuba Libre','3','Lime','2');
INSERT INTO #drinks VALUES ('6/30/2018','DC','Long Island','3','Rum','4');
INSERT INTO #drinks VALUES ('7/7/2018','FL','Cosmopolitan','5','Triple Sec','7');

预期结果如下：

请注意，正如预期结果所示，儿童是可互换的。例如，2018年7月7日，《世界杯》的三倍秒到达；然而，因为孩子也是朗姆酒，它改变了佛罗里达州玛格丽塔酒的供应

也不是6月30日和6月31日对古巴自由贸易区的更新

请考虑到零件是可互换的，并且每次新项目到达时，都会使以前的任何项目可用

---

最后，如果我可以添加另一个专栏，显示工具包的可用性，而不考虑位置，这将是非常棒的，仅基于孩子的可用性。例如，如果DC中有一个孩子3，而FL中没有孩子3，那么FL可以假设他们有足够的库存，可以根据其他位置的库存制作饮料

我认为这将给出所需的结果

创建了一个用于获取库存的函数

Create function GetInventoryByDateAndLocation
(@date DATE, @Loc NVARCHAR(2))
RETURNS TABLE
AS
RETURN
(
Select child,avail_amt from 
    (Select a_date, child,avail_amt, 
     ROW_NUMBER() over (partition by child order by a_date desc) as ranking 
     from drinks where loc = @Loc and a_date<=@date)c 
where ranking = 1
)

这将使所有的饮料，可以从库存。希望它能解决你的问题

---

这只是我的2美分。有更好的方法可以做到这一点，我希望更多的人会读到这篇文章并提出更好的建议。

不要认为这正是你想要的。。。也许会有帮助

SELECT DISTINCT #drinks.loc,#drinks.parent,avail.Avail
FROM #drinks
LEFT OUTER JOIN (
SELECT DISTINCT #drinks.parent, MIN(availnow.maxavailnow / line_num) 
OVER(PARTITION BY parent) as Avail
FROM #drinks
LEFT OUTER JOIN (
            SELECT #drinks.child,SUM(avail_amt) maxavailnow
            FROM #drinks
            LEFT OUTER JOIN (SELECT MAX(a_date) date,loc,child FROM #drinks GROUP BY loc,child) maxx ON #drinks.loc = maxx.loc AND #drinks.child = maxx.child AND maxx.date = #drinks.a_date
            GROUP BY #drinks.child
            ) availnow ON #drinks.child = availnow.child
            ) avail ON avail.parent = #drinks.parent

---

我已经创建了两个额外的表来帮助编写查询，但是如果需要，可以从饮料表生成这些表：

CREATE TABLE #recipes 
(
    parent      NVARCHAR(20),
    child       NVARCHAR(20)
);

INSERT INTO #recipes VALUES ('Long Island', 'Vodka');
INSERT INTO #recipes VALUES ('Long Island', 'Gin');
INSERT INTO #recipes VALUES ('Long Island', 'Rum');
INSERT INTO #recipes VALUES ('Maragrita', 'Tequila');
INSERT INTO #recipes VALUES ('Maragrita', 'Triple Sec');
INSERT INTO #recipes VALUES ('Cuba Libre', 'Coke');
INSERT INTO #recipes VALUES ('Cuba Libre', 'Rum');
INSERT INTO #recipes VALUES ('Cuba Libre', 'Lime');
INSERT INTO #recipes VALUES ('Cosmopolitan', 'Cranberry Juice');
INSERT INTO #recipes VALUES ('Cosmopolitan', 'Triple Sec');

CREATE TABLE #locations 
(
    loc      NVARCHAR(20)
);

INSERT INTO #locations VALUES ('CA');
INSERT INTO #locations VALUES ('FL');
INSERT INTO #locations VALUES ('DC');

然后，查询变成：

DECLARE @StartDateTime DATETIME
DECLARE @EndDateTime DATETIME

SET @StartDateTime = '2018-06-26'
SET @EndDateTime = '2018-07-31';

--First, build a range of dates that the report has to run for
WITH DateRange(a_date) AS 
(
    SELECT @StartDateTime AS DATE
    UNION ALL
    SELECT DATEADD(d, 1, a_date)
    FROM   DateRange 
    WHERE  a_date < @EndDateTime
)
SELECT a_date, parent, loc, avail_amt
FROM   (--available_recipes_inventory
        SELECT a_date, parent, loc, avail_amt,
               LAG(avail_amt, 1, 0) OVER (PARTITION BY loc, parent ORDER BY a_date) AS previous_avail_amt
        FROM   (--recipes_inventory
                SELECT a_date, parent, loc, 
                       --The least amount of the ingredients for a recipe is the most 
                       --amount of drinks we can make for it
                       MIN(avail_amt) as avail_amt
                FROM   (--ingredients_inventory
                        SELECT dr.a_date, r.parent, r.child, l.loc, 
                               --Default ingredients we don't have with a zero amount
                               ISNULL(d.avail_amt, 0) as avail_amt
                        FROM   DateRange dr CROSS JOIN
                               #recipes r CROSS JOIN
                               #locations l OUTER APPLY
                               (
                                --Find the total amount available for each 
                                --ingredient at each location for each date
                                SELECT SUM(d1.avail_amt) as avail_amt
                                FROM   #drinks d1
                                WHERE  d1.a_date <= dr.a_date
                                AND    d1.loc = l.loc
                                AND    d1.child = r.child
                               ) d
                        ) AS ingredients_inventory
                GROUP BY a_date, parent, loc
               ) AS recipes_inventory
        --Remove all recipes that we don't have enough ingredients for
        WHERE  avail_amt > 0 
       ) AS available_recipes_inventory
--Selects the first time a recipe has enough ingredients to be made
WHERE  previous_avail_amt = 0 
--Selects when the amount of ingredients has changed
OR     previous_avail_amt != avail_amt 
ORDER BY a_date
--MAXRECURSION needed to generate the date range
OPTION (MAXRECURSION 0)
GO

