SQL：如何获取一列语句行中所有字符串的总和

是否有一个sql查询能够将所有句子分割成字符串，对它们进行计数并返回前3个最常见的字符串

例如：-

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在MySQL中，您可以使用以下内容解析单词：

|   string   | sum |
|-------------|-----|
|    cool     |  5  |
|    love     |  3  |
|    lamb     |  2  |

请注意，此版本仅获取前三个单词。您需要展开

n

，以获得列中的最大字数

然后，您可以聚合为：

select substring_index(substring_index(col, ' ', n.n), ' ', -1) as word
from (select 1 as n union all select 2 as n union all select 3 as n
     ) n join
     t
     on col like concat(repeat('% ', n.n - 1), '%');

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PostgreSQL具有全文搜索功能。MySQL没有现成的插件，但可能有某种插件…@Pavitran。没有一个简单的机制。

select substring_index(substring_index(col, ' ', n.n), ' ', -1) as word
from (select 1 as n union all select 2 as n union all select 3 as n
     ) n join
     t
     on col like concat(repeat('% ', n.n - 1), '%');

select substring_index(substring_index(t.col, ' ', n.n), ' ', -1) as word,
       count(*)
from (select 1 as n union all select 2 as n union all select 3 as n
     ) n join
     t
     on col like concat(repeat('% ', n.n - 1), '%')
group by word