Sql 如何获取列中最常用的值

我在SQL server中有这样一个表

UsageTime        Website

10:45:08       yahoo.co.uk

10:24:06       msn.co.uk

09:45:08       lycos.co.uk

我需要像这样的东西

BusiestHour   NoOfWebsitesVisited
10:00         2     

我试过这个

SELECT TOP 3  UsageTime as BusiestHour, COUNT(Website) FROM  NoOfWebsitesVisited
GROUP BY BusiestHour    

但这并不完全正确。它不检查整个小时，只检查一个特定的值

任何帮助都将不胜感激：谢谢

SELECT TOP 3   
       DATEPART(HOUR,UsageTime) as BusiestHour, 
       COUNT(Website) FROM  NoOfWebsitesVisited
GROUP BY DATEPART(HOUR,UsageTime)
ORDER BY NoOfWebsitesVisited DESC;

也许你想要这样的东西：

SELECT TOP 3 WITH TIES
       DATEPART(HOUR,UsageTime) as BusiestHour, 
       COUNT(Website) FROM  NoOfWebsitesVisited
GROUP BY DATEPART(HOUR,UsageTime)
ORDER BY NoOfWebsitesVisited DESC;

也许你想要这样的东西：

SELECT TOP 3 WITH TIES
       DATEPART(HOUR,UsageTime) as BusiestHour, 
       COUNT(Website) FROM  NoOfWebsitesVisited
GROUP BY DATEPART(HOUR,UsageTime)
ORDER BY NoOfWebsitesVisited DESC;

使用dateparth，UsageTime获取日期的小时部分-然后可以构建更有用的表达式使用dateparth，UsageTime获取日期的小时部分-然后可以构建更有用的表达式