Sql Oracle连接之间的连接，间隔时间为分钟

我在按分钟连接具有不同日期间隔的表时遇到一些问题

例子： 表1

ID  Modules    Timestamp
1   Delivered  02-FEB-2020 08:24:45
1   Read       02-FEB-2020 08:27:50
1   Delivered  03-FEB-2020 09:24:45
1   Read       03-FEB-2020 10:00:50
2   Delivered  03-FEB-2020 09:28:10
2   Read       03-FEB-2020 09:30:11

问题: 有没有办法让数据变成这样

 ID  Modules1    Timestamp1            Modules2   Timestamp2
 1   Delivered   02-FEB-2020 08:24:45  Read       02-FEB-2020 08:27:50
 1   Delivered   03-FEB-2020 09:24:45
 1   Read        03-FEB-2020 10:00:50
 2   Delivered   03-FEB-2020 09:28:10  Read       03-FEB-2020 09:30:11

目标：

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因此，如果有人在5分钟内阅读，那么它将加入，如果没有，数据将保持不变。

您可以进行自加入，以达到以下所需结果：

With cte as 
(Select t.*, 
       Row_number() over (partition by id, modules order by timestamp) as rn
  From your_table t)
Select t1.*, 
       case when t1.modules = 'delivered' and t1.timestamp + interval '5' minute <= t2.timestamp 
            then t2.timestamp 
       end as timestamp2
       From cte t1 
       left join cte t2
       On (t1.rn = t2.rn and t2.modules = 'read')
       Left join cte3 
       On (t1.rn = t3.rn and t3.modules = 'delivered')
Where t1.modules = 'delivered' or t3.timestamp + interval '5' minute > t2.timestamp

---

干杯

我认为这是一种缺口和孤岛问题。每个孤岛的读取或任何一行的交付延迟5分钟

with tgrp as (
      select t.*,
             sum(case when modules = 'Delivered' or
                           prev_timestamp < timestamp - interval '5' minute
                        then 1 else 0
                   end) over (partition by id order by timestamp) as grp
      from (select t.*,
                   lag(timestamp) over (partition by id order by timestamp) as prev_timestamp
            from t
           ) t
      )
select id,
       max(case when seqnum = 1 then module end) as module1,
       max(case when seqnum = 1 then timestamp end) as timestamp1,
       max(case when seqnum = 2 then module end) as module2,
       max(case when seqnum = 2 then timestamp end) as timestamp2
from (select tgrp.*,
             row_number() over (partition by id, grp order by timestamp) as seqnum
      from tgrp
     ) tgrp
group by id, grp;

---

将其发布到SQLFiddle.com之类的网站上，并附上一个模式和一些示例数据。然后，在你的问题中加入一个链接。这样，你更有可能得到回复。另外，模块的ID在您的连接中也很重要吗？如果没有这一点，问题就变得模棱两可了。我会尝试以下几种方法：1使用子查询将它们拆分为仅传递和仅读取，然后在id和read.time之间完全外部连接delivered.time和delivered.time+5min，如果传递的值为null，则使用读取值。2使用按ID划分的滞后/超前分析功能查看当前行；case当当前行被传递时，则“y”作为keep，case当读取下一行时，并在5分钟内将这些读取的列值固定到该行上。当当前行和前一行被读取超过5分钟，然后“y”作为keep-else“n”，则将所有内容包装在WHERE-keep='y'中

select t.id, t.module, t.timestamp,
       (case when t.next_module = 'Read' and
                  t.next_timestamp < t.timestamp + interval '5' minute
             then t.next_module
        end) as module2,
       (case when t.next_module = 'Read' and
                  t.next_timestamp < t.timestamp + interval '5' minute
             then t.next_timestamp
        end) as timestamp2
from (select t.*,
             lead(module) over (partition by id order by timestamp) as next_module,
             lead(timestamp) over (partition by id order by timestamp) as next_timestamp
      from t
     ) t
where module = 'Delivery' or
      (next_timestamp > timestamp + interval '5' minute)