选择MAXd2.a\u日期 从作为d2的饮料 其中d2.parent=d.parent d2.loc=d.loc作为一个_日期 ，d.loc ，d.父母 ，SUMd.avail\u amt AS[avail\u amtSUM] ，COUNTd.avail\u amt为[avail\u amt count] 从饮料中提取d d.loc分组 ，d.父母

---

按a_日期下单

顺便说一句，出色的职位招聘数据、预期输出和所需逻辑的详细信息。我希望每个人在发帖时都能如此小心。做得好！！对我来说，对期望结果的逻辑解释不够。为什么在6月30日你能在华盛顿建造9个长岛？为什么你只能在6月28日在华盛顿建造4个长岛？看起来仍然有问题。。如果你在6月28日那天只有5杯杜松子酒，你怎么能在加州的7个长岛上生产呢？@SMHorus你错过了一份确定的配料表。从这些数据中我们无从得知世界主义者需要什么。正如我在上面的聊天中提到的，你应该制作三张单独的表格：按日期列出的地点清单、地点菜单和饮料配方。关于这个问题，最令人困惑的是，你如何制作一个没有可乐、龙舌兰和三倍秒的长岛？谢谢你的努力和反馈。我在我的系统中的实际表中尝试了这一点。不幸的是，它只返回一条记录。我不认为您在库存函数中考虑了行数。除此之外，您创建的函数可以创建超过2200万条记录，我知道这似乎是错误的。我只是认为行_num用于识别孩子。我将添加对代码的解释，然后您可以尝试进行一些修改

DECLARE @StartDateTime DATETIME
DECLARE @EndDateTime DATETIME

SET @StartDateTime = '2018-06-26'
SET @EndDateTime = '2018-07-31';

--First, build a range of dates that the report has to run for
WITH DateRange(a_date) AS 
(
    SELECT @StartDateTime AS DATE
    UNION ALL
    SELECT DATEADD(d, 1, a_date)
    FROM   DateRange 
    WHERE  a_date < @EndDateTime
)
SELECT a_date, parent, loc, avail_amt
FROM   (--available_recipes_inventory
        SELECT a_date, parent, loc, avail_amt,
               LAG(avail_amt, 1, 0) OVER (PARTITION BY loc, parent ORDER BY a_date) AS previous_avail_amt
        FROM   (--recipes_inventory
                SELECT a_date, parent, loc, 
                       --The least amount of the ingredients for a recipe is the most 
                       --amount of drinks we can make for it
                       MIN(avail_amt) as avail_amt
                FROM   (--ingredients_inventory
                        SELECT dr.a_date, r.parent, r.child, l.loc, 
                               --Default ingredients we don't have with a zero amount
                               ISNULL(d.avail_amt, 0) as avail_amt
                        FROM   DateRange dr CROSS JOIN
                               #recipes r CROSS JOIN
                               #locations l OUTER APPLY
                               (
                                --Find the total amount available for each 
                                --ingredient at each location for each date
                                SELECT SUM(d1.avail_amt) as avail_amt
                                FROM   #drinks d1
                                WHERE  d1.a_date <= dr.a_date
                                AND    d1.loc = l.loc
                                AND    d1.child = r.child
                               ) d
                        ) AS ingredients_inventory
                GROUP BY a_date, parent, loc
               ) AS recipes_inventory
        --Remove all recipes that we don't have enough ingredients for
        WHERE  avail_amt > 0 
       ) AS available_recipes_inventory
--Selects the first time a recipe has enough ingredients to be made
WHERE  previous_avail_amt = 0 
--Selects when the amount of ingredients has changed
OR     previous_avail_amt != avail_amt 
ORDER BY a_date
--MAXRECURSION needed to generate the date range
OPTION (MAXRECURSION 0)
GO

+------------+-------------+-----+-----------+
| a_date     | parent      | loc | avail_amt |
+------------+-------------+-----+-----------+
| 2018-06-28 | Long Island | DC  | 5         |
| 2018-06-28 | Long Island | CA  | 5         |
| 2018-06-28 | Long Island | FL  | 4         |
| 2018-06-30 | Long Island | DC  | 9         |
| 2018-07-01 | Maragrita   | DC  | 3         |
| 2018-07-02 | Long Island | FL  | 5         |
| 2018-07-07 | Maragrita   | FL  | 1         |
| 2018-07-13 | Cuba Libre  | CA  | 5         |
| 2018-07-19 | Cuba Libre  | FL  | 2         |
| 2018-07-31 | Cuba Libre  | DC  | 9         |
+------------+-------------+-----+-----------+