在SQL Server中，当开始时间和结束时间超过12点时，如何获取正确的时间格式

我尝试过员工的打卡打卡时间，我尝试过下面的查询，当打卡时间为上午10:00，打卡打卡时间为下午6:00时效果良好，显示的总持续时间为8小时

但当打卡时间如9:00pm和5:00am时，它就失败了

关于这个问题，我根据打卡和打卡进行了计算，显示了总小时数

但当用户在凌晨12点后打卡时，打卡和打卡上都显示为00:00，总持续时间显示为0

我得到的输出

    I:9:05AM\nO:5:32PM\nT:8:27 \nS :~Present On WeeklyOff - WeekOff,:Saturday,:    
    I:12:00AM\nO:12:00AM\nT:0:0  \nS :~Present On WeeklyOff - WeekOff,:Saturday,:

我的问题是：

SELECT 
    ROW_NUMBER() OVER (ORDER BY e.EmployeeCode,AttendanceDate DESC) AS 'SNo',  
    e.EmployeeCode AS 'EmpID',  
    e.EmployeeName AS 'EmpName',  
    d.DepartmentFName AS 'DeptName', 
    CONVERT(VARCHAR, a.AttendanceDate, 110) AS 'AttendanceDate',
    'I:' + LTRIM (RIGHT(CONVERT(VARCHAR(50),+'I:'+CONVERT(VARCHAR(50),+CONVERT(DATETIME, a.InTime,0)),100),7))+'\n'+'O:'+LTRIM (RIGHT(CONVERT(VARCHAR(20),CONVERT(DATETIME, CASE WHEN a.OutTime LIKE '%(%' THEN LEFT(a.OutTime, CHARINDEX('(', a.OutTime + ')') - 1)  
   ELSE a.OutTime END,0),100),7))+'\n'+ 'T:'+ CONVERT(CHAR(5),CAST(CAST(CASE WHEN  a.InTime> a.OutTime THEN DATEDIFF (MINUTE,CAST(a.InTime as datetime),DateAdd(day,1,CAST(a.OutTime AS datetime)))
 ELSE DATEDIFF(MINUTE, a.InTime , a.OutTime) END AS INTEGER)/60 AS VARCHAR)+':'+CAST(cast(CASE WHEN  a.InTime> a.OutTime THEN DATEDIFF (MINUTE,CAST(a.InTime as datetime),DateAdd(day,1,CAST(a.OutTime AS datetime)))
 ELSE DATEDIFF(MINUTE, a.InTime , a.OutTime) END AS INTEGER)%60 AS VARCHAR),108)+ '\n' + 'S :~' +  a.[Status]+ ' - ' + CASE WHEN a.[Status] = 'Present' THEN '' WHEN a.[Status] = 'On WeeklyOff' and la.LeaveType<>'' THEN la.LeaveType   
   WHEN DATENAME(dw, a.AttendanceDate)='Sunday' THEN 'WeekOff' WHEN DATENAME(dw, a.AttendanceDate)='SaturDay'   
   THEN 'WeekOff' ELSE la.LeaveType COLLATE SQL_Latin1_General_CP1_CI_AS   ENd + ',:'+DATENAME(dw, a.AttendanceDate) + ',:'+ CASE WHEN la.LeaveStatus is null THEN '' ELSE la.LeaveStatus END AS 'PunchDetails',
   '0LOP' AS 'NoOfLOP',
   '0WkEnd' AS 'NoOfWkEndWorked' ,ISNULL(la.LeaveStatus,'') AS 'LeaveStatus' 

-- INTO #Result02  
FROM   
    esslsmartofficenew.dbo.Employees e (NOLOCK) 
INNER JOIN
    esslsmartofficenew.dbo.AttendanceLogs a (NOLOCK) ON e.EmployeeId = a.EmployeeId 
INNER JOIN   
    esslsmartofficenew.dbo.Departments d (NOLOCK) ON d.DepartmentId = e.DepartmentId 
INNER JOIN  
    esslsmartofficenew.dbo.Shifts s (NOLOCK) ON s.ShiftId = a.ShiftId 
LEFT JOIN  
    IntranetReleaseNew.dbo.LeaveApplication la ON la.EmpId collate SQL_Latin1_General_CP1_CI_AS = e.employeecode collate SQL_Latin1_General_CP1_CI_AS 
                                               AND a.AttendanceDate >= la.leavefromdate 
                                               AND a.AttendanceDate <= la.leaveTodate  
WHERE   
    e.DepartmentId = '10' AND  
    e.EmployeeName NOT LIKE '%del_%' AND
    e.EmployeeCode LIKE '%S%' AND 
    e.EmployeeCode NOT LIKE '%Del_%' AND
    a.AttendanceDate = '2017-05-13'

