如何在SQL存储过程中使用XPATH获得以下输出
假设xml输入为如何在SQL存储过程中使用XPATH获得以下输出,sql,xpath,Sql,Xpath,假设xml输入为 <Tasks> <Task Name="Add2"> <Dependency Name="S1"/> </Task> <Task Name="Min2"> <Dependency Name="Dev1"/> <Dependency Name="Extra"/> </Task> <Tasks> 如何在Sql存储过程中使用Xpath实现这一点从技术上
<Tasks>
<Task Name="Add2">
<Dependency Name="S1"/>
</Task>
<Task Name="Min2">
<Dependency Name="Dev1"/>
<Dependency Name="Extra"/>
</Task>
<Tasks>
如何在Sql存储过程中使用Xpath实现这一点从技术上讲,您需要使用Xpath进行两次路径选择,因为您正在访问不同的节点。我将为您介绍sql server方法:
declare @xml_content xml = '<Tasks>
<Task Name="Add2">
<Dependency Name="S1"/>
</Task>
<Task Name="Min2">
<Dependency Name="Dev1"/>
<Dependency Name="Extra"/>
</Task>
<Tasks>'
with roots as (
select x.value('@Name','varchar(max)') task_name,x.query('.') deps
from @xml_content.nodes('Tasks/Task') a(x)
)
select r.task_name,x.value('@Name','varchar(max)') dependency_name
from roots r
cross apply roots.deps.nodes('/Task/Dependency') a(x)
您以前的一些问题是关于SQL Server的,所以
declare @xml xml = '
<Tasks>
<Task Name="Add2">
<Dependency Name="S1"/>
</Task>
<Task Name="Min2">
<Dependency Name="Dev1"/>
<Dependency Name="Extra"/>
</Task>
</Tasks>'
select T1.N.value('@Name', 'varchar(max)') as TaskName,
T2.N.value('@Name', 'varchar(max)') as DependencyName
from @xml.nodes('/Tasks/Task') as T1(N)
cross apply T1.N.nodes('Dependency') as T2(N)
您使用的是什么数据库管理系统?
declare @xml xml = '
<Tasks>
<Task Name="Add2">
<Dependency Name="S1"/>
</Task>
<Task Name="Min2">
<Dependency Name="Dev1"/>
<Dependency Name="Extra"/>
</Task>
</Tasks>'
select T1.N.value('@Name', 'varchar(max)') as TaskName,
T2.N.value('@Name', 'varchar(max)') as DependencyName
from @xml.nodes('/Tasks/Task') as T1(N)
cross apply T1.N.nodes('Dependency') as T2(N)