SPARK SQL按选择结果从组中选择
我有一张桌子,叫做新桌子。 在第一步中,我想按id、kmstand、vacationname和vacationvalue对结果进行分组,其中每个分组依据只存在一个计数。对于此步骤,我已经创建了一个查询:SPARK SQL按选择结果从组中选择,sql,select,nested,apache-spark-sql,Sql,Select,Nested,Apache Spark Sql,我有一张桌子,叫做新桌子。 在第一步中,我想按id、kmstand、vacationname和vacationvalue对结果进行分组,其中每个分组依据只存在一个计数。对于此步骤,我已经创建了一个查询: SELECT id, kmstand, vacationame, vacationvalue FROM `db_1`.`table_new` WHERE (vacationame='vacation1' OR vacationame='vacation2' OR va
SELECT id, kmstand, vacationame, vacationvalue
FROM `db_1`.`table_new`
WHERE (vacationame='vacation1'
OR vacationame='vacation2'
OR vacationame='vacation3'
OR vacationame='vacation4')
GROUP BY id, kmstand, vacationame, vacationvalue
HAVING COUNT(*) = 1 ORDER BY id, kmstand DESC
结果是:
id kmstand vacationame vacationvalue
1 1 4000 vacation1 munich
2 1 4000 vacation1 stuttgart
3 1 5500 vacation4 koln
4 1 5500 vacation2 frankfurt
5 1 5500 vacation3 berlin
6 1 5500 vacation1 potsdam
7 2 6000 vacation2 new york
8 2 6000 vacation1 bangladesh
9 2 3000 vacation1 washington
10 2 3000 vacation3 chicago
现在,我想选择一个id,其中kmstand和vacationname的组合现在是不同的。这意味着结果应该是:
id kmstand vacationame vacationvalue
1 1 5500 vacation4 koln
2 1 5500 vacation2 frankfurt
3 1 5500 vacation3 berlin
4 1 5500 vacation1 potsdam
5 2 6000 vacation2 new york
6 2 6000 vacation1 bangladesh
7 2 3000 vacation1 washington
8 2 3000 vacation3 chicago
为此,我创建了以下嵌套sql查询:
SELECT id, kmstand, count(*) as cnt
FROM `db_1`.`table_new`
WHERE (SELECT id, kmstand, vacationame, vacationvalue
FROM `db_1`.`table_new`
WHERE (vacationame='vacation1'
OR vacationame='vacation2'
OR vacationame='vacation3'
OR vacationame='vacation4')
GROUP BY id, kmstand, vacationame, vacationvalue
HAVING COUNT(*) = 1 ORDER BY id, kmstand DESC)
GROUP BY id, kmstand
HAVING cnt = 1
ORDER BY id, kmstand DESC
我也试过了,没有where子句或from,也没有找到解决方案。对于此SQL查询,我收到以下错误消息:org.apache.spark.SQL.AnalysisException:无法识别表达式规范中“SELECT”“id”“附近的输入;第3行第7位置
我很确定,语法不对。您有什么建议吗?不熟悉SPARK,但您可能想要:
SELECT id, kmstand, count(*) as cnt
FROM (SELECT id, kmstand, vacationame, vacationvalue
FROM `db_1`.`table_new`
WHERE (vacationame='vacation1'
OR vacationame='vacation2'
OR vacationame='vacation3'
OR vacationame='vacation4')
GROUP BY id, kmstand, vacationame, vacationvalue
HAVING COUNT(*) = 1) T
GROUP BY id, kmstand
HAVING cnt = 1
ORDER BY id, kmstand DESC
注意,我在FROM子句中为表添加了一个别名(T
)。这可能是必需的,也可能不是必需的,这取决于您的RDBMS
还请注意,您通常不能在子查询中按顺序排序。这是问题的答案。现在我可以在组合id、kmstand和VacationName不同的地方获得id
SELECT id, sumcnt, cnt2
FROM(
SELECT id, count(*) as cnt2, sum(cnt) as sumcnt
FROM (
SELECT id, kmstand, vacationame, count(*) as cnt
FROM `db_1`.`table_new`
WHERE (vacationame='vacation1'
OR vacationame='vacation2'
OR vacationame='vacation3'
OR vacationame='vacation4')
GROUP BY id, kmstand, vacationame)T
GROUP BY id)T
WHERE (sumcnt/cnt2 = 1)
您的查询存在的问题是,如果每个id的VacationName出现不止一次,则无法筛选出结果。结果应该是,只有具有非重复VacationName的id可用。我认为我们可以使用类似这样的内容:其中id的所有cnt都是1