选择
（按e.EmployeeCode、AttendanceDate DESC排序）上方的行号（）为“SNo”，
e、 员工代码为“EmpID”，
e、 员工名称为“EmpName”，
d、 部门名称“DeptName”，
将（VARCHAR，a.AttendanceDate，110）转换为“AttendanceDate”，
“I:”+LTRIM（RIGHT）（CONVERT（VARCHAR（50），+'I:”+CONVERT（VARCHAR（50），+CONVERT（DATETIME，a.InTime，0）），100），7））+'\n'+'O:'+LTRIM（RIGHT）（CONVERT（VARCHAR（20），CONVERT（DATETIME，CASE，当a.OutTime类似“%”时，然后LEFT（a.OutTime，a.OutTime+'））-1）
ELSE a.OutTime END，0），100），7）+'\n'+'T:'+转换（字符（5），转换（CAST（当a.InTime>a.OutTime然后DATEDIFF（分钟，转换（a.InTime作为datetime），DateAdd（天，1，转换（a.OutTime作为datetime）））
ELSE DATEDIFF（MINUTE，a.InTime，a.OutTime）END AS INTEGER）/60 AS VARCHAR）+'：'+CAST（CAST（当a.InTime>a.OutTime然后是DATEDIFF（MINUTE，CAST（a.InTime作为datetime），DateAdd（day，1，CAST（a.OutTime作为datetime））时的情况）
ELSE DATEDIFF（MINUTE，a.InTime，a.OutTime）以整数结尾）%60作为VARCHAR），108）+'\n'+'S:~'+a.[Status]+'-'+当a.[Status]='Present'时为''.[Status]='On WeeklyOff'时为'.[Status]='On WeeklyOff'，la.LeaveType''，然后为la.LeaveType时为'
当DATENAME（dw，a.AttendanceDate）=“星期日”时，则当DATENAME（dw，a.AttendanceDate）=“星期六”时，则为“周末”
然后“WeekOff”ELSE la.LeaveType将SQL\u Latin1\u General\u CP1\u CI\u整理为ENd+”，：“+DATENAME（dw，a.AttendanceDate）+”，：“+如果la.LeaveStatus为null，则“ELSE la.LeaveStatus”结束为“PunchDetails”，
“0LOP”作为“NoOfLOP”，
“0WkEnd”作为“NoOfWkEndWorked”，ISNULL（la.LeaveStatus，”）作为“LeaveStatus”
--进入#结果02
从…起
esslsmartofficenew.dbo.e（NOLOCK）
内连接
e.EmployeeId=a.EmployeeId上的esslsmartofficenew.dbo.AttendanceLogs a（NOLOCK）
内连接
esslsmartofficenew.dbo.Departments d（NOLOCK）ON d.DepartmentId=e.DepartmentId
内连接
esslsmartofficenew.dbo.ShiftId上的s（NOLOCK）移位=a.ShiftId
左连接
IntranetReleaseNew.dbo.LeaveApplication la ON la.EmpId collate SQL\u Latin1\u General\u CP1\u CI\u AS=e.employeecode collate SQL\u Latin1\u General\u CP1\u CI\u AS
和a.AttendanceDate>=la.leavefromdate
a.AttendanceDate我不想尝试解开你的代码，所以我只想处理相关的计算

如果我们可以假设，当停机时间小于开始时间时，则停机时间发生在第二天，我们可以使用如下方式：

注意：为了减少重复将时间转换为datetime的代码，在上述假设下，您可以使用子查询/派生表来达到相同的效果

create table t (employeeid int, attendancedate date, intime time(0), outtime time(0));
insert into t values (1,'20170601','21:00:00','05:00:00'),(2,'20170603','05:00:00','21:00:00');

;with cte as (
select *
  , indatetime =dateadd(minute,datediff(minute,0,intime),convert(datetime2(0),attendancedate))
  , outdatetime=case when outtime > intime
      then dateadd(minute,datediff(minute,0,outtime),convert(datetime2(0),attendancedate))
      else dateadd(minute,datediff(minute,0,outtime),convert(datetime2(0),dateadd(day,1,attendancedate)))
      end
from t
)
select 
    employeeid
  , attendancedate
  , intime = ltrim(right(convert(varchar(23),convert(datetime,intime ),100),7))
  , outtime= ltrim(right(convert(varchar(23),convert(datetime,outtime),100),7))
  /* if less than 24 hours we can use this simpler version: */
  , TotalDuration24 = convert(time(0),dateadd(minute,datediff(minute,indatetime,outdatetime),0))
  /* if values greater than 24 hours we would use this version: */
  , TotalDuration = convert(varchar(10),
      convert(varchar(4),(datediff(minute,indatetime,outdatetime)/60),2)+':'
     +right('00'+convert(varchar(2),datediff(minute,indatetime,outdatetime)%60),2)
    )
from cte

rextester演示：

返回：

+------------+----------------+--------+---------+-----------------+---------------+
| employeeid | attendancedate | intime | outtime | TotalDuration24 | TotalDuration |
+------------+----------------+--------+---------+-----------------+---------------+
|          1 | 2017-06-01     | 9:00PM | 5:00AM  | 08:00:00        | 8:00          |
|          2 | 2017-06-03     | 5:00AM | 9:00PM  | 16:00:00        | 16:00         |
+------------+----------------+--------+---------+-----------------+---------------+

嗨，即使在周末，它在所有的日子里都可以正常工作，但在一个场景中它失败了。当一个人的时间是下午6点和凌晨4点（例如），它失败了。我的意思是，如果它在周六超过11点59分，它的时间是12点和12点