如何在sql中查找同一列的行之间的差异

问题->写一个查询，显示取款超过存款金额的所有账号、存款、取款

试试这个您也可以通过自连接来完成：

;WITH D AS
(
SELECT ACNUMBER, SUM(TRANSACTION) AS Deposit
FROM TABLE_NAME 
WHERE TRANSACTION_TYPE = 'Deposit'
GROUP BY ACNUMBER
)
, W as
(
SELECT ACNUMBER, SUM(TRANSACTION) AS Withdrawal
FROM TABLE_NAME 
WHERE TRANSACTION_TYPE = 'Withdrawal'
GROUP BY ACNUMBER

)
SELECT D.ACNUMBER, d.Deposit, w.Withdrawal

FROM D 
INNER JOIN W
ON D.ACNUMBER = W.ACNUMBER
WHERE d.Deposit < w.Withdrawal

---

您不应按交易类型分组。试试这个

select acnumber,sum(transaction_amount * case when transaction_type = 'deposit' then 1 else -1 end) as amount 
from trandetails 
group by acnumber
order by acnumber asc 

您可能只对金额为负数的行感兴趣，因为这些是取款>存款的帐户。在这种情况下，请添加一个过滤器：

select acnumber,sum(transaction_amount * case when transaction_type = 'deposit' then 1 else -1 end) as amount 
from trandetails 
group by acnumber
having sum(transaction_amount * case when transaction_type = 'deposit' then 1 else -1 end) < 0
order by acnumber asc 

---

到目前为止您尝试了什么？？？选择acnumber、transaction_type、sumtransaction_amount作为trandetails组中的金额（按acnumber）、transaction_type订单（按acnumber）asc无法获取特定交易的不同赌注取款和存款acnumber@user5501922把这个问题作为你问题的一部分！这不会返回只有一种交易类型的任何帐户。Msg 8120，级别16，状态1，第3行列“trandetails.acnumber”在选择列表中无效，因为它不包含在聚合函数或GROUP BY子句中。在ruunin您的查询@Mangal PardeshiSorry时出现此错误。您需要在两个CTE中按ACNUMBER分组