Sql t是这样的：获取行：1-1002000-21004000-41008000-810016000-16100、32000-32100等等。@Raj针对您的范围进行了更新-它们不会呈指数增长，因为第一个和第二个范围都是2000行，所以您需要为第一组做一个特例。

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t是这样的：获取行：1-1002000-21004000-41008000-810016000-16100、32000-32100等等。@Raj针对您的范围进行了更新-它们不会呈指数增长，因为第一个和第二个范围都是2000行，所以您需要为第一组做一个特例。谢谢。你的回答多少解决了我的问题。我正试图修改查询以符合我的确切要求，如下所示：获取行：1-1002000-21004000-41008000-810016000-16100、32000-32100等等。@Raj针对您的范围进行了更新-它们不会呈指数增长，因为第一个和第二个范围都是2000行，所以您需要为第一组设置一个特例。

SELECT * FROM (SELECT t.*,ROWNUM AS rn FROM(SELECT * FROM   your_table ORDER BY your_condition) t)WHERE MOD( rn - 1, 2000 ) < 100;

select t.*
from (select t.*,
             row_number() over (floor(log(2, floor(1 + (seqnum - 1) / 1000) ))
                                order by col
                               ) as seqnum_2
      from (select t.*, row_number() over (order by col) as seqnum
            from t
           ) t
where seqnum_2 <= 100;

with rng as (select 0 num from dual union all
             select 1000 * power(2, level) from dual connect by level < 10 )
select * 
  from (select row_number() over (order by object_name) rn, object_name from all_objects)
  join rng on rn between num + 1 and num + 100 

SELECT *
FROM   (
  SELECT t.*,
         ROWNUM AS rn            -- Secondly, assign a row number to the ordered rows
  FROM   (
    SELECT *
    FROM   your_table
    ORDER BY your_condition      -- First, order the data
  ) t
)
WHERE rn - POWER(                -- Finally, filter the top 100.
             2,
             TRUNC( CAST( LOG( 2, CEIL( rn / 1000 ) ) AS NUMBER(20,4) ) )
           ) * 1000 + 1000 <= 100

WHERE CASE                -- Finally, filter the top 100.
        WHEN rn <= 2000 THEN rn
        ELSE rn - POWER(
                    2,
                    TRUNC( CAST( LOG( 2, CEIL( rn / 1000 - 1 ) ) AS NUMBER(20,4) ) )
                  ) * 1000
      END <= 100