SQL Server:对部分空数据使用聚合
我有一个问题,一些代码,我想得到一些帮助。以下是从PowerApps进入SQL数据库的表:SQL Server:对部分空数据使用聚合,sql,sql-server,tsql,group-by,powerapps,Sql,Sql Server,Tsql,Group By,Powerapps,我有一个问题,一些代码,我想得到一些帮助。以下是从PowerApps进入SQL数据库的表: +-----------------------+-----------------+-------------+-----------+------------+------+-----------+ | ID | ProductionOrder | Workstation | Status | Date | Pass | TotalTime |
+-----------------------+-----------------+-------------+-----------+------------+------+-----------+
| ID | ProductionOrder | Workstation | Status | Date | Pass | TotalTime |
+-----------------------+-----------------+-------------+-----------+------------+------+-----------+
| 60127429_1000_1_S035 | 108100 | S035 | Completed | 05/13/2020 | No | 121 |
| 60128523_1000_1_S120 | 884171 | S120 | Completed | 05/13/2020 | Yes | 18 |
| 60128523_13000_1_S080 | 884172 | S080 | Completed | 05/13/2020 | No | 26 |
| 60128523_13000_1_S090 | 884172 | S090 | Completed | 05/13/2020 | No | 19 |
| 60128523_13000_1_S120 | 884172 | S120 | Completed | 05/13/2020 | No | 16 |
| 60128523_28000_1_S070 | 884173 | S070 | Completed | 05/13/2020 | No | 10 |
| 60128523_28000_1_S080 | 884173 | S080 | Completed | 05/13/2020 | No | 16 |
| 60128523_28000_1_S090 | 884173 | S090 | Completed | 05/13/2020 | No | 21 |
| 60128523_28000_1_S120 | 884173 | S120 | Completed | 05/13/2020 | No | 17 |
| 60128523_47000_1_S080 | 884174 | S080 | Completed | 05/13/2020 | Yes | 10 |
| 60128523_47000_1_S090 | 884174 | S090 | Completed | 05/13/2020 | Yes | 50 |
| 60128523_47000_1_S120 | 884174 | S120 | Completed | 05/13/2020 | Yes | 19 |
| 60128569_6000_1_S080 | 884698 | S080 | Completed | 05/13/2020 | Yes | 9 |
| 60128569_6000_1_S090 | 884698 | S090 | Completed | 05/13/2020 | Yes | 47 |
| 60128569_6000_1_S120 | 884698 | S120 | Completed | 05/13/2020 | Yes | 54 |
| 60129071_1000_1_S070 | 105597 | S070 | Completed | 05/13/2020 | No | 137 |
| 60129071_1000_1_S080 | 105597 | S080 | Completed | 05/13/2020 | No | 12 |
| 60129071_1000_1_S090 | 105597 | S090 | Completed | 05/13/2020 | No | 21 |
| 60129071_23000_1_S070 | 105598 | S070 | Completed | 05/13/2020 | Yes | 50 |
| 60129071_23000_1_S080 | 105598 | S080 | Completed | 05/13/2020 | Yes | 12 |
| 60129071_23000_1_S090 | 105598 | S090 | Completed | 05/13/2020 | Yes | 29 |
| 60129071_23000_1_S120 | 105598 | S120 | Completed | 05/13/2020 | Yes | 20 |
| 60129071_23025_1_S020 | 105600 | S020 | Completed | 05/13/2020 | Yes | 21 |
| 60129151_2000_1_S090 | 104974 | S090 | Completed | 05/13/2020 | No | 26 |
| 60129151_2000_1_S120 | 104974 | S120 | Completed | 05/13/2020 | No | 24 |
+-----------------------+-----------------+-------------+-----------+------------+------+-----------+
接下来,我将创建一个视图,通过对每个工作站进行分组来获取一些指标。这是代码:
with cteNow AS
(
SELECT CASE WHEN 60 * DATEPART(HOUR, GETUTCDATE()) + DATEPART(MINUTE, GETUTCDATE()) > 60 * 21
THEN CONVERT(float,(16 - 7) * 60) --minutes in (4 PM - 7 AM) * 60 minutes/hour
ELSE
CONVERT(float,60 * DATEPART(HOUR, GETUTCDATE()) + DATEPART(MINUTE, GETUTCDATE()) - ((7 + 5) * 60))
END as MinutesToday
, CONVERT(varchar(50), DATEADD(HOUR, -5, GETUTCDATE()), 101) as TargetDate
)
SELECT dbs.Workstation,
100.0 - ISNULL(SUM(CASE WHEN dbs.Pass = 'Yes' AND Status = 'Completed' THEN 1 ELSE 0 END) / NULLIF(SUM(CASE WHEN dbs.Status = 'Completed' THEN 1 ELSE 0 END), 0), 0) AS RFT
FROM [Booms DBS] AS dbs LEFT JOIN [Booms Delay Entry] AS del ON dbs.ID = del.ID INNER JOIN cteNow AS N ON N.TargetDate = dbs.[Date]
GROUP BY dbs.Workstation, MinutesToday
这一点是为了测量每个站的“第一次正确”。每次在Pass
列中有一个“Yes”值时,它就是对RFT的点击。例如,如果给定站点中总共有十个构建,其中五个在Pass
列中有“Yes”,则表示50%的RFT
但是,RFT
列的结果总是为“100”。我添加了所有这些NULLIF
和ISNULL
警告,因为有时Pass
列可能为空,并且在某些天中,可能根本没有任何数据,尤其是在早上。我想这就是问题所在。我计算得不对吗?如果不包含这些空检查函数,我想不出任何其他方法来避免出错或被零除
提前谢谢
这一点是为了测量每个站的“第一次正确”。每次在Pass列中有一个“Yes”值时,它就是对RFT的点击。例如,如果给定站点中总共有十个构建,其中五个在Pass列中有“Yes”,则为50%RFT
似乎您需要条件聚合。我不了解您现有查询中日期算法的用途,但这将实现您所描述的:
select
workstation,
avg(case when statys = 'Completed' and pass = 'Yes' then 1.0 else 0 end) rft_rate
from dbs.workstation
group by workstation
这将为每个工作站提供一条记录,数值介于0和1之间,表示在列中有值的记录的速率是
这一点是为了测量每个站的“第一次正确”。每次在Pass列中有一个“Yes”值时,它就是对RFT的点击。例如,如果给定站点中总共有十个构建,其中五个在Pass列中有“Yes”,则为50%RFT
似乎您需要条件聚合。我不了解您现有查询中日期算法的用途,但这将实现您所描述的:
select
workstation,
avg(case when statys = 'Completed' and pass = 'Yes' then 1.0 else 0 end) rft_rate
from dbs.workstation
group by workstation
这将为每个工作站提供一条记录,数值介于0和1之间,表示在列中有值的记录的速率是