MS SQL临时表循环
需要有关sql循环查询的帮助吗 我的桌子:MS SQL临时表循环,sql,sql-server,tsql,hierarchical-data,recursive-query,Sql,Sql Server,Tsql,Hierarchical Data,Recursive Query,需要有关sql循环查询的帮助吗 我的桌子: ╔════════╦════════╦════════╦════════╦════════╗ ║ EMP_ID ║ EMP_L1 ║ EMP_L2 ║ EMP_L3 ║ EMP_L4 ║ ╠════════╬════════╬════════╬════════╬════════╣ ║ ALI ║ ABU ║ ║ ║ ║ ║ JAMES ║ KAREN ║ ║ ║
╔════════╦════════╦════════╦════════╦════════╗
║ EMP_ID ║ EMP_L1 ║ EMP_L2 ║ EMP_L3 ║ EMP_L4 ║
╠════════╬════════╬════════╬════════╬════════╣
║ ALI ║ ABU ║ ║ ║ ║
║ JAMES ║ KAREN ║ ║ ║ ║
║ JERRY ║ GEM ║ ║ ║ ║
║ JOSH ║ LIM ║ JERRY ║ GEM ║ ║
║ LIM ║ JERRY ║ GEM ║ ║ ║
╚════════╩════════╩════════╩════════╩════════╝
我的预期输出:
╔════════╦════════╦════════╦════════╦════════╗
║ EMP_ID ║ EMP_L1 ║ EMP_L2 ║ EMP_L3 ║ EMP_L4 ║
╠════════╬════════╬════════╬════════╬════════╣
║ ALI ║ ABU ║ ║ ║ ║
║ JAMES ║ KAREN ║ ║ ║ ║
║ JERRY ║ GEM ║ ║ ║ ║
║ JOSH ║ LIM ║ JERRY ║ GEM ║ ║
║ LIM ║ JERRY ║ GEM ║ ║ ║
╚════════╩════════╩════════╩════════╩════════╝
我只能得到一条线
declare @ID nvarchar(50) = (select EMP_ID from HRS_WORKFLOW01);
CREATE TABLE #TEMP(EMP_ID NVARCHAR(200),EMP_L1 NVARCHAR(200),EMP_L2 NVARCHAR(200),EMP_L3 NVARCHAR(200),EMP_L4 NVARCHAR(200))
DECLARE @L1 NVARCHAR(50);
DECLARE @L2 NVARCHAR(50);
DECLARE @L3 NVARCHAR(50);
DECLARE @L4 NVARCHAR(50);
SET @L1 = (SELECT L1EmplNo FROM HRS_WORKFLOW01 WHERE EMP_ID =@ID)
INSERT INTO #TEMP (EMP_ID,EMP_L1)VALUES(@ID,@L1)
SET @L2 = (SELECT L1EmplNo FROM HRS_WORKFLOW01 WHERE EMP_ID =@L1)
UPDATE #TEMP SET EMP_L2=@L2 WHERE EMP_ID=@ID
SET @L3 = (SELECT L1EmplNo FROM HRS_WORKFLOW01 WHERE EMP_ID =@L2)
UPDATE #TEMP SET EMP_L3=@L3 WHERE EMP_ID=@ID
SET @L4 = (SELECT L1EmplNo FROM HRS_WORKFLOW01 WHERE EMP_ID =@L3)
UPDATE #TEMP SET EMP_L4=@L4 WHERE EMP_ID=@ID
SELECT * FROM #TEMP
您需要使用
递归CTE
;WITH DATA
AS (SELECT *
FROM (VALUES ('ALI','ABU'),
('JOSH','LIM'),
('JAMES','KAREN'),
('LIM','JERRY'),
('JERRY','GEM')) TC(EMP_ID, EMP_L1)),
REC_CTE
AS (SELECT EMP_ID,
EMP_L1,
Cast(EMP_L1 AS VARCHAR(8000)) AS PARENT,
LEVEL = 1
FROM DATA
UNION ALL
SELECT D.EMP_ID,
D.EMP_L1,
Cast(RC.PARENT + '.' + D.EMP_L1 AS VARCHAR(8000)),
LEVEL = LEVEL + 1
FROM DATA D
JOIN REC_CTE RC
ON RC.EMP_ID = D.EMP_L1)
SELECT TOP 1 WITH TIES EMP_ID,
EMP_L1 = COALESCE(Parsename(PARENT, 1), ''),
EMP_L2 = COALESCE(Parsename(PARENT, 2), ''),
EMP_L3 = COALESCE(Parsename(PARENT, 3), ''),
EMP_L4 = COALESCE(Parsename(PARENT, 4), '')
FROM REC_CTE
ORDER BY Row_number()OVER(PARTITION BY EMP_ID ORDER BY LEVEL DESC)
OPTION (MAXRECURSION 0)
结果:
╔════════╦════════╦════════╦════════╦════════╗
║ EMP_ID ║ EMP_L1 ║ EMP_L2 ║ EMP_L3 ║ EMP_L4 ║
╠════════╬════════╬════════╬════════╬════════╣
║ ALI ║ ABU ║ ║ ║ ║
║ JAMES ║ KAREN ║ ║ ║ ║
║ JERRY ║ GEM ║ ║ ║ ║
║ JOSH ║ LIM ║ JERRY ║ GEM ║ ║
║ LIM ║ JERRY ║ GEM ║ ║ ║
╚════════╩════════╩════════╩════════╩════════╝
注意:这考虑到最多可以有4个级别。为了将数据拆分为不同的列,我使用了PARSENAME
函数,如果超过4个级别,该函数将不起作用
如果不想将父级拆分为不同的列,请删除
PARSENAME
,然后单独选择PARENT
列。您读过CTE(公共表表达式)吗教程?请以文本格式发布示例数据,而不是images@KyLim-您可以拥有任意数量的emp_id
如果总是emp_L1
到emp_L4
Msg 530,级别16,状态1,过程工作流,第23行语句终止,则不成问题。在语句完成之前,已用尽最大递归100,我收到这个错误xDUSE选项(MAXRECURSION 0);在陈述的结尾。